Helpmates - SuperProblem 2018 Informal Tourney - Коопматы
AWARD | ИТОГИ
E570 Dedicated to all participants
white Pb4 Ke5 Rg6
black Pg3g4c4f5d5b5 Ka4 Ra3a7 Sc5 Bb6
h#3 3.1.. (3+11)
E571
white Pg4b6 Kc4 Re8 Bd8
black Qe3 Pg6c6g7d7b7 Kf4 Rh1b5
h#2 2.1.. b), c) Bd8, Re8->e7 (5+9)
E572
white Sd4 Ka4 Rc6 Bd7
black Qh5 Pb2b7d2d5d6f7 Kd3 Sa1
h#2.5 3 solutions (4+9)
E570 8/r7/1b4R1/1pnpKp2/kPp3p1/r5p1/8/8 Dedicated to all participants of the tourney
1.Ra3-b3 Rg6-h6 2.Rb3*b4 Rh6-h2 3.Sc5-b3 Rh2-a2 # {,} 1.Sc5-a6 Rg6*g4 2.Sa6*b4 Rg4*g3 3.Ka4-a5 Rg3*a3 # {,} 1.Bb6-a5 b4*c5 2.Ba5-b4 Rg6-g7 3.Ka4-a5 Rg7*a7 #
Self-blocks of the same square b4 by different black pieces. On diagram - "the outline" of a dog, the symbol of 2018 according to Oriental horoscope (author)
Блокирование поля b4 разными чёрными фигурами. На доске силуэт собаки, символа 2018 года согласно восточному гороскопу (автор)
E571 3BR3/1p1p2p1/1Pp3p1/1r6/2K2kP1/4q3/8/7r
a) 1.Rh1-h6 Re8-e7 2.Kf4-g5 Re7-e4 # {,} 1.d7-d6 Bd8-e7 2.Kf4-e5 Be7-g5 # {,
E572 8/1p1B1p2/2Rp4/3p3q/K2N4/3k4/1p1p4/n7
1...Rc6-c2 2.Qh5-d1 Sd4-e2 3.Kd3*c2 Bd7-f5 # {,} 1...Rc6-c4 2.d5*c4 Bd7-f5 + 3.Kd3-c3 Sd4-b5 # {,} 1...Rc6-c5 2.d6*c5 Sd4-e2 3.Kd3-c4 Bd7-b5 #
3 active sacrifices by WR on unoccupied squares along the same line, model mates (authors)
3 активных жертвы WR на свободных полях на одной и той же линиис правильными матами (авторы)
Compare to | Сравните с:
P1284507 (director)
E575a
Solution | Решение 1...Bb5-c6 2.Qg2*f2 Qa5-c3 + 3.Qf2-g3 Se4-f2 # {,
4b3/4p3/6p1/QBp3P1/K1pnNp1p/7k/3b1Pqn/8 white Qa5 Pg5f2 Ka4 Bb5 Se4
black Qg2 Pe7g6h4f4c4c5 Sh2d4 Bd2e8 Kh3
h#2.5 two solutions (6+12)
E573
white Sf7 Rc2 Kb4
black Pf4e2 Se3 Bf3 Ke4 Rd3
h#2 4.1.. (3+6)
E574
white Pc3c2f4 Bh6a8 Rd1 Kf6
black Qa5 Pg6c7c6 Kd5 Rb5 Se3d3
h#2 b) Se3->e7 (7+8)
E575 See also version E575a
white Pf3e2g6 Kd2 Ba5 Se5
black Bg3b1 Kh4 Qf1 Ph5g2d5c5b5 Sh3 Rg7b3
h#2.5 b) +WRa5 (6+12)
E573 8/5N2/8/8/1K2kp2/3rnb2/2R1p3/8
1.Rd3-d5 Rc2-d2 2.Rd5-e5 Sf7-d6 # {,} 1.Ke4-d5 Rc2-c6 2.Bf3-e4 Rc6-d6 # {,
A Gravure problem with two pairs of thematically connected solutions with mates on the same squares (d6 & e5) by the both white pieces (author)
Гравюра с двумя парами решений, объединенными матами разными белыми фигурами на полях d6/e5 (автор)
E574 B7/2p5/2p2KpB/qr1k4/5P2/2Pnn3/2P5/3R4
a) 1.Kd5-e4 Rd1-e1 2.Sd3-c5 Ba8*c6 # {,} b) bSe3-->e7 1.Kd5-d6 Bh6-f8 2.c6-c5 Rd1*d3 #
A diagonal/orthogonal setting of black pin with double interference on the same square (c5) by the black unpinned pieces and pin-mates (author)
E575 8/6r1/6P1/BpppN2p/7k/1r3Pbn/3KP1p1/1b3q2 See also version E575a
a) 1...e2-e4 2.Rg7*g6 Ba5-d8 + 3.Rg6-g5 Se5-g6 # {,}
b) + wRa5 1...e2-e3 2.Qf1*f3 Ra5-a4 + 3.Qf3-g4 Se5-f3 #
Combination of white square vacation by capture of the white piece with pin of the black piece, Forsberg twins, mixed interference by WPe2 one-two play and pin-model mates with Umnov effects (author)
Комбинация освобождающей жертвы с последующим связыванием тематической черной фигуры, смешанным перекрытием, осуществляемым двойной игрой белой пешки, и правильными матами с эффектом Умнова. Близнец Форсберга (автор)
Compare to | Сравните с:
P1288792 , P1253912 (director)
E576
white Pc3 Sd3 Ba4 Kg1 Rg3
black Kd5 Bc6
h#2* set play + 2.1.. (5+2)
E577
white Pf4a7 Ka8 Rg7 Se5
black Rd4 Ke4 Bh1d6 Pe6e3
h#2 2.1.. (5+6)
E578
white Pd3d4f2g3c5 Kb1 Sg4b3
black Pe7a5 Kf5 Bd8
h#3 2.1.. (8+4)
E576 8/8/2b5/3k4/B7/2PN2R1/8/6K1
1...Rg3-f3 2.Kd5-e4 Ba4*c6 # {,} 1.Bc6-b5 Rg3-g6 2.Bb5-c4 Ba4-c6 # {,} 1.Bc6-d7 Rg3-g4 2.Bd7-e6 Rg4-d4 #
E577 K7/P5R1/3bp3/4N3/3rkP2/4p3/8/7b
1.Ke4-f5 + Rg7-b7 2.Rd4-e4 Rb7-f7 # {,} 1.Rd4-d5 Rg7-c7 2.Ke4-d4 Rc7-c4 #
E578 3b4/4p3/8/p1P2k2/3P2N1/1N1P2P1/5P2/1K6
1.e7-e5 f2-f4 2.e5*d4 Sg4-e5 3.Bd8-f6 Sb3*d4 # {,} 1.e7-e6 d4-d5 2.Bd8-f6 Sg4-e3 + 3.Kf5-e5 f2-f4 #
E579
white Pd5d3e2f3 Kh2 Bf1
black Pd6g4d4e3f5 Ke5 Rg1
h#3.5 2 solutions (6+7)
E580
white Pe2g2g5e4 Kg8 Bf1
black Pg7e7e6c5e3h5g3 Kd4 Sc1
h#5 2.1.. (6+9)
E581 ANTICIPATED
white Pc3g6g2e2e3 Kg1 Bf1
black Pg7e5e4c5g5g3 Ke8
h#14 one solution (7+7)
E579 8/8/3p4/3Pkp2/3p2p1/3PpP2/4P2K/5Br1
1...Bf1-h3 2.Rg1-d1 Kh2-g3 3.Rd1*d3 f3-f4 + 4.Ke5-e4 Bh3-g2 # {,} 1...Bf1-g2 2.Rg1-h1 + Kh2-g3 3.Rh1-h6 Bg2-h1 4.Rh6-f6 f3-f4 #
E580 6K1/4p1p1/4p3/2p3Pp/3kP3/4p1p1/4P1P1/2n2B2
1.Sc1*e2 g5-g6 2.Se2-g1 Bf1-d3 3.Sg1-f3 g2*f3 4.Kd4-e5 f3-f4 + 5.Ke5-f6 e4-e5 # {,} 1.Sc1-d3 e2*d3 2.Kd4-e5 d3-d4 + 3.Ke5-d6 Bf1-a6 4.e6-e5 d4*c5 + 5.Kd6-e6 Ba6-c8 #
E581 8/3k2p1/6P1/2p1p1p1/4p3/2P1P1p1/4P1P1/5BK1
1.Ke8-d7 Kg1-h1 2.Kd7-c6 Kh1-g1 3.Kc6-b5 c3-c4 + 4.Kb5-b4 Kg1-h1 5.Kb4-c3 Kh1-g1 6.Kc3-d2 Kg1-h1 7.Kd2*e3 Kh1-g1 8.Ke3-f4 e2-e3 + 9.Kf4-f5 Bf1-d3 10.Kf5*g6 Bd3*e4 + 11.Kg6-f6 Be4-h7 12.g7-g6 Kg1-f1 13.Kf6-f5 Kf1-e2 14.Kf5-e4 Bh7*g6 #
Anticipated | Предшественник:
P1351713 (director)
E582
white Qe6 Pc2f2 Kh6
black Pe7a4b3e3 Sc7e5 Ra6 Kd4
h#2 2.1.. b) Se5->c4 2.1.. (4+8)
E583
white Pf2 Kh8 Re6 Sc8 Bd6
black Pd5f3 Se5 Ra8b7 Kf5
h#2.5 b) Sc8->d8 (5+6)
E584
white Pf2 Ka1 Re7 Bc7
black Ba7 Ke5 Qh8 Pg3d7e4h6 Sh1c4 Rd6e6
h#3 b) Ka1->g1 (4+11)
E582 8/2n1p3/r3Q2K/4n3/p2k4/1p2p3/2P2P2/8
a) 1.Se5-d3 Qe6-c6 2.e7-e5 c2-c3 # {,} 1.Ra6-c6 f2-f4 2.Rc6-c4 Qe6*e5 # {,
E583 r1N4K/1r6/3BR3/3pnk2/8/5p2/5P2/8
a) 1...Re6-e8 2.Se5-d3 Bd6-e5 3.Kf5-e4 Sc8-d6 # {,}
b) wSc8-->d8 1...Bd6-b8 2.Se5-g4 Re6-e5 + 3.Kf5-f4 Sd8-e6 #
E584 7q/b1BpR3/3rr2p/4k3/2n1p3/6p1/5P2/K6n
a) 1.Ke5-f5 + Re7-g7 2.Re6-f6 f2*g3 3.Rd6-e6 g3-g4 # {,}
b) wKa1-->g1 1.Ke5-d5 Bc7-b6 2.Rd6-c6 f2-f3 3.Re6-d6 f3*e4 #
Compare to | Сравните с:
#421686 (director)
E587a
Solution | Решение 1.Ra2-h2 Bh5-f3 2.g3-g2 + Kf1-f2 3.Rh3-h7 Kf2-e3 4.Bc8-h3 Ke3-d4 5.Qb8-h8 + Kd4-c5 6.g2-g1=B + Kc5*c6 7.Bg1-a7 Kc6-c7 #
kqb5/4p3/2p5/7B/p7/6pr/r7/n1n2K2 white Kf1 Bh5
black Bc8 Ka8 Qb8 Pg3a4c6e7 Sc1a1 Ra2h3
h#7 one solution (2+11)
E587b
Solution | Решение 1.Rg2-h2 Bh5-f3 2.g3-g2 + Kf1-f2 3.Rh3-h7 Kf2-e3 4.Bc8-h3 Ke3-d4 5.Qb8-h8 + Kd4-c5 6.g2-g1=B + Kc5*c6 7.Bg1-a7 Kc6-c7 #
kqb5/4p3/2p5/7B/8/6pr/6r1/2n2K2 white Kf1 Bh5
black Bc8 Ka8 Qb8 Pg3c6e7 Sc1 Rg2h3
h#7 one solution (2+9)
E586a
Solution | Решение1...e4-e5 2.Kg6-f5 e5*f6 3.Kf5-e4 f6*g7 4.Ke4-d3 g7*h8=Q 5.Qh7-e4 Qh8-c3 # {,
5r1n/5ppq/4ppkp/7n/4P3/5p2/3Pb3/1K6 white Pd2e4 Kb1
black Be2 Kg6 Qh7 Pf3h6f6e6g7f7 Sh5h8 Rf8
h#4.5 2 solutions (3+12)
E585
white Pd5e5 Kb1 Se7f7
black Be8 Ke4 Qe6 Pf6 Sg8 Rc4
h#3.5 2 solutions (5+6)
E586 See also version E586a
white Pc2d4 Ka1
black Bd2g8 Kf6 Qg7 Pe3h5g6f7e7e6d6 Sg5 Rh7e8
h#4.5 2 solutions (3+14)
E587 See versions E587a E587b
white Kf1 Bh5
black Bb7 Ka8 Qb8 Pg3c2d3c3b5c6 Sc1 Rd2
h#7 one solution (2+11)
E585 4b1n1/4NN2/4qp2/3PP3/2r1k3/8/8/1K6
1...e5*f6 2.Qe6*e7 f6*e7 3.Be8-c6 e7-e8=Q + 4.Ke4*d5 Qe8-e5 # {,} 1...d5*e6 2.Be8*f7 e6*f7 3.Ke4*e5 f7*g8=Q 4.Rc4-f4 Qg8-d5 #
E586 4r1b1/4ppqr/3ppkp1/6np/3P4/4p3/2Pb4/K7 See also version E5860a
1...d4-d5 2.Kf6-e5 d5*e6 3.Ke5-d4 e6*f7 4.Kd4-c3 f7*g8=Q 5.Qg7-d4 Qg8-b3 # {,
E587 kq6/1b6/2p5/1p5B/8/2pp2p1/2pr4/2n2K2 See also author's version E587a E587b
1.Rd2-h2 {!!} Bh5-f3 {!!} 2.g3-g2 + Kf1-f2 3.Bb7-c8 Kf2-e3 4.Bc8-h3 Ke3-d4 5.Qb8-h8 + {!!} Kd4-c5 6.g2-g1=B + Kc5*c6 7.Bg1-a7 Kc6-c7 #
Linear black officers play on h-file with hideaway effect (author)
Линейные черные фигуры ищут убежище на линии h (автор)
E590a
Solution | Решение1.Qd1-h1 Ba8*h1 2.Ra3-a8 Bh1*a8 3.Rc1-h1 Ba8*h1 4.Ke5-d4 Kb2*b3 #
B7/8/8/2p1k3/1p6/rp1pb3/1K2p3/B1rq4 white Kb2 Ba8a1
black Qd1 Pb4c5e2d3b3 Ke5 Be3 Ra3c1
h#4 one solution (3+10)
E588
white Kb5 Ra8 Be1
black Pf7e2 Kh1
h#2.5 2 sols. b)Pe2->f2 2 sols. (3+3)
E589
white Qe4 Pf2a5 Ke1 Rh1a1
black Bd5d8 Kb5 Qh8 Pd3h4f5e6c6 Sf4c4 Re5b8
h#2 zero a)+wSa4, b)Kb5->g5 (6+13)
E590 See also version E590a
white Pe2 Kb2 Ba1h1
black Qa4 Pb5c5b4b3 Ke5 Ba8e3 Re1
h#3.5 one solution (4+9)
E588 R7/5p2/8/1K6/8/8/4p3/4B2k
a) 1...Be1-g3 2.e2-e1=R Ra8-a2 3.Re1-g1 Ra2-h2 # {,} 1...Be1-f2 2.e2-e1=S Ra8-a3 3.Se1-g2 Ra3-h3 # {,
Слабые превращения на фоне Умнова с правильными матами (автор)
E589 1r1b3q/8/2p1p3/Pk1brp2/2n1Qn1p/3p4/5P2/R3K2R
a) +wSa4 1.Kb5-b4 {(Bxa5?)} 0-0 2.Bd8*a5 Rf1-b1 # {,}
b) bKb5-->g5 1.Kg5-g4 {(Qh5?)} 0-0-0 2.Qh8-h5 Rd1-g1 #
Anticipatory prevention of negative effect in B2 allowing white castling (author)
Превентивное устранения негативного эффекта второго хода черных, открывающее возможность белой рокировки (автор)
E590 b7/8/8/1pp1k3/qp6/1p2b3/1K2P3/B3r2B See also version E590a
1...Bh1*a8 2.Re1-h1 Ba8*h1 3.Qa4-a8 Bh1*a8 4.Ke5-d4 Kb2*b3 #
Task - wB pendulum with amplitude 7 (author)
Маятник белого слона с максимальной амплитудой (автор)
E593a
Solution | Решение1.Kd5-d4 Bh1*e4 2.Sc3-d5 Be4*g6 3.Rg5-f5 Kf1-g2 4.Kd4-e4 Kg2-g3 5.Ba1-d4 f2-f3 #
8/8/4p1p1/3kp1rp/4p3/2npp3/3r1P2/b4K1B white Pf2 Kf1 Bh1
black Ph5g6e6e5e4d3e3 Kd5 Rg5d2 Sc3 Ba1
h#5 one solution (3+12)
E591
white Kc8 Se8
black Be2 Ke1 Qg7 Pd3a3a4e4c5 Sd2c4 Rh7
h#4 2.1.. (2+11)
E592
white Pe2 Kd3 Be3
black Pe7g7g6e6f5c5 Ke8 Rf7e1 Sb7g2
h#4.5 one solution (3+11)
E593 See also version E593a
white Pe2 Ke1 Bg1
black Pa4c3d3d4d5f6 Sc5e6 Bc2 Kc4 Rf5g6
h#4.5 one solution (3+12)
E591 2K1N3/6qr/8/2p5/p1n1p3/p2p4/3nb3/4k3
1.Sd2-b3 Se8-c7 2.Ke1-d2 Kc8-b7 3.Kd2-c3 Kb7-a6 4.Kc3-b4 Sc7-d5 # {,} 1.Qg7-c3 Se8-g7 2.Ke1-f2 Kc8-d7 3.Kf2-e3 Kd7-e6 4.Ke3-d4 Sg7-f5 #
E592 4k3/1n2prp1/4p1p1/2p2p2/8/3KB3/4P1n1/4r3
1...Be3*c5 2.Rf7-f8 e2-e4 3.Ke8-f7 Bc5-e3 4.Kf7-f6 Kd3-d4 5.Rf8-f7 e4-e5 #
E593 8/8/4npr1/2np1r2/p1kp4/2pp4/2b1P3/4K1B1 See also author's version E593a
1...Bg1*d4 2.Bc2-b3 Bd4*f6 3.Rf5-e5 Ke1-f2 4.Kc4-d4 Kf2-f3 5.Bb3-c4 e2-e3 #
E594a
Solution | Решение1.Bf7-g8 {! (Bg6?)} Kg7-f8 2.Ke5-f6 Kf8-e8 3.Kf6-g7 Ke8-e7 {tempo} 4.Kg7-h8 Ke7-f8 5.Bg8-h7 Sd6-f7 # {ideal mate}
8/5bK1/3N4/4k3/8/8/8/8 white Sd6 Kg7
black Ke5 Bf7
h#5 one solution (2+2)
E594 See also version E594a
white Ke5 Sd6
black Pf5 Ke7 Be6
h#5 one solution (2+3)
E595
white Pf5 Kh3
black Bf7a7 Ka8 Qf8 Pg6e6d5c5c6c7 Sb8 Rd8e7
h#4 2.1.. (2+13)
E596
white Pc2e3a4 Sb2 Kg7
black Qe6 Pf5c6b6 Kd5 Rd6d8 Bf7
h#3 2.1.. (5+8)
E594 8/4k3/3Nb3/4Kp2/8/8/8/8 See also version E594a
1.Ke7-f8 Ke5-f6 2.Kf8-g8 Kf6-e7 3.Kg8-h8 Ke7-e8 {! tempo} 4.Be6-g8 Ke8-f8 5.Bg8-h7 Sd6-f7 #
E595 kn1r1q2/b1p1rb2/2p1p1p1/2pp1P2/8/7K/8/8
1.Ka8-b7 f5*g6 2.Kb7-c8 g6-g7 3.Kc8-d7 g7-g8=S 4.Kd7-e8 Sg8-f6 # {,}
1.Bf7-e8 f5-f6 2.Be8-d7 f6*e7 3.Bd7-c8 e7-e8=S 4.Bc8-b7 Se8*c7 #
Zalokotsky theme, snake, long-trip, white underpromotions, model mates (authors)
Тема Залокцкого, тема змейки, слабые превращения в коней, правильные маты (авторы)
E596 3r4/5bK1/1pprq3/3k1p2/P7/4P3/1NP5/8
1.Kd5-c5 Kg7-h7 {! tempo (a5?)} 2.Qe6-b3 c2*b3 3.Bf7-d5 Sb2-d3 # {,} 1.Kd5-e5 a4-a5 {! tempo (Kh7?)} 2.Rd6-d3 c2*d3 3.Rd8-d5 Sb2-c4 #
E597
white Kd1 Bh1
black Pc7d4 Ka8 Rg2
h#7.5 b) Pc7->b4, h#8.5 (2+4)
E598 Dedicated to A. Melnichuk - 60
white Pc3c5d6 Se4b8 Rf4h5 Kf5
black Rg8 Sh2a5 Ba2h4 Kb5
h#2v 2.1.. (8+6)
E599 In Memoriam Yuri Fokin
white Pb2a2 Kd1
black Rc2 Bc1 Kb4
h#5 2.1.. (3+3)
E597 k7/2p5/8/8/3p4/8/6r1/3K3B
a) 1...Kd1-e1 2.c7-c5 Ke1-f1 3.c5-c4 Kf1*g2 4.c4-c3 Kg2-f3 5.c3-c2 Kf3-e4 6.c2-c1=B Ke4-d5 7.Bc1-f4 Kd5-c6 8.Bf4-b8 Kc6-b6 # {,
b) 1...Kc1 2.b3 Kb1 3.b2 Ka2 4.b1=S+ Kb3 5.Sc3 Kc4 6.Sb5 Kd5 7.Rb2 Kc6 8.Sa7+ Kc7+ 9.Rb7+ Bxb7#
Passive/active sacrifice of BR, promotion to bB/bS with selfblock on adjacent squares, two symmetric semi-Rundlaufs of wK from e1 to d5; try in b): 2.d3? 9.Rb2-b7?? (authors)
Пассивная/активная жертва BR, превращение в BB/BS с блокированиями на смежных полях, два симмеиричных полу-круиза WK с e1 до d5; попытка в b): 2.d3? 9.Rb2-b7?? (авторы)
Compare to | Сравните с:
P1196308 (director)
E598 1N4r1/8/3P4/nkP2K1R/4NR1b/2P5/b6n/8 Dedicated to Alexander Melnichuk - 60
1.Bh4-e1 Kf5-f6 2.Be1*c3 + Se4*c3 # {(1.Be7? K?? 2.Bxd6 Sxd6#? 3.Kxc5),
E599 8/8/8/8/1k6/8/PPr5/2bK4 In Memoriam Yuri Fokin (11.07.1925 - 16.02.2018)
1.Bc1-d2 Kd1-e2 2.Kb4-a4 Ke2-d3 3.Rc2-c3 + Kd3-d4 4.Rc3-b3 Kd4-c4 5.Bd2-a5 a2*b3 # {Y ,F }
Capital Latin Letters 'Y' and 'F' in mate positions (author)
В матовых позициях «Y» и «F» – Yuri Fokin (автор)
E600a
Solution | Решение1...Ke3-d4 2.Bc6-d7 Bb7*e4 3.Bb8-e5 + Kd4-c5 4.0-0-0 Kc5-b6 5.Be5-b8 Be4-b7 #
rb2k3/1B6/2b5/6r1/4n3/4K3/8/8 white Ke3 Bb7
black Se4 Bb8c6 Ra8g5 Ke8
h#4.5 one solution (2+6)
E601a
Solution | Решение1.Ka6-b6 Rc1-c8 2.Sd3-e5 Bf8-c5 # {,}
1.Ka6-b5 Bf8-a3 2.Se6-g5 Rc1-c5 #
5B1K/1b6/k3n2R/p6r/p3p3/3np3/8/2R2B2 white Kh8 Rc1h6 Bf1f8
black Pe3a4a5e4 Ka6 Rh5 Sd3e6 Bb7
h#2 2.1.. (5+9)
E601b
Solution | Решение 1.Kc1-c2 Rb3-a3 2.Sf4-d5 Be2-d3 # {,} 1.Kc1-d2 Be2-f1 2.Bc4-d5 Rb3-d3 #
A Meredith2R5/3r4/8/6B1/2b2n2/1R6/1p2B2K/2knr3 white Rb3c8 Kh2 Bg5e2
black Pb2 Sd1f4 Re1d7 Kc1 Bc4
h#2 2.1.. (5+7)
E600 See also version E600a
white Kd2 Bb7
black Bg8b8 Ke8 Qg4 Pd7d4c5b6a6 Sa3 Rg3a8
h#5.5 one solution (2+12)
E601 See versions E601a E601b
white Rc7h6 Kb1 Bb4f1
black Pa4c5 Ka6 Bb7d6 Sa5d3 Rh5h7
h#2 2.1.. (5+9)
E602 ANTICIPATED
white Ph7c4 Kh8 Bb5 Sf8c3
black Pa7d6 Sc6h5 Ra8 Kc5 Ba1
h#2 b) Sc3->d4 (6+7)
E600 rb2k1b1/1B1p4/pp6/2p5/3p2q1/n5r1/3K4/8 See also version E600a
1...Bb7-f3 2.Bb8-f4 + Kd2-d3 3.c5-c4 + Kd3*d4 4.b6-b5 Kd4-c5 5.0-0-0 Kc5-b6 6.Bf4-b8 Bf3-b7 #
E601 8/1bR4r/k2b3R/n1p4r/pB6/3n4/8/1K3B2 See also versions E601a E601b
1.Ka6-b6 Rc7-c8 2.Sd3-e5 Bb4*c5 # {,} 1.Ka6-b5 Bb4-a3 2.Bd6-e5 Rc7*c5 #
Compare to | Сравните с:
P1078631 (director)
E602 r4N1K/p6P/2np4/1Bk4n/2P5/2N5/8/b7
a) 1.Sh5-f6 {(Sg7?)} Sc3-d5 2.Sc6-b8 {(Sd8?)} Sf8-e6 # {,}
b) wSc3-->d4 1.Sh5-g7 {(Sf6?)} Sd4-c2 2.Sc6-d8 {(Sb8?)} Sf8-d7 #
The author has added a second pair of dual avoidances and now the both mates are model instead of just one in Vysotska's problem - see:
yacpdb/407506 P0535652 (director)
E603
white Se7 Kc3
black Ba4 Ke8 Qb8 Pd6e6a7a5a2d5 Sc2 Ra8
h#5 one solution (2+11)
E604 Dedicated to Gligori Janevski
white Pe4 Be3 Re2 Kb3
black Qh1 Pf5g6e7e6c5d4b4 Ke5 Rf6d6 Bc6
h#2 6.1.. (4+12)
E605
white Kh1 Sb6
black Bb8 Ke8 Qg7 Pc7b7 Se3 Ra8
h#5 one solution (2+7)
E603 rq2k3/p3N3/3pp3/p2p4/b7/2K5/p1n5/8
1.Qb8-b1 Se7*d5 2.0-0-0 Kc3-c4 3.Ba4-b3 + Kc4-b5 4.Bb3-c4 + Kb5-c6 5.Qb1-b8 Sd5-e7 #
Black Indian combined with black castling-Klasinc theme on b8 (authors)
Индийская тема в игре черных в сочетании с рокировочным Класинцем на b8 (авторы)
Compare to | Сравните с:
P0522151 (director)
E604 8/4p3/2brprp1/2p1kp2/1p1pP3/1K2B3/4R3/7q
1.d4-d3 Be3-c1 2.Ke5-d4 Bc1-b2 # {,} 1.Rf6-f7 Be3-h6 2.Ke5-f6 e4-e5 # {,
A task setting of organized disharmony with thematically connected solutions (I + II & III + IV+ V + VI) and 6 different mates by all white half-battery pieces: P/B/R (author)
E605 rb2k3/1pp3q1/1N6/8/8/4n3/8/7K
1.Bb8-a7 Sb6-d5 2.0-0-0 Sd5*c7 3.Se3-d5 Sc7-a8 4.Sd5-c7 Kh1-h2 5.Ba7-b8 Sa8-b6 #
E606
white Rf1a6 Sf8d4 Ba1e4 Ka4
black Bd5b6 Kf6 Qc5 Pb4c7 Sh4 Rf2
h#2 2.1.. (7+8)
E607
white Pb6b3f2 Kh4 Rg3 Bf6f7
black Pa3c3d3b5e7d7c6 Kc5 Rd6 Ba2
h#2 4.1.. (7+10)
E608
white Pf5e5b5a5h6 Ke1
black Ph2g3c3e4g5h7 Kd3 Sh5g8
h#3.5 5 solutions (6+9)
E606 5N2/2p5/Rb3k2/2qb4/Kp1NB2n/8/5r2/B4R2
1.Qc5-e7 Be4-g6 2.c7-c5 Sd4-e6 # {black Goethart ,}
1.Bd5-f7 Be4-c2 2.Qc5-g5 Sd4-f5 # {white Goethart}
Compare to | Сравните с:
#362558 (director)
E607 8/3ppB2/1Ppr1B2/1pk5/7K/pPpp2R1/b4P2/8
1.e7-e6 f2-f3 2.Kc5-d5 Rg3-g5 # {,} 1.e7-e5 b3-b4 + 2.Kc5-d4 Rg3-g4 # {,
A setting of helpmate of future with two pairs of thematically connected solutions (author)
E608 6n1/7p/7P/PP2PPpn/4p3/2pk2p1/7p/4K3
1...b5-b6 2.Kd3-c4 b6-b7 3.Kc4-b5 b7-b8=Q + 4.Kb5-a6 Qb8-b6 # {,} 1...f5-f6 2.Kd3-e3 f6-f7 3.Ke3-f3 f7-f8=Q + 4.Kf3-g2 Qf8-f1 # {,
E610a
Solution | Решение
1.Qg7*e5 Bg4-h5 2.Qe5-d4 Bh5-f7 # {,} 1.f3-f2 Bg4-e2 2.Sc6-d4 Be2-c4 # {,
8/3N2q1/2np4/3kN3/4ppB1/5p2/r7/2K5 white Kc1 Bg4 Se5d7
black Qg7 Pf3f4e4d6 Kd5 Ra2 Sc6
h#2 4.1.. (4+8)
E609
white Ph4f5d5g6f6e6a6 Kc1
black Pe2c4a5h6e7 Kd3 Bc2 Ra7
h#3 5.1.. (8+8)
E610 See also version E610a
white Pg6 Kd4 Ba3 Se6f8
black Qh1 Pg4g7 Kf6 Bf1
h#2 4.1.. (5+5)
E611
white Pg2a5 Kc1 Rd1 Sf4d4
black Pf2c2g3c3g6a6g7 Sa1b4 Rf1 Kc4 Bh6
h#3 b) Sd4->e2 (6+12)
E609 8/r3p3/P3PPPp/p2P1P2/2p4P/3k4/2b1p3/2K5
1.Kd3-e3 g6-g7 2.Ke3-f2 g7-g8=Q 3.Kf2-e1 Qg8-g1 # {,}
1.Kd3-d4 f6*e7 2.Kd4-c5 e7-e8=Q 3.Kc5-b6 Qe8-c6 # {,}
1.Kd3-e4 f6-f7 2.Ke4*f5 f7-f8=Q + 3.Kf5*g6 Qf8-f7 # {,
Compare to | сравните с:
yacpdb/406232 , E608 (director)
E610 5N2/6p1/4NkP1/8/3K2p1/B7/8/5b1q See also author's version E610a
1.Qh1-f3 Se6-g5 {(Sf4?)} 2.Qf3-f5 Sg5-h7 # {,} 1.Qh1-h5 Se6-f4 {(Sg5?)} 2.Qh5-f5 Sf8-h7 # {,
E611 8/6p1/p5pb/P7/1nkN1N2/2p3p1/2p2pP1/n1KR1r2
a) 1.Rf1-h1 {(Bg5?)} Sd4-e2 2.Rh1-h5 Rd1-d3 3.Rh5-b5 Rd3*c3 # {,
Two white units are pinned and black must choice which one to unpin. This depends on the position of a white S. White have no tempo moves in W1 and the S must play in the square that it occupies in the other twin position, in mutual way. Black moves three times the same piece. In B1 it keeps the pin, so that to prevent the inversion of white moves, in B2 it unpins and in B3 it self-blocks a square (author)
Две тематические белые фигуры связаны в начальной позиции и черным надо выбрать какую развязывать. Этот выбор зависит от исходной позиции несвязанного белого коня. У белых нет темпохода, и конь должен играть на поле, которое он занимает в позиции близнеца. Черные ходят трижды одной и той же фигурой. Вступительным ходом они сохраняют связку чтобы не было перестановки W1/W2, вторым ходом они осуществляют развязывание и третьим - блокируют поле (автор)
E612
white Kh4 Rh3 Bb2
black Pf6 Kb4
h#4 2.1.. (3+2)
E613
white Pb4d3 Kb3 Bf3
black Pa7d5 Ka6
h#3.5 2 solutions (4+3)
E614 Dedicated to Boris Shorokhov-50
white Kd5 Bh1
black Bb1h4 Kh3 Qb6 Ph2g3f4d6d7b5c4g6 Sg2e4 Re1g8
h#4 one solution (2+16)
E612 8/8/5p2/8/1k5K/7R/1B6/8
1.Kb4-c4 Kh4-g3 2.Kc4-d3 Kg3-f3 3.Kd3-d2 Bb2-c1 + 4.Kd2-e1 Rh3-h1 # {,
E613 8/p7/k7/3p4/1P6/1K1P1B2/8/8
1...Bf3-g4 2.d5-d4 Kb3-c4 3.Ka6-b7 Kc4-c5 4.Kb7-a6 Bg4-c8 # {,
E614 6r1/3p4/1q1p2p1/1p1K4/2p1np1b/6pk/6np/1b2r2B
1.Se4-c5 Kd5-d4 2.Sg2-e3 Bh1-c6 3.Se3-g2 {!} Kd4-d5 {!} 4.Sc5-e4 Bc6*d7 #
Возможно впервые реализована тема Класинца с открытием одной тематической линии и последующим возвратом на начальные поля трех (!) фигур сторон (автор)
E617a
Solution | Решение1...Sd8-c6 2.Rb3-b7 Sc6-b4 3.0-0-0 Kc2-b3 4.Kc8-b8 Kb3-a4 5.Kb8-a7 Ka4-a5 6.Rd8-a8 Sb4-c6 # {,
r2Nk3/8/8/8/8/1r6/2K5/8 white Kc2 Sd8
black Ke8 Rb3a8
h#5.5 1.2.1.. (2+3)
E615 Dedicated to Boris Shorokhov-50
white Pf2e2e3 Kb1 Bg2
black Qf3 Pf4g3g4b2c3b3c4c6 Sf1d1 Bh1 Ke4
h#5 one solution (5+13)
E616 Dedicated to Boris Shorokhov-50
white Rb2 Kc1 Bc8 Pc2b3a2
black Bc7 Ke8 Qb8 Pf5e6d7c3b4b5 Sb6 Ra7a8
h#4.5 one solution (6+12)
E617 See also version E617a
white Sc6 Kc2
black Ke8 Ra8b3
h#5 2.1.. (2+3)
E615 8/8/2p5/8/2p1kpp1/1pp1Pqp1/1p2PPB1/1K1n1n1b
1.Ke4-f5 {! (Ke5?)} e3*f4 2.Qf3-e3 {! (Q~?)} Bg2*c6 3.Bh1-d5 Bc6-e8 4.Qe3-f3 e2-e3 5.Kf5-e4 Be8-g6 #
Тема Класинца 2х2: две черные фигуры открывают и закрывают одну и ту же тематическую линию, предоставляя возможность двум другим фигурам осуществить передислокацию. Бристоль. Выбор игры (автор)
E616 rqB1k3/r1bp4/1n2p3/1p3p2/1p6/1Pp5/PRP5/2K5
1...Bc8-a6 2.Qb8-b7 Ba6*b5 3.Ra7*a2 Rb2*a2 4.0-0-0 Ra2-a8 + 5.Qb7-b8 Bb5-a6 #
Klasinc: w/ B-R (a6), b/ Q-R (b8), w/b B-R (a6). Kozakin theme, model pin-mate (author)
E617 r3k3/8/2N5/8/8/1r6/2K5/8 See also author's version E617a
1.Rb3-b7 Sc6-b4 2.0-0-0 Kc2-b3 3.Kc8-b8 Kb3-a4 4.Kb8-a7 Ka4-a5 5.Rd8-a8 Sb4-c6 # {,
В первом решении - возвраты белого коня и черной ладьи. Малютка, идеальные маты (author)
E618
white Kf5 Rc5
black Bg1a8 Kb3 Qb7 Pe4a4a6a7 Sa2 Ra3
h#4 b) black Ra4 (2+10)
E619
white Rb8 Ka3 Bb5
black Pg3f4e3d4c5f6d7c6 Ke4 Bh8a4 Sf8c8 Rb1
h#3 2.1.. b) wSb5 2.1.. (3+14)
E620
white Qh1 Pg3f4c4e5d5e7 Ke8
black Pf3d3b3f5 Ke4 Ba4b8 Sh6a7 Rb5a8
h#2 2.1.. b) Pd3->e3 2.1.. (8+11)
E618 b7/pq6/p7/2R2K2/p3p3/rk6/n7/6b1
a) 1.Sa2-b4 {! (Sc3?)} Rc5-c1 2.Sb4-d5 Kf5*e4 3.Sd5-c3 + Ke4-d3 4.Sc3-a2 Rc1-b1 # {,
Белая константа – «константа Барсукова», возвраты с точным выбором первого хода по ромбу и прямоугольнику, построение чёрной батареи, которая объявляет шах (authors)
E619 1Rn2n1b/3p4/2p2p2/1Bp5/b2pkp2/K3p1p1/8/1r6
a) 1.e3-e2 Bb5*e2 2.f6-f5 Rb8-b3 3.Bh8-e5 Be2-f3 # {,} 1.Ba4-d1 Bb5-f1 2.Bd1-g4 Rb8-b2 3.Ke4-f3 Bf1-g2 # {,
E620 rb2K3/n3P3/7n/1r1PPp2/b1P1kP2/1p1p1pP1/8/7Q
a) 1.Sa7-c8 Qh1-a1 2.Bb8*e5 {(a)} Qa1*e5 # {,} 1.Rb5*d5 + {(b)} Ke8-f8 2.Rd5-d4 Qh1-e1 # {,
HOFT. Changed functions of black batteries: play/destruction by interference. Shifted black moves Bxe5 and Rxd5 in pairs of solutions (author)
HOTF. Перемена функций черных батарей: игра – разрушение путем перекрытия. Перенос черных ходов (автор)
E623a
Solution | Решениеa) 1.Ke4-e5 + Bg8-d5 2.Bf3*d5 + Se3*d5 # {,
K5B1/b7/3p2p1/r1r2n1R/2Ppk3/4Nb2/4R3/8 white Ka8 Pc4 Se3 Re2h5 Bg8
black Pd4g6d6 Ke4 Bf3a7 Sf5 Rc5a5
h#2 -wBg8 (6+9)
E623b
Solution | Решение1.Bf3-h5 Rg5*h5 2.Ke4-e5 Se3-d5 # {,
K7/2q5/3p4/5nR1/2Ppk3/4Nb2/4R3/8 white Pc4 Se3 Re2g5 Ka8
black Qc7 Pd4d6 Ke4 Bf3 Sf5
h#2 2.1.. (5+6)
E621
white Pd2e2d3c6 Kd1 Bb1c1
black Pa2b2b7 Kh1 Ra1
h#3,5 b) Kh1->g1 (7+5)
E622
white Pg2c2b2e3e5c5 Be6d6 Re2 Kc8
black Ba2f6 Ke4 Qb4 Pd3g5c6h7 Sb3g6 Rd2h4
h#2 4.1.. (10+12)
E623 See versions E623a E623b
white Qg8 Pc4 Se3 Re2g5 Ka8
black Bf3a7 Ke4 Qc5 Pg2g4d4g6d6g7e7 Sf5 Ra5
h#2 b) -wQg8 (6+13)
E621 8/1p6/2P5/8/8/3P4/pp1PP3/rBBK3k
a) 1...c6*b7 2.b2*c1=S b7-b8=Q 3.Sc1*d3 Qb8-g3 4.Sd3-c1 Bb1-e4 # {,}
b) bKh1-->g1
1...c6-c7 2.a2*b1=S c7-c8=Q 3.Sb1*d2 Qc8-h3 4.Sd2-b1 Bc1-e3 #
Тема Зилахи со взаимным превращением пешек. Возврат черных фигур с развязыванием белых. Мередит (автор)
E622 2K5/7p/2pBBbs1/2P1P1p1/1q2k2r/1s1pP3/bPPrR1P1/8
1.Sb3-d4 Be6-g4 {(1...exd4? 2.Kxd4 c3??, 1...Bd7 ??)} 2.Sd4-f5 Bg4-f3 # {,} 1.Rh4-f4 {(1...exf4? 2.Kxf4 exf6??, 1...Bg4 ??)} Be6-d7 2.Rf4-f5 Bd7*c6 # {,
Compass theme (South) combined with Zajic and Kniest themes (author)
E623 K5Q1/b3p1p1/3p2p1/r1q2nR1/2Ppk1p1/4Nb2/4R1p1/8 See also versions E623a E623b
a) 1.Ke4-e5 + Qg8-d5 + 2.Bf3*d5 + Se3*d5 # {,}
b) -wQg8
1.Qc5*c4 Se3*f5 + 2.Ke4-d5 Sf5*e7 #
Different battery mates (authors)
Батарейные маты разными фигурами (авторы)
E625a
Solution | Решение1.Rf3-e3 Rh1-h3 {!} 2.Re3-e7 Rh3-h2 3.Re7-g7 Kh4*g3 # {,
Twinless version. Meredith (director)6b1/3p3k/5pp1/8/5rpK/5rp1/6p1/7R white Kh4 Rh1
black Pd7f6g6g4g3g2 Kh7 Bg8 Rf4f3
h#3 2.1.. (2+10)
E625b
Solution | Решение 1.Rc3*c4 Rh1-h3 {!} 2.Rc4-c7 Rh3-h2 3.Rc7-g7 Kh4*g3 # {,
1b4b1/7k/3pppp1/8/2P1r1pK/1pr3p1/6p1/7R white Pc4 Kh4 Rh1
black Pg2g3b3g4g6f6e6d6 Kh7 Rc3e4 Bg8b8
h#3 2.1.. (3+13)
E624
white Pc2g3g4d4d5 Kf2 Rd2 Bf7
black Qh7 Pc3e5 Ke4 Re1e3 Bf5
h#2 4.1.. (8+7)
E625 See versions E625a E625b
white Kh4 Rh1
black Qd1 Pd7f6g6g4g3g2 Bg8 Rf3d3 Kh7
h#3 b) -bRd3 (2+11)
E626
white Pc6d3h4f3 Se3 Rf5 Kf2
black Be2d8 Kd6 Qf4 Ph7d4c7e6f6e5 Sf1 Ra2e7
h#3 2.1.. (7+13)
E624 8/5B1q/8/3Ppb2/3Pk1P1/2p1r1P1/2PR1K2/4r3
1.Qh7-g8 Bf7-g6 2.Qg8*d5 Bg6*f5 # {,} 1.Bf5-e6 Bf7-g8 2.Be6*d5 Bg8*h7 # {,
L'idée des noirs dans la 1ere paire est de bloquer la case d5/d4 et pour les blancs de mater sur les vecteurs h7-e4 /e1-e4. Mais tactiquement, le déroulement s'effectue de manière différente.
La tactique noire: Dans une phase une pièce noire s'embusque pour atteindre la case d5 ou d4 toute en perdant la garde d'une case (X) de dans une autre phase elle ouvre tout en perdant la garde d'une autre case (Y).
La tactique blanche: Dans une phase, les pièces blanches ouvrent les lignes des pièces noires toute en occupant les vecteurs directement (Fg6; Te2) aux 1ers coups. Dans une autre phase. Les pièces blanches reculent (Fg8; Td1) et occuperont les vecteurs aux 2ème coups.
On atteint les mêmes objectifs de manière différente (author)
E625 6b1/3p3k/5pp1/8/6pK/3r1rp1/6p1/3q3R See also author's versions E625a E625b
a)
1.Rd3-e3 Rh1-h2 {!} 2.Re3-e7 Rh2-h3 3.Re7-g7 Kh4*g4 # {,}
b) -bRd3
1.Rf3-e3 Rh1-h3 {!} 2.Re3-e7 Rh3-h2 3.Re7-g7 Kh4*g3 #
White minimal (authors)
Минимальная задача. (авторы)
E626 3b4/2p1r2p/2Pkpp2/4pR2/3p1q1P/3PNP2/r3bK2/5n2
1.Qf4-e4 {!} Rf5-f4 {!} 2.e5*f4 f3*e4 3.Kd6-e5 Se3-c4 # {,} 1.Qf4-g5 {!} Se3-d5 {!} 2.e6*d5 h4*g5 3.Kd6-e6 Rf5*f6 #
A task of four active sacrifices on free squares: two - by White's R/S (involving Zilahi) and two - by bQ (author)
Рекордная задача - 4 тихие активные жертвы: белых по Зилахи, чёрного ферзя под удары пешек (автор)
E627 In Memoriam Vadim Vinokurov
white Pd6d4d5 Kh1 Ra4 Sh6g4 Ba8
black Qd1 Ph5d7b6b5g3h3h2d3 Sg1 Ra6 Ke4
h#3 2.1.. (8+12)
E628 In Memoriam Vadim Vinokurov
white Kh3 Bg2
black Qe2 Kf2 Bg1f1 Sd2
h#4 one solution (2+5)
E629 In Memoriam Vadim Vinokurov
white Pe3d4d5 Kd1 Bf7 Rd8
black Ba1 Kc4 Qc3 Pb3a3c5a5 Sd2b5 Rh2c2
h#2 see text (6+11)
E627 B7/3p4/rp1P3N/1p1P3p/R2Pk1N1/3p2pp/7p/3q2nK
1.Qd1-b3 Sg4-e3 2.Qb3*d5 Se3-g2 3.Qd5-b7 Ba8*b7 # {,} 1.Qd1-a1 Sh6-f5 2.Qa1*d4 Sf5-h4 3.Qd4-b4 Ra4*b4 #
Compare to | Сравните с:
P0576487 , yacpdb/400379 (director)
E628 8/8/8/8/8/7K/3nqkB1/5bb1
1.Bg1-h2 Bg2*f1 2.Kf2-g1 Bf1*e2 3.Kg1-h1 Be2-f1 4.Bh2-g1 Bf1-g2 #
На доске силуэт голуба - символа мира. Белый слон в решении дважды описывает букву "V". Вадиму Винокурову (Vadim Vinokurov) посвящается.
Минимальная миниатюра-аристократ - тема ТТ-203 (автор)
E629 3R4/5B2/8/pnpP4/2kP4/ppq1P3/2rn3r/b2K4
a) {diagram}
1.Kc4-d3 Rd8-e8 2.Sd2-c4 {(c4?)} Bf7-g6 # {,}
b) bSb5-->f6 {Sb5->f6}
1.Kc4-b4 Bf7-e8 2.c5-c4 {(Sc4?)} Rd8-b8 # {,
Compass theme - West (author)
E631a
Solution | Решение1.Kd6-d7 Rd2-f2 2.Qf4-b8 Bg3-c7 3.Qb8-c8 Rf2-f7 # {,
4n3/8/2pkp3/8/5q2/3b2B1/3R2K1/2r5 white Rd2 Bg3 Kg2
black Bd3 Kd6 Qf4 Pc6e6 Se8 Rc1
h#3 2.1.. (3+7)
E632a
Solution | Решение1.Ra5*b5 + Kc5*b5 2.g6-g5 Bb6-g1 3.Ba7-e3 Bg1-h2 # {,
8/bp1qp3/1Bn1B1p1/rRK5/4rk2/1b3p2/n7/8 white Kc5 Rb5 Be6b6
black Bb3a7 Kf4 Qd7 Pf3g6e7b7 Sa2c6 Re4a5
h#3 2.1.. (4+12)
E630 In Memoriam Vadim Vinokurov
white Pg5g4e5e3b4a6 Sf1d7 Kc8
black Ph5g6f2b5a7 Ke1 Be8
h#4 2.1.. b) Ke1->f1 2.1.. (9+7)
E631 See also version E631a
white Bg3 Rd1 Ka1
black Bd3 Kd6 Qf4 Pc6e6 Se8 Rc2
h#3 2.1.. (3+7)
E632 See also version E632a
white Rb5 Sh6 Bb6 Kc5
black Ba7c8 Kf4 Qb3 Pb7b4c3f3g6e6e7 Sc6h8 Ra5e4
h#3 2.1.. (4+15)
E630 2K1b3/p2N4/P5p1/1p2P1Pp/1P4P1/4P3/5p2/4kN2
a) 1.Ke1-d1 e3-e4 2.Kd1-c2 Sf1-e3 + 3.Kc2-b3 Se3-c2 4.Kb3-a4 Sd7-c5 # {,} 1.Ke1-e2 g4*h5 2.Ke2-f3 Sf1-d2 + 3.Kf3-g4 Sd2-f3 4.Kg4*h5 Sd7-f6 # {,
HOTF in 4 moves (authors)
E631 4n3/8/2pkp3/8/5q2/3b2B1/2r5/K2R4 See also version E631a
1.Kd6-d7 Rd1-f1 2.Qf4-b8 Bg3-c7 3.Qb8-c8 Rf1-f7 # {,} 1.Kd6-c7 Bg3-e1 2.Bd3-a6 Rd1-d8 3.Ba6-b7 Be1-a5 #
Compare to | Сравните с:
yacpdb/438970 , yacpdb/430721 , P1083348 (director)
E632 2b4n/bp2p3/1Bn1p1pN/rRK5/1p2rk2/1qp2p2/8/8 See also version E632a
1.Ra5*b5 + Kc5*b5 2.g6-g5 Bb6-g1 3.Ba7-e3 Bg1-h2 # {,} 1.Ba7*b6 + Kc5*b6 2.Re4-e3 Rb5-g5 3.Ra5-e5 Rg5-g4 #
Compare to | Сравните с:
yacpdb/395964 (director)
E633
white Pc2 Bb6 Rb5 Ka6
black Bc3e2 Kf4 Qe6 Pa7d2g6h6 Sa5d5 Ra8d4
h#3 2.1.. (4+12)
E634 Dedicated to Ivan Antipin - 65
white Qh3 Ka4 Rc4 Be7
black Bg2e5 Ke6 Qf1 Pb6a5h4g4h5 Sh7d8 Re1
h#2 2.1.. (4+12)
E635
white Pf3d3 Kh1 Bg7e8
black Ph7e7 Sf5 Rd5g8 Ke6
h#3 4.1.. (5+6)
E633 r7/p7/KB2q1pp/nR1n4/3r1k2/2b5/2Ppb3/8
1.Be2-f3 Rb5*d5 2.Kf4-e3 Rd5-c5 3.Rd4-f4 Rc5-e5 # {,} 1.Qe6-g4 Bb6*d4 2.Kf4-g5 Bd4-c5 3.Sd5-f4 Bc5-e7 #
Compare to | Сравните с:
P0575529 (director)
E634 3n4/4B2n/1p2k3/p3b2p/K1R3pp/7Q/6b1/4rq2
1.Qf1-f5 Qh3-b3 2.Bg2-h3 Rc4-c7 # {,} 1.Bg2-d5 Rc4*g4 2.Qf1-a6 Rg4-g7 #
E635 4B1r1/4p1Bp/4k3/3r1n2/8/3P1P2/8/7K
1.Sf5-d6 f3-f4 2.Sd6-e4 d3*e4 3.Rd5-d6 f4-f5 # {,} 1.Rd5-e5 d3-d4 2.Re5-e4 f3*e4 3.Sf5-d6 d4-d5 # {,
Four mates on initial squares occupied with black units: Sf5 (f5#), Rd5 (d5#), Rg8 (Bg8#) and Ke6 (Be6#) - delayed Umnov. All the mates are model. Meredith (author)
E636
white Pb2a2b3 Kc1 Ra1 Bc8
black Bg6c7 Ke8 Qb8 Pd3b4f5e5b5h7d7 Se4b6 Ra7a8
h#4.5 4 solutions (6+15)
E637
white Kh1 Bh2
black Rh4f4 Ke3 Bf2h3 Sh5
h#6.5 one solution (2+6)
E638
white Pc2 Sa2 Kd6
black Pc4a7 Kf1
h#7 one solution (3+3)
E636 rqB1k3/r1bp3p/1n4b1/1p2pp2/1p2n3/1P1p4/PP6/R1K5
1...Bc8*d7 + 2.Ke8-d8 Bd7-e8 3.Kd8-c8 a2-a4 4.Kc8-b7 Be8-c6 + 5.Kb7-a6 a4*b5 # {,
E637 8/8/8/7n/5r1r/4k2b/5b1B/7K
1...Bh2-g1 2.Rf4-f3 Kh1-h2 3.Bh3-g4 + Kh2-g2 4.Sh5-f4 + Kg2-f1 5.Sf4-h3 Kf1-g2 6.Ke3-f4 Kg2-h1 7.Kf4-g3 Bg1-h2 #
Tempo moves including switchback of the white bishop and round-trip of the white King. Ideal mate (author)
Темпоходы, включая возврат белого слона и round-trip белого короля. Идеальный мат (автор)
E638 8/p7/3K4/8/2p5/8/N1P5/5k2
1.c4-c3 Sa2*c3 2.a7-a5 Sc3-d5 3.Kf1-e2 c2-c4 4.Ke2-d3 c4-c5 5.Kd3-c4 Kd6-c7 6.Kc4-b5 Kc7-b8 7.Kb5-a6 Sd5-c7 #
E640a
Solution | Решение 1...Rb1-a1 2.Rh8-h2 Ra1-a7 3.Rh2*d2 Ra7-d7 4.Rd2-f2 Bc1-g5 5.Rf2-f7 Rd7-d8 # {,
4k1nr/8/2pb4/8/8/1p1p4/1P1P4/1RB3K1 white Rb1 Kg1 Bc1 Pd2b2
black Ke8 Pd3b3c6 Rh8 Bd6 Sg8
h#4.5 2 solutions (5+7)
E639a
Solution | Решение1...Kg2-h2 {(Kg1?)} 2.Kd5-c4 Bh1-g2 {!} 3.Rf3-c3 Bg2-h3 {
3q4/1p6/2b5/2pk4/1p4p1/1p3r2/6K1/7B white Kg2 Bh1
black Qd8 Pb3b4c5b7g4 Kd5 Bc6 Rf3
h#5.5 one solution (2+9)
E639 See also version E639a
white Pb3 Kc2 Bb1
black Qd7 Pf6e7e3b5b4a3 Bh7 Rh5d3 Kf5
h#5.5 2 solutions (3+11)
E640 See also version E640a
white Pb2d2f2h2 Kg1 Bc1 Rh1
black Pb3d3g2h7g7f3 Ke8 Bf8f7 Sg8e7 Rh8
h#5 one solution (7+12)
E641
white Pb2 Ka1 Bf1
black Qh6 Pg2a2h3g3b3g4f4e5 Rg6f6 Bg5 Ke6
h#5.5 one solution (3+13)
E639 8/3qp2b/5p2/1p3k1r/1p6/pP1rp3/2K5/1B6 See also author's version E639a
1...Kc2-c1 2.Kf5-e6 Bb1-c2 3.Rd3-d6 Bc2-d1 4.Bh7-b1 Bd1-c2 5.Rh5-e5 Bc2-h7 6.Bb1-f5 Bh7-g8 # {,
Feather theme, Klasinc w/b Bc2, b/ Qe6, Bristol w/b B-B, b/w Q-B, model mates (author)
E640 4kbnr/4nbpp/8/8/8/1p1p1p2/1P1P1PpP/2B3KR See also version E640a
1.g7-g5 h2-h4 2.Bf8-g7 h4*g5 3.Bg7*b2 Rh1*h7 4.Sg8-h6 Bc1*b2 5.0-0 Rh7-h8 #
E641 8/8/4krrq/4p1b1/5pp1/1p4pp/pP4p1/K4B2
1...Bf1*g2 2.Ke6-f5 Bg2*h3 3.g3-g2 Bh3*g2 4.Qh6-h1 + Bg2-f1 5.Qh1-e4 Bf1-g2 6.g4-g3 Bg2-h3 #
W1W4W5 & W2W3W6: two pendulums of wB | два маятника белого слона (author)
Compare to | Сравните с:
yacpdb/347007 (director)
E642 Dedicated to Anatoly Skripnik - 60
white Pf2b2 Kg3 Rh4 Sc3c5 Ba7
black Pf6 Kc4 Bd4
h#1.5 5 solutions (7+3)
E643 (correction by Vladislav Nefyodov)
white Pd5e5c5d2 Se8 Bh1f4 Kh3
black Qb5 Ph5h4e6b7 Kc4
h#3 3.1.. (8+6)
E644
white Pc4 Kb5 Rc2
black Pd5e4e5e7d7c7b6b2 Kd6 Be6 Sa4b1
h#2 b) Pc4->d4 (3+12)
E642 8/B7/5p2/2N5/2kb3R/2N3K1/1P3P2/8
1...f2-f4 2.Bd4-e5 f4*e5 # {,} 1...Kg3-f4 2.Bd4-e3 + Kf4*e3 # {,
E643 4N3/1p6/4p3/1qPPP2p/2k2B1p/7K/3P4/7B
1.Kc4-d4 Se8-d6 {(A)} 2.Qb5-e2 Bf4-e3 + {(B)} 3.Kd4-d3 Bh1-e4 # {(C),
This is correction of cooked problem
P0504281 . All three mates are model (director)
E644 8/2ppp3/1p1kb3/1K1pp3/n1P1p3/8/1pR5/1n6
a) 1.Sb1-d2 {(Sbc3+?)} c4*d5 2.Kd6*d5 Rc2*d2 # {,}
b) wPc4-->d4 1.Sa4-c5 {(Sac3+?)} Rc2*c5 2.b6*c5 d4*c5 #
active sacrifice and choise of move in B1, active sacrifice in W1 (involving active Zilahi), model mates (author)
E645a
Solution | Решение 1.Bh6-g5 h4*g5 2.0-0 Qh1-h8 # {,
r3k2r/3p1q2/7b/1K2BP2/4P2P/p7/8/7Q white Qh1 Pf5h4e4 Kb5 Be5
black Qf7 Pa3d7 Ke8 Bh6 Rh8a8
h#2 3.1.. (6+7)
E645 See also version E645a
white Qh1 Ph4g4 Kf3 Be5
black Pe3d3c5g6b6 Sa5e7 Bg5 Ke8 Rh8a8
h#2 b) Be5->f6, c) Be5->d1 (5+11)
E646
white Pd4 Kd6
black Bf8d5 Ka7 Qb7 Pf6a6 Sd7 Re7b8
h#4 2.1.. (2+9)
E647
white Ph2g4d3c5 Kf7 Bf5e7
black Kc8 Pe2g3e4e5e6c7 Rf2b7 Bf3d8 Sg7b6
h#2 2.1.. b) Kc8->e3 2.1.. (7+13)
E645 r3k2r/4n3/1p4p1/n1p1B1b1/6PP/3ppK2/8/7Q See also version E645a
a) 1.0-0-0 Kf3-g3 2.Rd8-d7 Qh1-a8 # {,} b) wBe5-->f6 1.0-0 h4*g5 2.Rf8-f7 Qh1-h8 # {,} c) wBe5-->d1 1.Ke8-f7 Bd1-b3 + 2.Kf7-f6 Qh1-a1 #
Threefold play by wQ from corner to corner after opening of white lines by friendly unit. Ideal twins. In a) and b) we see castlings with active self-blocks by Rooks (like in
P0578361 ), in c) – unexpected move by BK from the edge of the board. The author hasn’t choose the Meredith version [r3k3/4n3/1p4p1/n1p1B1p1/4K2P/8/8/7Q, b) Ra8->h8, c) Be5->d1] in view of less lucky twins.
Also compare to the following works by the same author:
yacpdb/456406
and
yacpdb/456405 in which wQ's lines are opened by Black (director)
Трехкратная игра ферзя из угла в угол после самостоятельного вскрытия линий белыми. Форма идеальных близнецов. В а) и b) – рокировки с активными блокированиями ладьями (как в
P0578361 ), в с) – неожиданный уход черного короля от края доски с пассивными блокированиями.
Автор не выбрал мередитную версию [r3k3/4n3/1p4p1/n1p1B1p1/4K2P/8/8/7Q, b) Ra8->h8, c) Be5->d1] из-за менее удачных близнецов.
Также сравните с задачами автора
yacpdb/456406 и
yacpdb/456405 , где линии для ходов ферзя из угла в угол вскрываются силами черных, а не белых (директор)
E646 1r3b2/kq1nr3/p2K1p2/3b4/3P4/8/8/8
1.Bd5-c6 d4-d5 2.Qb7-a8 d5*c6 3.Rb8-b7 c6-c7 4.Sd7-b8 c7-c8=S # {
White minimal (author)
E647 2kb4/1rp1BKn1/1n2p3/2P1pB2/4p1P1/3P1bp1/4pr1P/8
a) 1.c7-c6 Bf5*e6 + 2.Kc8-c7 Be7-d6 # {,} 1.Kc8-d7 Bf5*e4 2.Sb6-c8 c5-c6 # {
HOTF a1/b1 a2/b2 (author)
E648
white Pb4h4 Kc2
black Bf8 Ke8 Qd8 Ph5f7b6 Sg8 Ra6
h#4 3.1.. (3+8)
E649 Dedicated to V. Nefyodov-60
white Sd2 Pd4a4c6 Bb2 Ra2 Kd3
black Bb1b8 Ka7 Qa1 Pc2f4b4c7d6d5f6g7 Se3e8
h#3 b) Sd2->e6 (7+16)
E650 Dedicated to V. Nefyodov-60
white Pf4b4c5d4 Ke7 Rc8 Bh6
black Kc1 Pf5h3f2a4b5 Be8g7 Rd8 Se6b1
h#4 2.1.. (7+11)
E648 3qkbn1/5p2/rp6/7p/1P5P/8/2K5/8
1.Bf8-c5 b4*c5 2.Ra6-a7 c5*b6 3.Ra7-e7 b6-b7 4.Qd8-c8 + b7*c8=Q # {,
E649 1b2n3/k1p3p1/2Pp1p2/3p4/Pp1P1p2/3Knr2/RBpN1r2/qb6
a) 1.Qa1*b2 Ra2-a1 2.Qb2-a2 Sd2-c4 3.Qa2*a4 Ra1*a4 # {,}
b) wSd2-->e6 1.Qa1*a2 Bb2-a1 2.Qa2-b2 Se6*c7 3.Qb2*d4 + Ba1*d4 #
E650 2Rrb3/4K1b1/4n2B/1pP2p2/pP1P1P2/7p/5p2/1nk5
1.Rd8*d4 Rc8-d8 2.Rd4-d1 Rd8-d4 3.Se6*f4 Rd4*f4 4.Bg7-b2 Rf4-c4 # {,
E651
black Ph7h6h3g4e4d5b7 Sd2 Rg3f2 Ka8
white Pg5f4e3e2a2 Sc6 Rg2f3 Ke1
h#2 4.1.. (9+11)
E652
white Kc1 Pf5d3 Ba5e8 Rh4
black Pa7f6 Be5 Kd6
h#2 see text (6+4)
E653
white Kh1 Sf3d3 Rc5
black Pe2g3c3d4c4d6 Rd2e5 Ke4 Sa6 Ba8
h#2 3.1.. (4+11)
E651 k7/1p5p/2N4p/3p2P1/4pPp1/4PRrp/P2nPrR1/4K3
1.g4*f3 g5*h6 2.Rg3-g8 Rg2*g8 # {,} 1.h6*g5 f4*g5 2.Rf2*g2 Rf3-f8 # {,
Compare to | Сравните с:
yacpdb/446706 (director)
E652 4B3/p7/3k1p2/B3bP2/7R/3P4/8/2K5
a) {diagram position} 1.Kd6-c5 Be8-c6 2.Be5-d6 Rh4-c4 # {,
The BK moves on c5, d4, e5 and return on d6. The second thematic piece (BB) moves on the same squares: d6, c5, d4 and return on e5 (author)
Compare to | Сравните с:
P0539284 (director)
E653 b7/8/n2p4/2R1r3/2ppk3/2pN1Np1/3rp3/7K
1.Sa6*c5 Sf3-g5 + 2.Ke4-d5 Sd3-b4 # {,} 1.Ke4*d3 Rc5*e5 2.d6-d5 Sf3-e1 # {,} 1.Ke4*f3 Sd3-f2 2.Re5-e3 Rc5-f5 #
Compare to | Сравните с:
P1094972 (director)
E654
white Qb1 Kc3 Pd4
black Pa3a4a5d2b5 Kd6 Qe6
h#2 see text (3+7)
E655
white Ph4 Kh3 Rf6 Sf5f3 Be2
black Bb8c8 Ke4 Qh1 Pb7f7d6d5c2c4h2f4 Sc6 Rc3f2
h#2 b) Sc6->c7 (6+15)
E656
white Rf8 Kb1 Bg8 Se6f6
black Bg6a3 Ke3 Qd5 Pf7h5g5e5b3c3c5 Sd4 Rf5c8
h#3 b) Sd4->e4 (5+14)
E654 8/8/3kq3/pp6/p2P4/p1K5/3p4/1Q6
a) {diagram} 1.Kd6-d5 Qb1-h7 2.Qe6-e4 Qh7-d7 # {,
The Bukovina maneuver - the movement of at least two white and/or black pieces on at least three different squares and their return to original positions.
The bK moves on d5, c5 and return on d6. The bQ moves on e4, c6 and return on e6. The twin “in mate position with the reatriting moves of the white” is specific to this maneuver (author)
E655 1bb5/1p3p2/2np1R2/3p1N2/2p1kp1P/2r2N1K/2p1Br1p/7q
E656 2r2RB1/5p2/4NNb1/2pqprpp/3n4/bpp1k3/8/1K6
a) 1.Qd5-f3 Se6*d4 2.Ke3*d4 Rf8*f7 3.Qf3-e3 Rf7-d7 # {,}
b) bSd4-->e4 1.Rf5-f3 Sf6*e4 2.Ke3*e4 Bg8*f7 3.Rf3-e3 Bf7*g6 #
E657
white Pc5g2g4g3g5 Ka3
black Qf8 Pb3c6b6d6g6g7f7 Kh8 Rg8
h#3.5 see text (6+10)
E658
white Ph5c3 Sf7 Bh6f5 Kd7
black Rb5 Kf6 Ba2a1
h#2 2.1.. (6+4)
E659
white Pb2 Ke4
black Pa5b5b6 Kc2
h#5 2.1.. (2+4)
E657 5qrk/5pp1/1ppp2p1/2P3P1/6P1/Kp4P1/6P1/8
a) {diagram} 1...c5*d6 2.Qf8-d8 d6-d7 3.Qd8*g5 d7-d8=Q 4.Qg5-h4 Qd8*h4 # {,
E658 8/3K1N2/5k1B/1r3B1P/8/2P5/b7/b7
1.Rb5*f5 Sf7-e5 2.Ba2-f7 Se5-g4 # {,} 1.Kf6*f7 c3-c4 2.Ba1-f6 Bf5-e6 #
Black Umnov in the first solution (on f6), bicolor Umnov in the second solution (on f7), Zilahi, model mates (author)
E659 8/8/1p6/pp6/4K3/8/1Pk5/8
{I} 1.Kc2-d2 {tempo} b2-b4 2.Kd2-c3 b4*a5 3.Kc3-b4 a5-a6 4.Kb4-a5 a6-a7 5.Ka5-a6 a7-a8=Q # {,
Zweimal Tempoverlust des schwarzen Königs im Sechssteiner. Verzögerter Umnov & Excelsior in Lösung I. Einmal Mustermatt, einmal Idealmatt (author)
Темпоигра черного короля, отсроченный Умнов, эксцельсиор и правильный мат в первом решении. Идеальный мат во втором (автор)
E660
white Qf3 Kh3 Rd7 Bh1
black Bc8 Ke5 Qa3 Pb7d4d5f7h5 Se3f5 Rf1
h#2 2.1.. (4+11)
E661
white Kh1 Bg2
black Qb7 Pb5c3d5f4 Ka6 Bb2
h#6 b) Bg2->c8 (2+7)
E662
white Pb4b3b5b6d5c2 Ka5
black Pd6d7b7c3 Ka8
h#13.5 one solution (7+5)
E660 2b5/1p1R1p2/8/3pkn1p/3p4/q3nQ1K/8/5r1B
1.Sf5-g3 {!} Qf3*f7 2.Se3-g4 Rd7*d5 # {,} 1.Se3-g4 {!} Rd7*f7 2.Sf5-g3 Qf3*d5 #
Preventive and indirect unpin of wQ and wR by bSs. White pieces play on two squares d5 and f7 (author)
E661 8/1q6/k7/1p1p4/5p2/2p5/1b4B1/7K
a) 1.Bb2-a3 Bg2*d5 2.Ba3-c5 Kh1-g2 3.b5-b4 Kg2-f3 4.Ka6-b5 Bd5-c6 + 5.Kb5-c4 Kf3-e4 6.Qb7-b5 Bc6-d5 # {,
E662 k7/1p1p4/1P1p4/KP1P4/1P6/1Pp5/2P5/8
1...Ka5-a4 2.Ka8-b8 Ka4-a3 3.Kb8-c8 Ka3-a2 4.Kc8-d8 Ka2-b1 5.Kd8-e7 Kb1-c1 6.Ke7-f6 Kc1-d1 7.Kf6-e5 Kd1-e2 8.Ke5*d5 Ke2-d3 9.Kd5-e6 Kd3*c3 10.d6-d5 Kc3-d3 11.d5-d4 Kd3-e4 12.Ke6-d6 Ke4-f5 13.Kd6-d5 c2-c3 14.d7-d6 c3-c4 #
Beide Könige auf langen Märschen. Eile-mit-Weile-Abschluss des weißen Bauern, um den schwarzen e.p.-Schlag im Mattzug zu vermeiden. Mustermatt. Kindergarten-Problem (ausschließlich Könige und Bauern auf dem Brett) - author
Длинные марш-броски обоих королей, аннигиляция пешек d5/c3, двойная игра пешки c2 чтобы избежать взятия на проходе. Правильный мат. Детсадовская задача: только короли и пешки (автор)
E663
white Pc2b3 Kf3 Re6
black Pd6b6 Kd5 Bc5
h#2 see text (4+4)
E664
white Bf4 Kc5 Qg8 Pd2f3d3c3 Sc1 Rf1b3
black Ba3 Kc2 Qg1 Pb4d5c7 Sg3d4 Rf5e5
h#2 3.1.. (10+10)
E665
white Pb3 Kg2 Rb1 Bf1
black Pb4e4d5c5c7g7 Ke8 Ra8h8 Sa6e5 Bg6
h#3 2.1.. (4+12)
E663 8/8/1p1pR3/2bk4/8/1P3K2/2P5/8
a) {diagram} 1.Kd5-d4 Re6-e3 2.d6-d5 c2-c3 # {,
Bukovina maneuver - the movement of at least two white and/or black pieces on at least three different squares and their return to original positions. In my problem the bKd5 moves to d4, c5 and return on d5. The wRe6 moves to e3,e4 and return on e6 (author)
E664 6Q1/2p5/8/2Kprr2/1p1n1B2/bRPP1Pn1/2kP4/2N2Rq1
1.Sd4*b3 + Kc5-c6 2.d5-d4 Qg8*b3 # {,} 1.Ba3*c1 Qg8-b8 2.b4*c3 Rb3*c3 # {,} 1.Sg3*f1 Qg8-g2 2.Sf1*d2 Qg2*d2 #
Two flights-giving key moves by capturing of white pieces (author)
Пассивные жертвы белых фигур с предоставлением двух полей свободы чёрному королю (автор)
Compare to | Сравните с:
yacpdb/413178 (director)
E665 r3k2r/2p3p1/n5b1/2ppn3/1p2p3/1P6/6K1/1R3B2
1.0-0-0 Rb1-a1 2.Sa6-b8 Ra1-a8 3.Se5-d7 Bf1-a6 # {,} 1.0-0 Bf1-d3 2.Kg8-h7 Bd3*e4 3.Rf8-g8 Rb1-h1 #
E666
white Ph6d7 Kd8 Rf5
black Be8 Ke6 Qg3 Pd6h7g7 Sc7g6 Rg8
h#2 see text (4+9)
E667
white Kh4 Se4
black Qa5 Pd5h5c3a4 Kf5 Re7d3 Ba1
h#4 3.1.. (2+9)
E668 M. Dragoun,
white Qf2 Ph3g5g6e6b5b3 Sd6 Bf7 Kc4
black Ke5 Ph4g7g4g2d4c5b6 Sf1c7 Rg3 Bh7g1
h#2 4.1.. (10+13)
E666 3Kb1r1/2nP2pp/3pk1nP/5R2/8/6q1/8/8
a) {diagramm} 1.g7*h6 d7*e8=S 2.Rg8-g7 Se8*g7 # {,
White selfpinning through AUW followed by black thematic (TT 214) unpinnings. a) & b): 1. Rf8? 2. Rf6?? 3. Kf7! bQ controls g7 in a) & b): 1. Rh8 dxe8=S 2. Sf8 Sxg7+, as well as d6 in c): 1. Kf7 dxe8=S 2. Sf8 Sxd6+ (author)
E667 8/4r3/8/q2p1k1p/p3N2K/2pr4/8/b7
1.Kf5-g6 Se4*c3 2.Kg6-h7 Sc3-e4 3.Ba1-h8 Kh4*h5 4.Re7-g7 Se4-f6 # {,}
1.Rd3-g3 Se4-d2 2.Rg3-g4 + Kh4-h3 3.Kf5-g5 Kh3-h2 4.Kg5-h4 Sd2-f3 # {,}
1.Kf5-e5 Kh4-g5 2.Ke5-d4 Kg5-f4 3.Re7-c7 Se4-g5 4.Rc7-c4 Sg5-e6 #
E668 8/2n2Bpb/1p1NP1P1/1Pp1k1P1/2Kp2pp/1P4rP/5Qp1/5nb1
1.Rg3-d3 Kc4*d3 2.Sc7-d5 Sd6-c4 # {,} 1.Bh7*g6 Bf7*g6 2.Sc7*e6 Sd6-f7 # {,
E669
white Pe2e3 Kf7 Se6b7
black Pd5f5 Ke4 Be5
h#2 2.1.. (5+4)
E670
white Pf3f2 Kb5 Bb4 Sf6
black Pe5f5c7 Sc2 Rg5 Kf4
h#2 3.1.. (5+6)
E671
white Kh1 Bb7
black Qg3 Pb6 Kf2 Rb5g2
h#8.5 one solution (2+5)
E669 8/1N3K2/4N3/3pbp2/4k3/4P3/4P3/8
1.Be5-f4 Kf7-f6 2.Bf4*e3 Sb7-d6 # {,} 1.f5-f4 Kf7-g6 2.f4*e3 Sb7-c5 #
Meredith. Analogies (author)
E670 8/2p5/5N2/1K2ppr1/1B3k2/5P2/2n2P2/8
1.Sc2-e1 Bb4-c5 2.Se1*f3 Bc5-e3 # {,} 1.e5-e4 Bb4-a5 2.e4*f3 Ba5*c7 # {,} 1.Rg5-g3 Bb4-f8 2.Rg3*f3 Bf8-h6 #
Meredith. Analogies (author)
E671 8/1B6/1p6/1r6/8/6q1/5kr1/7K
1...Bb7*g2 2.Qg3-a3 {! (Qc3?)} Kh1-h2 3.Kf2-e3 Kh2-g3 4.Ke3-d4 + Kg3-f4 5.Kd4-c5 Kf4-e5 6.Kc5-b4 + Ke5-d6 7.Kb4-a5 + Kd6-c7 8.Ka5-a6 Kc7-b8 9.Qa3-a5 Bg2-b7 #
White minimal miniature, black Indian theme, delayed Umnov, long trips of both Kings, white B-Switchback with ideal mate (author)
E672
white Pd2 Kc3 Bh1
black Bh5 Ke4 Qa8 Ph3g2a5a6 Sg4b8 Rh2
h#5 2.1.. (3+10)
E673
white Kc1 Re6d8 Bc6b8
black Bg3 Ke4 Qe8 Pf6f5f3d7 Se5d5 Rd2
h#2 b) Pf3->e3 (5+10)
E674
white Pd3f4 Kh1 Be6 Sc4g6 Rb7
black Pe2g3h6f6 Kf3 Bf2g8 Sa5h8
h#2 3.1.. (7+9)
E672
1.Sb8-d7 Kc3-b2 2.Ke4-d3 Kb2-c1 3.g2-g1=B Bh1-b7 4.Bg1-d4 Bb7-c8 5.Qa8-e4 Bc8*a6 # {,
“Качели” белого слона относительно полей g2 и b7. В первом решении пешка g2 вскрывает линию для белого слона, а тот в свою очередь для черного ферзя. Во втором решении конь g4 вскрывает линию для черного слона, а белый слон для черной ладьи (author)
E673 1B1Rq3/3p4/2B1Rp2/3nnp2/4k3/5pb1/3r4/2K5
a) 1.d7*c6 Bb8*e5 2.Sd5-e7 Be5*g3 # {,}
b) bPf3-->e3 1.d7*e6 Rd8*d5 2.Se5-d7 Rd5*d2 #
E674 6bn/1R6/4BpNp/n7/2N2P2/3P1kp1/4pb2/7K
1.Sa5*c4 Rb7-b4 2.Sc4-e3 Sg6-h4 # {,} 1.Bg8*e6 Rb7-e7 2.Be6-g4 Sc4-d2 # {,} 1.Sh8*g6 Rb7-g7 2.Sg6*f4 Be6-g4 #
Ambush, cyclic Zilahi, Nagnibida theme. Indirect battery cycle of square e3, f4, g4: control/self-block (author)
Compare to | сравните с:
P1094081 (director)
E675
white Kb5 Rc8
black Sb4 Pb3d6g7e7 Bg4 Rb2c6 Ke4
h#4 3.1.. (2+9)
E676
white Ph3f2b4b3 Sf5f4 Rc3 Ka6
black Be4a1 Ke5 Qb8 Pg5e7 Se3h4 Rd5e1
h#2 8.1.. (8+10)
E677
white Pe5b4 Bg6 Rg5 Ka1
black Pc2c4 Kd5 Bh3 Rh5
h#3 3.1.. (5+5)
E675 2R5/4p1p1/2rp4/1K6/1n2k1b1/1p6/1r6/8
1.Rb2-d2 Rc8-b8 2.Sb4-c2 Kb5*c6 3.Ke4-d3 Kc6-d5 4.Bg4-e2 Rb8*b3 # {,
Three echo model mates (authors)
Compare to | сравните с:
P1005379 (director)
E676 1q6/4p3/K7/3rkNp1/1P2bN1n/1PR1n2P/5P2/b3r3
{} 1.Ke5*f4 { } Sf5*h4 2.Se3-f5 Sh4-g6 # {,} 1.Sh4*f5 Rc3-c6 2.Ba1-d4 Sf4-g6 # {,} 2.Ke5-d4 { } Se7-c6 # {,} 1.Ke5*f5 Rc3-c7 2.e7-e5 Rc7-f7 # {,} 1.Ke5-f6 { } Rc3-c8 2.Qb8-e5 Rc8-f8 # {,} 1.Rd5-d7 Sf5-h6 {} 2.Ke5-d6 { } Sh6-f7 # {,
HOTF 4x2. 1st pair: Zilahi (S-S) + mates on the same square. 2nd pair: Zilahi (R-Sf5). 3rd pair: self-blocks + double play by mating pieces. 4th pair: self-blocks + echo mates. Full BK star - including initial BK's position in the 2nd solution (author)
E677 8/8/6B1/3kP1Rr/1Pp5/7b/2p5/K7
1.Bh3-e6 {(a)} Rg5-g4 2.Rh5-h4 {(b)} Rg4*c4 3.Rh4-d4 {(c)} Rc4-c5 # {,} 1.Rh5-h4 {(b)} Bg6-f5 2.Rh4-d4 {(c)} Bf5-c8 3.Bh3-e6 {(a)} Bc8-b7 # {,
Organized disharmony 2+1 with model mates (author)
Compare to | сравните с:
yacpdb/98309 (director)
E678
white Qh1 Pg3a3 Rh5a5 Bf2 Ka7
black Bh4c6 Kd6 Qd4 Pb6d2f3g2 Sd5 Rb1e6
h#2 b) Bf2->a1 (7+11)
E679
white Rf5h4 Bf6g8 Kh8
black Qh2 Pb2d2d5b5 Kc4 Bd4 Re7
h#2 b) black Rd5 (5+8)
E680
white Pf5d6 Sg4e4 Bd8 Kb5
black Pb4d7 Kf3 Rf4
h#3 2.1.. (6+4)
E678 8/K7/1pbkr3/R2n3R/3q3b/P4pP1/3p1Bp1/1r5Q
a) 1.Rb1-b5 Qh1-b1 2.Kd6-c5 Qb1-b4 # {,}
b) wBf2-->a1 1.Bh4-g5 Qh1-h4 2.Kd6-e5 Qh4-f4 #
Compare to | сравните с:
yacpdb/352630 , P1071747 (director) (director)
E679 6BK/4r3/5B2/1p1p1R2/2kb3R/8/1p1p3q/8
a) 1.Kc4-c3 Bg8-h7 2.Bd4-e5 Rf5-f3 # {,}
b) + bRd5 1.Kc4-c5 Rh4-h6 2.Rd5-e5 Bf6*e7 #
E680 3B4/3p4/3P4/1K3P2/1p2NrN1/5k2/8/8
1.Kf3*e4 Bd8-h4 2.Ke4-d5 Bh4-g3 3.Rf4-d4 Sg4-f6 # {,} 1.Kf3*g4 Bd8-b6 2.Kg4-h5 Bb6-e3 3.Rf4-h4 Se4-f6 #
Zilahi theme with ambush play by WB and model mates. Gravure (authors)
E681
white Ph5c3d2 Kg6 Bh1
black Pe5h6 Rd5 Bc5g2 Ke4
h#3 2.1.. (5+6)
E682
white Pg3f3c2b2b3 Kh5 Be3 Sb6
black Pc5c6e6h7h6g4 Ke5 Rd7 Sf5f2
h#2 4.1.. (8+10)
E683
white Qa5 Pb6h2g2d2 Kg1 Rd1
black Qb3 Pg6b7d6c3e3f3h4h3 Sf6e6 Bd5a1 Ke5
h#2 see text (7+14)
E681 8/8/6Kp/2brp2P/4k3/2P5/3P2b1/7B
1.Bg2-f3 Bh1-g2 2.Bc5-e3 Bg2-h3 3.Be3-f4 Bh3-f5 # {,} 1.Rd5-d6 + Kg6-f7 2.Ke4-d5 d2-d3 3.Bg2-e4 Bh1*e4 #
E682 8/3r3p/1Np1p2p/2p1kn1K/6p1/1P2BPP1/1PP2n2/8
1.Sf2-d3 Be3-f4 + {(C)} 2.Ke5-d4 c2-c3 # {(B),} 1.Rd7-d6 Sb6-d7 + {(C)} 2.Ke5-d5 c2-c4 # {(D),}
1.Rd7-f7 c2-c3 {(B)} 2.Rf7-f6 Be3-f4 # {(A),} 1.Sf2-e4 c2-c4 {(D)} 2.Se4-d6 Sb6*d7 # {(C)}
E683 8/1p6/1P1pnnp1/Q2bk3/7p/1qp1pp1p/3P2PP/b2R2K1
a) {diagram} 1.Ke5-d4 {} g2*f3 { } 2.Bd5-c4 { } d2*c3 # {} g2-g4 { } 2.Bd5-e6 { } d2-d4 # {} g2*h3 { } 2.Bd5-e4 { } d2*e3 # {} g2-g3 { } 2.Bd5-c6 { } d2-d3 #
Very sophisticated idia of three patterns combination: double Albino with sinergic play of white pawns and BB star. Each pattern occurs in particular move order (director)
E684
white Qa1 Pb4c3d4f4f7 Kf8
black Bb6a2 Kf6 Qa6 Pf5h3f3e2a3b2 Sg2 Rg1b3
h#2 3.1.. (7+13)
E685
white Kh7 Rb7 Sc2d2
black Ba8a1 Kd1 Qa6 Pe5d4c4a2 Sf3 Rb8a7
h#3 3.1.. (4+11)
E686
white Qa4 Pd4c3b2 Bg2 Re8h4 Ka1
black Bg1c8 Ke4 Qf4 Pf5h3f6d7c6c2b6 Se5f3
h#2 b) Pd4->c4 (8+15)
E684 5K2/5P2/qb3k2/5p2/1P1P1P2/prP2p1p/bp2p1n1/Q5r1
1.Rb3*c3 Qa1-c1 2.Rc3-b3 Qc1-c6 # {,} 1.Bb6*d4 Qa1-d1 2.Bd4-b6 Qd1-d6 # {,} 1.Sg2*f4 Qa1-c1 2.Sf4-g2 Qc1-h6 #
Compare to | сравните с:
P0535081 , P0580112 (director)
E685 br6/rR5K/q7/4p3/2pp4/5n2/p1NN4/b2k4
1.Sf3-e1 Rb7-d7 2.Ba8-f3 Sd2-b3 {(A)} 3.Bf3-e2 Sc2-e3 # {(B),} 1.Kd1-c1 Rb7-c7 2.Rb8-b1 Sc2-e3 {(B)} 3.Ba1-b2 Sd2-b3 # {(A),} 1.Kd1-e2 Kh7-g7 {!(tempo)} 2.Ke2-d3 Sc2-e1 + 3.Kd3-c3 Sd2-e4 #
E686 2b1R3/3p4/rpp2p2/4np2/Q2Pkq1R/2Pr1n1p/1Pp3B1/K5b1
a) 1.Bg1-e3 Bg2*h3 2.Sf3*d4 Bh3-g2 # {,}
b) wPd4-->c4 1.d7-d5 Re8*c8 2.Se5*c4 Rc8-e8 #
E687
white Pc4h3 Kg1 Bh1 Rh2
black Be5 Kb3 Qc1 Pe6d7c5a3g2h4 Sg3d1 Re3
h#3.5 2 solutions (5+12)
E688
white Kc6 Pg4c2 Sh3 Rf8 Bg5
black Pf4f3f2e5e2c7a6 Re4d2 Be3 Kd4
h#2.5 3 solutions (6+11)
E689 ANTICIPATED
white Kh1 Sd1
black Rf6f2 Kd7 Be6f4
h#6 4.1.. (2+5)
E687 8/3p4/4p3/2p1b3/2P4p/pk2r1nP/6pR/2qn2KB
1...Rh2*g2 2.Kb3*c4 Kg1-h2 {! (tempo)} 3.Kc4-d5 Kh2-g1 {! (tempo)} 4.Qc1-c4 Rg2-d2 # {,}
1...Bh1*g2 2.Kb3-c2 Rh2-h1 {! (tempo)} 3.Re3-b3 Rh1-h2 4.Be5-c3 Bg2-e4 #
E688 5R2/2p5/p1K5/4p1B1/3krpP1/4bp1N/2Prpp2/8
1...Rf8*f4 {!} 2.Be3*f4 {!} Bg5-h4 3.Kd4-e3 Bh4*f2 # {,}
1...Bg5*f4 {!} 2.Re4*f4 {!} Rf8-d8 + 3.Kd4-e4 Sh3-g5 # {,}
1...Sh3*f4 {!} 2.e5*f4 {!} c2-c3 + 3.Kd4-e5 Rf8-e8 #
Cyclic Zilahi, sacrifices of white pieces on same square f4, FML-effect in the Black play (author)
E689 8/3k4/4br2/8/5b2/8/5r2/3N3K ANTICIPATED
1.Bf4-d6 Kh1-g1 2.Rf2-f5 Sd1-f2 3.Be6-d5 Kg1-f1 4.Kd7-e6 Kf1-e2 5.Ke6-e5 Ke2-e3 6.Rf6-e6 Sf2-g4 # {
The problem is completelly anticipated | У задачи имеется полный предшественник:
yacpdb/465062 (director)
E690
white Kg7 Be7
black Bb2 Ke4 Qd6 Pf3d4 Sf6 Re6
h#5 2.1.. (2+7)
E691
white Ka3 Bg1
black Kc5 Pc4b5 Bf3 Rf2 Se4
h#4.5 one solution (2+6)
E692
white Qa6 Pd3 Ka8 Rf3
black Bh1 Ke1 Qb2 Pc5 Sc2d6 Ra2d7
h#2 2.1.. (4+8)
E690 8/4B1K1/3qrn2/8/3pk3/5p2/1b6/8
1.Sf6-g4 Be7-f6 2.Qd6-g3 Bf6*d4 3.Ke4-f4 Bd4-f6 4.Re6-e4 Kg7-g6 5.Bb2-e5 Bf6-g5 # {,
Multiple "topological effects" Множественные "топологические эффекты" (director)
E691 8/8/8/1pk5/2p1n3/K4b2/5r2/6B1
1...Bg1-h2 2.Rf2-d2 Bh2-b8 {!(tempo)} 3.Se4-d6 Bb8-c7 {! (tempo)} 4.Bf3-c6 Bc7-b8 5.Rd2-d5 Bb8-a7 #
E692 K7/3r4/Q2n4/2p5/8/3P1R2/rqn5/4k2b
1.Sc2-a3 d3-d4 2.Qb2-d2 Qa6-f1 # {,} 1.Sd6-e4 d3*e4 2.Rd7-d2 Rf3-f1 #
Unpinnig, opening line by WP – d4 and dxe4, twofold self-blocks on d2 by different black pieces and mates by different white pieces on the same square in Meredith position (authors)
E693
white Pc5 Kg2 Sf2
black Bg4 Kf4 Qe3 Pc4 Sf5f3 Re4
h#3 2.1.. (3+7)
E694
white Pe4 Rc7 Bh1 Kc8
black Pa3a5b5d3d7 Sb1b8 Ra1c6 Kb3
h#3 2.1.. (4+10)
E695
white Ra8 Kb2 Bf1
black Qc7 Pg4e4c5e6b6 Kc6 Re3d3
h#2.5 see text (3+9)
E693 8/8/8/2P2n2/2p1rkb1/4qn2/5NK1/8
1.Re4-d4 Sf2-e4 2.Sf3-e5 Se4-g5 3.Rd4-e4 Sg5-e6 # {,} 1.Bg4-h5 Sf2-g4 2.Sf3-g5 Sg4-e5 3.Bh5-g4 Se5-g6 #
Compare to | Сравните с:
yacpdb/384405 (director)
E694 1nK5/2Rp4/2r5/pp6/4P3/pk1p4/8/rn5B
1.Rc6-c2 e4-e5 2.Rc2-b2 Rc7-c2 3.Kb3-a2 Bh1-d5 # {,} 1.Rc6-c4 Bh1-f3 2.Rc4-b4 Rc7-c4 3.Kb3-a4 Bf3-d1 #
Compare to | Сравните с:
P1352373 (director)
E695 R7/2q5/1pk1p3/2p5/4p1p1/3rr3/1K6/5B2
a) {diagram } 1...Ra8-e8 2.Rd3-d7 Bf1-c4 {(A)} 3.Kc6-d6 { } Re8*e6 # {(B),} 3.Kc6-c7 { } Ra8-c8 # {(C),} 3.Kc6-b6 { } Ra8-a6 # {(D),} 3.Kc6-c5 { } Ra4-c4 # {(A)}
Cyclically changed squares on which BB & BR play on mating moves c4e6-e6c8-c8a6-a6c4. Probably, this feature is rendered for the first time. HOTF: a+d & b+c. BK cross is performed exactly on B3. 4 model echo mates. Meredith (author)
Циклическое чередование матовых полей, на которые играют белые слон и ладья: c4e6-e6c8-c8a6-a6c4 (возможно впервые). HOTF: a+d & b+c. Крестик черного короля на 3-м ходу. 4 правильных эхо-мата. Мередит (автор)
E696
white Kb7 Re3
black Ba1 Kd5 Qh2 Pc3b4c4e7e6g3 Sa8 Rh5d1
h#3 3.1.. (2+12)
E697
white Kh1 Sg8
black Rg4e4 Bd1f4 Kc7
h#6.5* set play (2+5)
E698
white Pe2 Kc8 Bg1a2 Ra6
black Ke5 Sc6c4
h#2 2.1.. (5+3)
E696 n7/1K2p3/4p3/3k3r/1pp5/2p1R1p1/7q/b2r4
1.Kd5-c5 Re3*c3 2.Rd1-d6 Rc3-a3 3.Ba1-d4 Ra3-a5 # {,} 1.Kd5-d6 Re3*g3 2.Rh5-c5 Rg3-g8 3.Qh2-e5 Rg8-d8 #
E697 6N1/2k5/8/8/4rbr1/8/8/3b3K
2.Rg4-h4 + Kh1-g2 3.Bd1-f3 + Kg2*f3 4.Kc7-c8 Kf3*e4 5.Bf4-b8 + Ke4-d5 6.Rh4-d4 + Kd5-c6 7.Rd4-d8 Sg8-e7 # {,
E698 2K5/8/R1n5/4k3/2n5/8/B3P3/6B1
1.Ke5-d5 Ba2-b1 2.Sc6-e5 {display-departure-rank} e2-e4 # {,} 1.Ke5-d6 Ra6-a5 2.Sc4-e5 {display-departure-rank} Bg1-c5 #
Compare to | Сравните с:
yacpdb/377339 (director)
E699
white Pe4 Kb7 Bc8 Sh8
black Bg4 Kh5 Qg6 Pf7g5f4 Sg3f6 Rg7h4
h#3 2.1.. (4+10)
E700
white Pf2f4 Kc1 Be2d6 Sa5e6
black Qd3 Pc5d7 Ke4 Sb5
h#2 3.1.. (7+5)
E701
white Sd1b2 Bf7 Kd7
black Pf2e4d5d3b4a6a5 Sg1c8 Be3c2 Kd4 Rf4c4
h#2.5 3 solutions (4+14)
E699 2B4N/1K3pr1/5nq1/6pk/4Ppbr/6n1/8/8
1.Bg4-h3 Bc8-g4 +{(A)} 2.Kh5*g4 Sh8*g6 {(B)} 3.Sf6-h5 {display-departure-file} Sg6-e5 # {,} 1.Qg6-h6 Sh8-g6 {(B)} 2.Kh5*g6 Bc8*g4 {(A)} 3.Sg3-h5 {display-departure-file} Bg4-f5 #
A combination of Zilahi and Chumakov themes. B-W and B-B FML effect. Reciprocally changed W1/W2. Model mates (author)
Синтез тем Зилахи и Чумакова. Черно-белый и черно-черный "ушел-пришел". Чередование 1-го и 2-го ходов белых. Правильные маты (автор)
Compare to | Сравните с:
P1087577 (director)
E700 8/3p4/3BN3/Nnp5/4kP2/3q4/4BP2/2K5
1.Qd3*e2 Bd6-e5 2.Ke4-d3 Se6*c5 # {,} 1.d7*e6 Be2-f3 + 2.Ke4-d4 Bd6-e5 # {,} 1.Qd3*d6 f2-f3 + 2.Ke4-d5 Be2-c4 #
Cyclic Zilahi where black King goes to d3-d5 (authors)
E701 2n5/3K1B2/p7/p2p4/1prkpr2/3pb3/1Nb2p2/3N2n1
1...Bf7*d5 {(A)} 2.Kd4*d5 Sb2*d3 {} 3.Rc4-d4 { } Sd1*e3 # {(B),} 3.d5-d4 { } Sb2*c4 # {(C),} 3.Be3-d4 { } Bf7*d5 # {(A)}
Cycle of the first and third white moves, cyclic Zilahi, self-block of d4 by remaining thematic black piece (other two being captured), model mates (author)
E702
white Rf5 Kh4 Bf1 Se3d5
black Qe6 Pf2d2c3d4g6c7c6 Ke4 Rd1
h#2 4.1.. (5+10)
E703
white Pe3e4d4g6 Kf2
black Pd3c4 Sc3 Bf5 Ke6 Rd5f8
h#2.5 b) wSg6, c) wBg6 (5+7)
E704
white Kb5 Rd1 Bc8
black Qe7 Pe2g3c3 Sg1 Ba8 Kf4
h#3 5.1.. (3+7)
E702 8/2p5/2p1q1p1/3N1R2/3pk2K/2p1N3/3p1p2/3r1B2
1.Rd1*f1 Rf5-e5 + {(A)} 2.Ke4-d3 Sd5-f4 # {(B),} 1.d4*e3 Sd5-f4 {(B)} 2.Ke4-f3 Bf1-g2 # {(C),
A combination of the white moves cycle with fourfold cyclic Zilahi is implemented with model mates for the first time (author)
Синтез четырехфазного циклического Зилахи и циклического чередования ходов белых впервые представлен с правильными матами (автор)
E703 5r2/8/4k1P1/3r1b2/2pPP3/2npP3/5K2/8
a) 1...g6-g7 2.Rd5-d7 g7*f8=Q 3.Sc3-d5 e4*f5 # {,}
b) + wSg6 1...Kf2-f3 2.Rd5-d6 e4*f5 + 3.Ke6-d5 Sg6-e7 # {,}
c) + wBg6 1...e4*d5 + 2.Ke6*d5 Bg6-h5 3.Kd5-e4 Bh5-f3 #
E704 b1B5/4q3/8/1K6/5k2/2p3p1/4p3/3R2n1
1.Kf4-f3 Rd1-d5 2.Kf3-g2 Bc8-b7 3.Kg2-h1 Rd5-h5 # {,} 1.Qe7-e3 Rd1-d8 2.Kf4-e4 Bc8-d7 3.Ke4-d3 Bd7-f5 # {
E705
white Kc6 Ra6 Ba7
black Pb4a4b5b6 Kh1 Bd6
h#4 2.1.. (3+6)
E706
white Kh1 Rg4
black Pa5 Sd5 Rf2 Kb6
h#5.5 b) wBg4 (2+4)
E707
white Pb3c3 Sd5 Rf2 Ke3
black Pe4 Ka8 Rb7
h#2 b), c), d) BK->h8, h1, a1 (5+3)
E705 8/B7/RpKb4/1p6/pp6/8/8/7k
1.a4-a3 Ba7-b8 2.a3-a2 Bb8*d6 3.a2-a1=R Ra6-a2 4.Ra1-g1 Ra2-h2 # {,}
1.b4-b3 Kc6-d5 2.Bd6-a3 {! (B~?)} Kd5-e4 3.b5-b4 Ke4-f3 4.b6-b5 Ra6-h6 #
E706 8/8/1k6/p2n4/6R1/8/5r2/7K
a) 1...Rg4-g7 2.Rf2-f4 Kh1-g2 3.Rf4-a4 Kg2-f3 4.Sd5-b4 Kf3-e4 5.Sb4-a6 + Ke4-d5 6.Kb6-b5 Rg7-b7 # {
E707 k7/1r6/8/3N4/4p3/1PP1K3/5R2/8
a) 1.Ka8-a7 c3-c4 2.Ka7-a6 Rf2-a2 # {,}
b) bKa8-->h8 1.Rb7-g7 Sd5-e7 2.Kh8-h7 Rf2-h2 # {,}
c) bKa8-->h1 1.Rb7-h7 Sd5-f4 2.Rh7-h2 Rf2-f1 # {,}
d) bKa8-->a1 1.Rb7*b3 Sd5-b4 2.Rb3-b1 Rf2-a2 #
Corner twins and model mates (author)
Угловые близнецы с правильными матами (автор)
E708
white Pb2e2 Ka3 Bb7 Sf4
black Ke5
h#2.5 b) Bb7->a7 (5+1)
E709
white Pg2d2 Sa5 Bf8 Kh3
black Ka8
h#5 one solution (5+1)
E710
white Ka8 Bb7
black Qc7 Rb4a5 Ke2 Be4 Sa6
h#7.5 one solution (2+6)
E708 8/1B6/8/4k3/5N2/K7/1P2P3/8
a) 1...e2-e4 2.Ke5-d4 Sf4-e6 + 3.Kd4-c4 Bb7-a6 # {,}
b) wBb7-->a7 1...Sf4-g2 2.Ke5-d5 Ka3-a4 3.Kd5-c4 Sg2-e3 #
Ideal mates on the same square after different play in twins (author)
После разнородной игры черный король получает идеальные зеркальные маты на одном поле (автор)
E709 k4B2/8/8/N7/8/7K/3P2P1/8
1.Ka8-b8 Bf8-a3 2.Kb8-c7 Ba3-c1 {!} 3.Kc7-d6 Sa5-b7 + {(Sc4+?)} 4.Kd6-e5 Sb7-d6 5.Ke5-f4 d2-d4 #
Ideal mirror battery mate (author)
Идеальнй зеркальный батарейный мат (автор)
E710 K7/1Bq5/n7/r7/1r2b3/8/4k3/8
1...Bb7-d5 {! (Bc6/Ka7?)} 2.Ke2-d3 Bd5-c6 3.Kd3-c4 Bc6-b7 4.Kc4-b5 Ka8-a7 5.Qc7-c4 Bb7-a8 6.Sa6-c5 + Ka7-b8 7.Be4-b7 Kb8-c7 8.Bb7-a6 Ba8-c6 #
Step-by-step Bristol (author)
Пошаговый Бристоль (автор)
E711
white Pe3e5c2 Kd8 Bd3 Sd1f1
black Pe2f4f5e6b6c6a6 Kf3 Bc8 Sa8
h#3 b),c)Kd8->b4,a3 d)Pc2->d6 (7+10)
E712
white Sg2a8 Kc6
black Ke5 Bh1f6
h#4 3.1.. (3+3)
E713
white Kg2 Bb8
black Pc7 Kf7 Rb3c6
h#12.5 one solution (2+4)
E711 n1bK4/8/ppp1p3/4Pp2/5p2/3BPk2/2P1p3/3N1N2
a) 1.e2-e1=S Kd8-e7 2.Se1*d3 Ke7-d6 3.Kf3-e4 Sf1-d2 # {,}
b) wKd8-->b4 1.e2*f1=R Sd1-b2 2.Kf3*e3 Kb4-c3 3.Rf1-f3 Sb2-d1 # {,
A combination of cyclic Zilahi paradox with black AUW (author)
Синтез чёрного AUW и парадокса циклического Зилахи (автор)
E712 N7/8/2K2b2/4k3/8/8/6N1/7b
1.Ke5-d4 Kc6-d7 2.Bf6-e5 Sg2-f4 3.Bh1-e4 Sf4-e6 + 4.Kd4-d5 Sa8-b6 # {,
Ideal echo mates on different squares in the center of chessboard, including chameleon echo (author)
Идеальные эхоматы в центре - на разных полях, в т.ч. хамелеонные (автор)
Compare to | сравните с:
P0576436 ,
yacpdb/360516 (director)
E713 1B6/2p2k2/2r5/8/8/1r6/6K1/8
1...Bb8-a7 2.Kf7-e6 Ba7-e3 3.Ke6-d5 Kg2-f3 4.Kd5-c4 Kf3-e4 5.Kc4-c3 Ke4-d5 6.Kc3-b2 Kd5*c6 7.Kb2-a1 Kc6-d5 8.c7-c5 Be3-c1 9.c5-c4 Bc1-a3 10.c4-c3 Kd5-c4 11.c3-c2 Kc4*b3 12.c2-c1=S + Kb3-c2 13.Sc1-a2 Ba3-b2 #
King-cleaner. Excelsior. Ideal mate (author)
Король-чистильщик. Эксцельсиор. Идеальный мат (автор)
E714
h# (0+0)
E715
h# (0+0)
E716
h# (0+0)
E714
E715
E716
Vitaly Medintsev
H # 2 - Menachem Witztum
H # 2.5 & 3 - Anatoly Stepochkin
H # 3.5 - N - Boris Shorokhov
