Award in SuperProblem  2018 Informal Tourney  Fairies
Итоги годового конкурса SuperProblem  2018  Сказочные задачи
Published: January 03, 2019Опубликовано: 03 января 2019
63 problems were published in the SuperProblem InformalTournament. Below were 21 miniatures, which I judged separately.
To deal with the problems gave me a lot of joy, there were absolute top problems and also smaller
ones, just mixed as it should be. It should be known, that I attach great importance to harmony
between the solutions and analogous play. Furthermore, cycle problems are very appealing to me. If
this is succeeded in an acceptable construction and a reasonably original idea is presented, a front
placement is guaranteed. I hope very much that I will do justice to the authors with my judgment. If
not, have mercy on me. Nobody should forget that an award requires a lot of time and attention and
you do not get any money for it.
Before I come to my ranking, a few comments on problems that did not make it into the award:
G140 Stepochkin: Without the bGa1, which disturbs the fairy piece economy, a commendation
would have been possible, for example see Appendix, A.
G146 Tominic: Shows the theme of the 184th TT of Super Problem in triplicate. Weaknesses are the
bCamel and the bPao, they only prevent cooks. The solutions are not completely analogous. Pity
about the problem.
G156 Zheglov: Still five Echoes, but too many repetitions, especially in IV) and V).
G161 Stun: These six echoes are too stereotypical, the solutions seem a bit boring.
G169 Novomesky: For the triple chameleonecho with a wP and two pieces of the Lionfamily, there
is something similar from the author (see Appendix, B).
G179 Nefyodov: Dual mates in the HS# are not a new idea, the problem does not offer much
anyway.
G192 Kochulov: Unfortunately, there are uninvolved officers in both mating positions. Two white in
the first and one black in the second one. Furthermore in the second solution there is no equivalent to
3.nTxe1 [+nTh8]? in the 1st solution.
G195 Stephenson: Dual avoiding single and double step of the bP. Unfortunately, Black no longer
has any defence on the threatening mate.
G198 Smotrov: Symmetry is too intrusive in this serieshelpmate.
Here is my ranking. I have decided to split the top price in Main Subsection. A second prize would not do justice to any of these
two outstanding problems.
Subsection "Miniatures"  Подраздел "Миниатюры"
Prize  G159 Jaroslav Štúň SuperProblem, 16052018 

8/1(Q1)N5/1k(q1)5/8/8/4K3/8/8 
serh#11  2 sol. Madrasi + PWC
b7, c6: Locust (L)  (3+2) 

1st Honourable Mention  G162 Dieter Müller SuperProblem, 17052018 

8/8/5B2/4(q1)3/3RP3/5K2/8/8 
hs#6  3 sol Parrain Circe
e5: Locust (L)  (4+1) 

2nd Honourable Mention  G160 Jaroslav Štúň SuperProblem, 16052018 

8/8/8/8/8/5p2/6P1/7k 
h#9  Einstein Chess+ PWC  (1+2) 

Prize  G159 Jaroslav Štúň (Slovakia)
1.Kxc7[+wSb6] 2.Kxb7[+wLc7] 3.Ka6 4.Kb5 5.Kxb6[+wSb5] 6.Kc5 7.Lxb5a4[+wSc6] 8.Kxc6[+wSc5] 9.Kxc7[+wLc6] 10.Kd6 11.Kd5 Sd7#
1.Kxb7[+wLb6] 2.Kc8 3.Kd7 4.Kd6 5.Kc5 6.Kxb6[+wLc5] 7.Kb7 8.Kxc7[+wSb7] 9.Lxb7a8[+wSc6] 10.Kxc6[+wSc7] 11.Kxc5[+wLc6] Sd5#
A enchanting problem with five men and roundtrip of the bK in
both solutions. PWC and Madrasi come into their own in the
consistently exciting solutions with dualavoiding matingmoves. A
little gemstone.
1st Honourable Mention  G162 Dieter Müller (Germany)
1.Ke2 Lxe4e3+ 2.Kf1[+wPf3] Lxf3g3 3.Rc4[+wPe3] Lxe3d3 4.Bd4[+wPc1] Lxc4b5 5.Bb2[+wRa2] Lxb2b1 6.Rf2[+wBg2] Lxc1d1#
1.Rd6 Lxd6c7 2.Ke2[+wRc5] Lxc5c4+ 3.Kd1[+wRb4] Lxb4a4 4.Bh8[+wRd6] Lxe4f4 5.Bf6[+wPc2] Lxf6f7 6.Rd2[+wBf2] Lxf2f1#
1.Bd8 Lxd4c3+ 2.Kg4[+wRe5] Lxe5f6 3.Kh3[+wRf4] Lxf4f3 4.Bc7[+wRe3] Lxe4d5 5.Be5[+wPg2] Lxe5f5 6.Rg3[+wBg5] Lxg5h5#
An HS#6 with three Echoes and no repetitions (for me, 1.Ke2 and
1.Ke2 [+ wRc5] are different), that's remarkable. The black locust
shifts the white pieces to the block until forced to mate the white
king. If the locust had captured all three white pieces on the
mating move, a prize would have been possible.
2nd Honourable Mention  G160 Jaroslav Štúň (Slovakia)
1.fxg2=S[+wPf3] f4 2.Sxf4=B[+wPg2] g3 3.Kg1 gxf4=S[+bBg3] 4.Bf2=S Sg2=P 5.Kxg2[+wPg1] g1xf2=S[+bSg1] 6.Sh3=P Sh1=P+ 7.Kxh1[+wPg2] gxh3=S[+bPg2] 8.g1 Sxg1=B[+bPh3] 9.h2 Bxh2=R[+bPg1]#
It takes until the 7th move before the bP comes after many
changes of place and transformations to h3. Only then can the
mate final be started with a black blocking pawn on g1. Quite rich
for a threeman problem.
3rd Honourable Mention  G155 Viktor Zheglov SuperProblem, 10042018 

8/1R5r/3K3r/8/8/7R/6k1/8 
hs#9  4 sol. Functionary Chess  (3+3) 

Commendation  G149 Anatoly Stepochkin SuperProblem, 16022018 

8/8/8/3k4/8/8/B4pK1/4R3 
h#3  b) wRe1>g4 c)Kg2>g6; d)Ba2>a6 KöKo  (3+2) 

Commendation  G193 Marko Klasinc SuperProblem, 27092018 

8/3k4/5n2/1(q2)1(!p)1(!q2)2/8/8/8/5K2 
h#5  b) nPd5>g5 Circe
b5, f5: Grasshopper (G)  (1+3+2) 

3rd Honourable Mention  G155 Viktor Zheglov (Russia)
I) 1.Kc7 Rb6 2.Rg3+ Kf2 3.Rg2+ Ke2 4.Kb8 Kd3 5.Rd7+ Kc4 6.Ka8 Rg7 7.Rg4+ Kb5 8.Rb4+ Ka6 9.Ra7+ Rxa7#
II) 1.Ke7 Ra6! 2.Ra3 Ra7 3.Ra2+ Kg3 4.Rg2+ Kg4 5.Kf7 Kg5 6.Kg8 Rg7+ 7.Kh8 Kh6 8.Rg4 Rg6 9.Rh7+ Rxh7#
III) 1.Ke5 Rh5+ 2.Kf4 Rg5 3.Rh2+ Kf1 4.Rd2! Rg8 5.Rg7 Rh4 6.Kg3 Rg4+ 7.Kh2 Rg2+ 8.Kh1 Rf2 9.Rg1+ Rxg1#
IV) 1.Kc5 Rc6+ 2.Kc4 Re7! 3.Rh2+ Kf2 4.Kc3 Ke2 5.Kb2 Kd2 6.Rb6 Rc2+ 7.Ka1 Kc1 8.Re2 Rb7 9.Rb1+ Rxb1#
Four echoes in HS#9 in all four corners (I and II as well as III and
IV mirrored, I and III as well as II and IV rotated by 90°). Since
kings in functionary chess can only move on observation, checks
are often inevitable, if only rooks are on the board. That the wK is
in check is probably unavoidable here. Let's hope that the problem
remains sound, because in this number of moves testing programs
are overwhelmed. In the PDB there was a problem showing a fourcorner echo with only three pieces, but with fairy piece and
twinning (see Appendix, C).
Commendation  G149 Anatoly Stepochkin (Russia)
a) diagram: 1.f1S Kf2 2.Sd2 Ke3 3.Ke4+ Kd4#
b) Re1>g4: 1.f1B Kf3 2.Bh3 Ke4+ 3.Kd4 Ke5#
c) Kg2>g6: 1.f1R Re2 2.Rf7 Kf6 3.Re7 Re6#
d) Ba2>a6: 1.f1Q Re6 2.Qf2 Kf3 3.Qc5 Ke4#
Wellfounded AUW with lively solutions. A KökoHelpmate of the
better kind.
Commendation  G193 Marko Klasinc (Slovenia)
a) diagram: 1.Sxd5[+nPd2] nGc8 2.nPd1=nQ+ nQa4 3.Sb6 nGe6 4.Kc8 nQa6+ 5.Gb7+ nGxa6[+nQd8]#
b) nPd5>g5: 1.nGc8 nGe6 2.Gh5 nPg6 3.Gf7 nPg7 4.Ke8 nPg8=nQ+ 5.nQg6 nGxg6[+nQd8]#
The commendation is for the beautiful CirceMates with double
check.
Main subsection  Основной подраздел
1st2nd Prize  G141 Michal Dragoun SuperProblem, 08012018 

2K5/(q3)p5(Q3)/2p5/p1P5/(Q3)3kN2/(q3)2NppbP/r2p3n/1b6 
h#2  6.1..
a7, a4, a3, h7: Leo (LE)  (7+13) 

1st2nd Prize  G158 Borislav Gadjanski SuperProblem, 16042018 

(q3)k6/(q3)(Q1)5(Q1)/p2(b3)pp2/P1p2p2/PPN2(r3)2/1KN1p3/2P4(B3)/4(N3)2(Q1) 
hs#4  2 sol.
a7, a8: Leo (LE) f4: Pao (PA); e1: Nao (NA) h2, d6: Vao (VA)
h1, h7, b7: Hurdle colour changing Leo
 (12+11) 

3rd Prize  G192 Lev Grolman SuperProblem, 20092018 

(n2)3(q3)b1r/P1(n2)(!n2)(!n2)qpp/1pp4(!q3)/8/4p1kP/(!q3)5r1/1(!n2)2p2p/(q3)6K 
h#2  5.1.. Take & Make Chess
e8, a1, h6, a3: Lion (LI) c7, a8, b2, e7, d7: Nightrider (N)
 (3+16+5) 

1st2nd Prize  G141 Michal Dragoun (Czech Republic)
1.LExa4 Se5 2.LEd4 Seg6#
1.LExh7 Sd5 2.LEf5 S5b4#
1.Ra1 LExa7 2.Ba2 LEc2#
1.Sf1 LEb5 2.Bh2 LEh4#
1.f2 LEc2+ 2.Kf3 LEf5#
1.e2 LEh4+ 2.Ke3 LEb3#
Everything is just right here. Perfect harmony between all three
pairs of solutions, good construction and in every solution there is
a antibatterymate by a Leo with a wS as a hurdle. Each pair would
be good enough to be published separately. A masterful 3x2 TFHelpmate at its best.
1st2nd Prize  G158 Borislav Gadjanski (Serbia)
1.hccLEb7g7 LEf7 2.hccLExf7[g7=b]! Ka7 3.Sa3 VAxb4! (VAd6~?) 4.hccLEhb7+ hccLExb7[f7=b]#
1.hccLEb7g2 LEf3 2.hccLExf3[g2=b]! Ka8 3.Sa2 PAxb4! (PAf4~?) 4.hccLE7b7+ hccLExb7[f3=b]#
The solutions can be described as follows: orthogonal Bristol move
of wLEb7 to g7, simultaneously hurdle for the wLEh7, the bLEa7
follows the wLE and moves to f7, the wLEh7 captures the bLEf7
and colours the wLEg7 black. The bK moves to the square left by
the bLE, a wS opens a diagonal antibattery line and at the same
time blocks a square. At the end of the helpplay, the bVA opens
the diagonal h2b8 for the wVA and hides on b4, so that he cannot
move to the 7th rank. The selfmate is done by recoloring the
wLEf7. The exact same strategy with exactly the same motifs is
seen in the second solution, except that the orthogonal features
are diagonal and the diagonal orthogonal ones. A monumental,
profound work that leaves nothing to be desired. Note that all fairy
pieces belong to the Chinese family.
3rd Prize  G192 Lev Grolman (Russia)
1.LIc3 nNa1+ (A) 2.Nce3 nLIxe3d1# (B)
1.b5 nLIxa8c4+ (B) 2.Qf4 nNxf4f6# (C)
1.LIg6 nNe8+ (C) 2.Qf6 nLIxf6d4# (D)
1.g5 nLIxh8g8+ (D) 2.Qg6 nNxg6h6# (E)
1.c5 nNc6+ (E) 2.LIe5 nNxe5e3# (A)
In all five solutions, there is a neutral double checkmate by
capturing a black piece from the battery line of a neutral piece. I
was quite impressed how the squares around the black king are
guarded by the neutrals with the greatest of ease. Although the
first black moves are motivated differently, nevertheless this fivefold cyclic interchange of function of the neutral pieces is a great
achievement.
4th Prize  G189 Ladislav Salai & Michal Dragoun SuperProblem, 23082018 

1(Q3)q5/7(Q3)/2pPP3/2K2(b3)p1/1(q3)4pP/2(r3)P1(b3)(b3)p/(Q3)2P2(r3)k/7b 
h#2  3.1..
g3, f5, f3: BishopLion (BL) g2, c3: RookLion (RL) b4, h7, b8, a2: Lion (LI)  (9+13) 

5th Prize  G145 Hubert Gockel SuperProblem, 21012018 

2R1BBq1/1N4pr/6Rp/1p6/kPP5/P2Q4/P7/6K1 
#2  AMU  (11+6) 

6th Prize  G196 Vitaly Medintsev SuperProblem, 22112018 

8/5K2/3p4/2p3p1/pNp1k1p1/8/q4PN1/1b2r3 
hs#4.5  2.1..  (4+10) 

4th Prize  G189 Ladislav Salai (Slovakia) & Michal Dragoun (Czech Republic)
1.BLb7 LIb6 2.LIxd2 hxg5#
1.Qa6 LIaa7 2.LIxh4 d7#
1.BLd7 LIha7 2.LIxd6 dxc3#
There are three white batteries each controlled by two black
pieces, with the bLIb4 targeting all three batteries. To guard the
square g1, a white Lion must be placed on the diagonal a7g1 by
providing a black defender as a hurdle. The bLIb4 then moves into
a selfpin. Firstclass cyclic interchange of function of white Lions.
5th Prize  G145 Hubert Gockel (Germany)
Any move of wBf8 threatens [2.Bxb5#] due to observation g8e8  Любой ход слоном f8 ведет к угрозе 2.Bxb5# изза открытия g8e8
1.Be7? Qe6!
1.Bd6? Qxe8!
1.Bc5? Qxc4!
1.Re6?  2.Ra6#, 1...Qxe6 2.Bxb5#, 1...Qh8!
1.Bxg7!  2.Bxb5#
1...Qxe8 2.Ra6# (2.Ra8+?)
1...Qxc4 2.Ra8# (2.Qb3+?)
1...Qd5 2.Qb3# (2.Sc5+?)
1...Qxg7 2.Sc5# (2.Ra6#??)
Great fourfold cycle of parries by the black queen that always
attacks two white pieces, but only allows one mate. Along with the
tries (two of them are refuted by the thematic refutations) this is
an impressive demonstration of the fairy condition AMU.
6th Prize  G196 Vitaly Medintsev (Russia)
1...Qe2 2.Sc6 (A) Kd5 3.Sh4 (B) Bh7 4.Sf3 Qe2e4! 5.Se7+ Qxe7#
1...Qc2 2.Sh4 (B) Kf4 3.Sc6 (A) Re8 4.Sd4 Qc2e4! 5.Sg6+ Qxg6#
A fleetfooted helpselfmate with freestanding wK. I was persuaded
by the spacious, analogue play and the excellent harmony of both
solutions. The fact that the bQ has to make a stopover on e4 on its
long way to the matesquare is the icing on the cake of this
composition.
1st Honourable Mention  G197 Hubert Gockel SuperProblem, 26112018 

4K3/8/2p5/N1qR2pp/4n3/2k2p1p/2pPp3/2B1Q1nr 
h#2  4.1.. Super Guards  (6+12) 

2nd Honourable Mention  G184 Menachem Witztum SuperProblem, 10082018 

8/3NBn1p/2p1kP2/1p6/1q1n2K1/2N2rPB/8/Q2b4 
hs#2.5  2 sol.  (8+9) 

3rd Honourable Mention  G186 Anatoly Stepochkin SuperProblem, 18082018 

8/8/4K3/1bp5/pkBp4/R2n4/np6/8 
h#2  2.1.. Circe  (3+8) 

1st Honourable Mention  G197 Hubert Gockel (Germany)
1.Sg3 Qf2 2.Sf1 Qxc5# (2.Sf5? ... 3.Kd4!)
1.Sf2 d4 2.Sg4 dxc5# (1...Qxf2#?? [нелегальное взятие  illegal capture] 2...Qxc5#)
1.Qf2 d3 2.Qg2 dxe4# (1...Qh4?? [невозможный ход  illegal move] 2...Qxe4#)
1.Qa7 Qh4 2.Qa8+ Qxe4# (1...d3? – 2.dxe4? не защищает от шаха  doesn't defense against a check)
SuperguardsHelpmate with TF character. It is interesting to see
how, when the black guards S and Q are switched off, the b4
square is guarded. The reciprocal attempts in the first white move
fail much more subtle in the first pair than in the second one.
2nd Honourable Mention  G184 Menachem Witztum (Israel)
1...Be2 2.Qe1 Rd3+ (Re3+?) 3.Kh4+ Sf5#
1...Qc4 2.Qa2 Sc2+ (Sb3+?) 3.Kh5+ Rf5#
On the wK two batteries are addressed. One is switched off by
pinning, the other gives mate after three consecutive checks. Nice
dual avoidance at the first check. The version of V. Medintsev I like
a little bit better, but does not change the classification.
3rd Honourable Mention  G186 Anatoly Stepochkin (Russia)
1.Kxa3[+wRa1] Rc1 2.Sab4 (Sdb4?) Rc3#
1.Kxc4[+wBf1] Bg2 2.Sdb4 (Sab4?) Bd5#
These rebirths remind me of my own jointcomposition with Dieter
Müller (see Appendix, D). In G186 the bK can capture the wR/wB on
the first move, because the lines to a3 and c4 are blocked by bSS.
Both must block square b4, but only the one that opens the line of
the reborn piece. Circe mates, nice dual avoidance and economical
construction.
4th Honourable Mention  G177 Ján Kovalič SuperProblem, 10072018 

4K3/2q1p1(Q2)1/4p3/1Pp1k1rP/2(q2)1p1p1/1(Q2)b1p1P(q2)/4p1p1/8 
h#2  1.2.1.1 b, c) Gg7>h1, f1
g7, b3, c4, h3: Grasshopper (G)
 (6+14) 

5th Honourable Mention  G148 János Csák SuperProblem, 08022018 

b2r3q/8/5p1p/5Pbk/5p1n/4pPp1/4PnP1/4K2R 
ser=12   (6+12) 

Commendation  G147 Brian Stephenson & Stephen Taylor SuperProblem, 08022018 

5(b3)2/4P3/1PP(R3)3R/p1K4(r3)/2P4(r3)/Q1nk4/(N3)4(n3)2/7(b3) 
r#2 
d6, h4, h5: Pao (PA) f8, h1: Vao (VA) a2, f2: Nao (NA)  (9+8) 

4th Honourable Mention  G177 Ján Kovalič (Slovakia)
a) diagram: 1.Kf5 Gb2 2.Be5 (A) Gb1#, 1...Gb6 2.Qe5 (B) Gd7#
b) Gg7>h1: 1.Kd4 Gf3 2.Qe5 (B) Gb6#, 1...Gh4 2.Re5 (C) Gf4#
c) Gg7>f1: 1.Kd6 Gxh3 2.Re5 (C) Gh6#, 1...Gfd3 2.Be5 (A) Ga3#
In the keys, the bK draws a Y on the board and always turns off
one of his three officers as a block. The two others block the
square just leaving in a dualavoiding way. This results in a cyclic
block change B/Q  Q/R  R/B. Unfortunately, the composer did not
succeed in realizing the reciprocal interchange of function of the
wGG and mate pattern in c) either. That prevented a slightly
higher placement.
5th Honourable Mention  G148 János Csák (Hungary)
1.00 2.Rd1 3.Rxd8 4.Rxh8 5.Rxa8 6.Ra1 7.Rf1 8.Rxf2 9.Kf1 10.Ke1 11.Rf1 12.Rh1=
Funny and original, white castling and in the end king and rook are
back in castling position. In the PDB I did not find anything
comparable.
Commendation  G147 Brian Stephenson & Stephen Taylor (England)
1.Qb3!  2.Qb5 Se4#
1...PAe4 2.Re6 PAee5#
1...VAe4 2.Rf6 VAf5#
1...NAe4 2.Rg6 NAg5#
Fine reflexmate with meeting point e4. To prevent his knight’s
threatening reflexmate on e4, Black blocks this square with Pao,
Vao and Nao. After that, the white rook can give up the control of
the black antibattery and enforces the reflexmate by exact
removal.
Commendation  G171 Ladislav Packa SuperProblem, 14062018 

7b/1Pp3p1/6Pk/P1r1P1pp/2pp4/1p4p1/1P2n3/1K1b2n1 
h#3.5  2 sol. AntiCirce  (6+14) 

Commendation  G178 Ján Kovalič SuperProblem, 10072018 

2n5/5ppp/2kp4/ppNb1pP1/r6r/1qnP3P/6N1/1Q4bK 
h#2  b) Pg5>f2 Take & Make Chess  (7+15) 

Commendation  G194 Marko Klasinc SuperProblem, 27092018 

8/4N3/1p6/4r3/4kb2/K3P3/1N1p1PP1/8 
h#2  4.1.. Andernach Chess  (6+5) 

Commendation  G171 Ladislav Packa (Slovakia)
1...b8R 2.Sh3 Rxb3[wRb3>h1] 3.Ba4 Rxh3[wRh3>h1] 4.Be8 Rxh5[wRh5>h1]#
1...b8B 2.Sf4 Bxc7[wBc7>c1] 3.Rc8 Bxf4[wBf4>c1] 4.Re8 Bxg5[wBg5>c1]#
On its way to the rebirth square, the underpromoted white piece
opens the line of a black piece so that it can occupy the rebirth
square of its king. To reach the mate, the white piece must be
reborn twice again, because he has to clear black pieces out of the
way. The harmony between the two solutions is good, but they
look a little bloodless at me.
Commendation  G178 Ján Kovalič (Czech Republic)
a) diagram: 1.dxc5e4 Qxg1b6+ 2.Kxb6g6 Sxh4f4#
b) Pg5>f2: 1.Bxg2f4 Qxb3d5+ 2.Kxd5f3 Sxa4d4#
First, a bR must be interfered, then the wQ sacrifices herself for
the bK, the bK moves to the mating square and a white S gives
mate. Take & Make in each half move, good. No corresponding line
opening for the wQ in b), less good. 15 black pieces, acceptable,
because Take & Make is a dynamic condition.
Commendation  G194 Marko Klasinc (Slovenia)
1.d1Q g4 2.Qxg4=w Qg2#
1.d1R Sd3 2.Rxd3=w Rd4#
1.d1B Sa4 2.Bxa4=w Bc2#
1.d1S Sf5 2.Sxe3=w f3#
Lovely black AUW. White actively sacrifices three times, one time
passively a piece so that the promoted piece can change colour.
The fourth solution differs slightly from the other three, but fits
well into the overall concept.
Appendix  Приложение
A Anatoly Stepochkin version Franz Pachl 

8/P4P2/(q1)bK1p3/4(q1)p1N/r5b1/3Brk2/5pn1/q7 
h#2  2.1..  (5+12) 

B Daniel Novomesky "Phénix", 2004 

3(q1)4/1(Q1)6/8/8/k7/8/K1P5/8 
h#4.5  3.1..
b7, d8: Lion  (3+2) 

C Cornel Pacurar Commendation, "Gaudium", 2013 

8/8/5(B2)2/8/8/3K4/8/6(b2)1 
hs#7  Ultraschachzwang b,c)Kd3>f4,c4; d)PRg1>g4
f6, g1: Princess (PR)  (2+1) 

A Anatoly Stepochkin, version Franz Pachl
1.Re4 f8=KA (A) 2.Bd4 (Qd4?) a8=KA# (B)
1.Rf4 a8=KA (B) 2.Qd4 (Bd4?) f8=KA# (A)
B Daniel Novomesky
1...c4 2.Kb4 LIb3 3.Ka5 LId5 4.LId3 Kb3 5.LIa6 c5#
1...c3 2.Kb5 LIb2 3.Ka4 LId4 4.LId2 Kb2 5.LIa5 c4#
1...Ka1 2.Kb4 LIb1 3.Ka3 LId3 4.Ld1 Kb1 5.LIa4 c3#
C Cornel Pacurar
a) diagram: 1...PRc5+ 2.Ke2 PRa6+ 3.Kf2 PRc5+ 4.PRd4 PRd3+ 5.Kg2 PRf4+ 6.Kh1 PRd5+ 7.PRf3 PRxf3#
b) Kd3>f4: 1...PRe2+ 2.Kg5 PRc1+ 3.Kg6 PRd3+ 4.PRe4 PRf4+ 5.Kg7 PRe6+ 6.Kh8 PRd4+ 7.PRf6 PRxf6#
c) Kd3>c4: 1...PRe3+ 2.Kb5 PRf1+ 3.Kb6 PRe3+ 4.PRd4 PRc4+ 5.Kb7 PRd6+ 6.Ka8 PRe4+ 7.PRc6 PRxc6#
d) PRg1>g4: 1...PRf5+ 2.Kd2 PRh6+ 3.Kc2 PRf5+ 4.PRe4 PRe3+ 5.Kb2 PRc4+ 6.Ka1 PRe5+ 7.PRc3 PRxc3#
D Franz Pachl & Dieter Müller 1st Prize, TT Problemecho, 2002 

8/B7/2p5/nPr3P1/PkB1b1R1/R6K/1p1p4/1n6 
h#2  2.1.. Circe  (8+8) 

D Franz Pachl & Dieter Müller
1.Bh7 Ba2+ 2.Kxa3[+wRa1] Bxc5[+bRh8]#
1.Rf5 Rd3 2.Kxc4[+wBf1] Rxe4[+bBc8]#
Judge of the section: Franz Pachl (Germany)Судья раздела: Франц Пахль (Германия)
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