Final Award in Quick Composing TT-130 | Окончательные итоги блицконкурса TT-130

Thrice to the same square | Трижды на одно поле

Theme | Тема

27 entries were received from 17 authors representing 8 countries | На конкурс поступило 27 композиций от 17 авторов из 8 стран

Award is the following | Отличия распределились следующим образом

1st Prize, 1st Place - No 16
Evgeni Bourd
TT-130, SuperProblem, 16-02-2015
2B3K1/r1BRNp2/5b2/p1P4n/r2Nk1pP/1nQR2p1/2Pp2P1/1b2q3
#3(12+13)
2nd Prize, 2nd Place - No 12
Semion Shifrin
TT-130, SuperProblem, 16-02-2015
1q1N4/3pbN2/1R4r1/1pPp3n/1Qpk1pP1/5P2/2PB2B1/6K1
#3(11+10)
3rd Prize, 3rd Place - No 4
Vladimir Shumarin
TT-130, SuperProblem, 16-02-2015
3n2B1/1b1p1p2/p1P1PP2/P7/3Np2R/3kN3/3p1P2/B2K4
#3(11+8)

1st Prize, 1st Place - No 16, Evgeni Bourd (Israel)

1.Sb5! – 2.Sd6+ Kf4 3.Sd5#
1...Sd4 2.R7xd4+ Rxd4/Bxd4 3.Bf5#
1...Bd4 2.Qxd4+ Sxd4/Rxd4 3.Sc3#
1...Rd4 2.R3xd4+ Sxd4/Bxd4 3.Qd3#
1...Ra6 2.Bb7+ Rc6 3.Bxc6#
Definitely the best problem of the tourney. It has original triple avoidance and despite captures of black officers it is excellent in its originality!!
EN <-> RU

2nd Prize, 2nd Place - No 12, Semion Shifrin (Israel)

1...Qxb6 2.Qb2+ Kxc5/c3 3.Bb4#/Qxc3#/Qb4#
1.Sb7? – 2.Qc3#, 1...Qxb7!
1.Bf1? – 2.c3#, 1...Rxg4+!
1.Kf2? – 2.Bc3#, 1...Bh4+!
1.Rd6! – 2.Qb2+ Kxc5/c3 3.Bb4#/Qxc3#/Qb4#
1...Rxd6 2.Bf1 – 3.c3#
1...Bxd6 2.Kf2 – 3.Bc3#
1...Qxd6 2.Sb7 – 3.Qc3#
It is always very pretty when the theme is copied by both black and white, in addition there is good analogy between the variations.
EN <-> RU

3rd Prize, 3rd Place - No 4, Vladimir Shumarin (Russia)

1.Bxf7? – 2.Bh5 – 3.Be2#, 1...Bxc6! (a)
1.Sdc2? – 2.Sb4#, 1...Sxc6! (b)
1.Se2? – 2.Sf4#, 1...Sxe6! (c)
1.Bh7? – 2.Bxe4#, 1...d5! (d)

1.Rh5! – 2.Rd5 – 3.Sd~#
1...Bxc6 (a) 2.Sdc2 – 3.Sb4#, 2...Ba4 3.Rd5#
1...Sxc6 (b) 2.Se2 – 3.Sf4#
1...dxc6 2.Sf3 – 3.Se5#, 2...exf3 3.Bh7#

1...Sxe6 (c) 2.Sdc2 – 3.Sb4#
1...dxe6 2.Sb3 – 3.Sc5#
1...fxe6 2.Se2 – 3.Sf4#, 2...e5 3.Bc4#
1...d5 (d) 2.Rxd5 Sxc6/Bxc6 3.Sxc6#, 2...Sxe6/fxe6 3.Sxe6#, 1...Ba8 2.Rd5 Bxc6/Sxc6/dxc6 3.Sxc6#, 2...Sxe6/dxe6/fxe6 3.Sxe6#.
The problem duplicates the theme of the tourney but there is a similarity between both triplets.
EN <-> RU
1st Honorable mention - No 11
Igor Agapov
TT-130, SuperProblem, 16-02-2015
K3B3/pPP1Bp2/r4P2/p1Nk4/2N1prP1/p3P3/2QP3b/q7
#3(12+10)
2nd Honorable mention - No 18
Fedor Davidenko
TT-130, SuperProblem, 16-02-2015
1q3N1b/1pn1r1n1/4P3/2P2k1b/2PpR1pB/3Bp1p1/6K1/8
#3(8+12)
3rd Honorable mention - No 8
Zoltan Labai
TT-130, SuperProblem, 16-02-2015
2qN4/2Rp1RP1/4bP2/2B1kPK1/1pP1Np2/pB1pnP2/1nP5/1Q6
#3(14+10)

1st Honorable mention - No 11, Igor Agapov (Russia)

1.Qa4! – 2.Bxf7+ Re6 3.Bxe6#
1...Qxf6 2.Se5! – 3.Qd4#, 2...Qxe5 3.Qb3#
1...Raxf6 2.Se6! – 3.Qc6#, 2...Rxe6 3.Qb5#, 2...Kxe6 3.Qd7#
1...Rfxf6 2.Sb2!– 3.Qxe4#/Qd4#, 2...Qxb2 3.Qxe4#, 2...Qb1 3.Qd4#
1...Re6 2.Sxe6 – 3.Qc6#, 1...Qe5 2.Sxe5 – 3.Qd4#
Nice play of interferences by white, which allows an additional threat on the second white move.
EN <-> RU

2nd Honorable mention - No 18, Fedor Davidenko (Russia)

1.Sh7! – 2.Rxe3+ Kf4 3.Bg5#
1...Sgxe6 2.Rf4+ Kxf4 3.Bxg3#, 2...Ke5 3.Rf5#
1...Scxe6 2.Rxd4+ Ke5 3.Bf6#
1...Rxe6 2.Re5+ Kxe5/Kf4 3.Bxg3#
1...Kg6 2.Rxg4+ Kh6 3.Bg5#
Good analogy between the variations of white.
EN <-> RU

3rd Honorable mention - No 8, Zoltan Labai (Slovakia)

1.Re7? – 2.Sf7#, 1...Sexc4 2.Qg1 Kd5 (a) 3.Qd4#, 2...Se3 3.Sf7#, 1...Qxd8!
1.Sf2! – 2.Qxb2+ axb2 3.Sxd3#
1...Sexc4 2.Qe1+ Kd5 (a) 3.Qe4#, 2...Se3 3.Sg4#
1...Sbxc4 2.Qa1+ Kd5 (a) 3.Qd4#, 2...Sb2 3.Sxd3#
1...Bxc4 2.Re7+ Kd5 (a) 3.g8Q(B)# Be6 3.Sf7#
Nice switchback problem by black, but it has no dual avoidances.
EN <-> RU
1st Commendation - No 23
Ingemar Lind
TT-130, SuperProblem, 16-02-2015
6BK/4N2p/1Q3r1p/1P2p1kn/2r1ppP1/1bPP4/3NPRRn/4B3
#3(13+11)
2nd Commendation - No 24
Ingemar Lind
TT-130, SuperProblem, 16-02-2015
8/5Q2/3PR3/8/8/8/3KP1pp/6k1
#3(5+3)
3rd Commendation - No 7
Zoltan Labai
TT-130, SuperProblem, 16-02-2015
4K3/2QpP3/1Nbr1pN1/b2p1P2/R2pkpB1/1P5R/4PBn1/2nq4
#3(12+12)

1st Commendation - No 23, Ingemar Lind (Sweden)

1.Rxf4! ~ (Sxf4) 2.Qxf6+ Sxf6 3.Rf5#
1...Kxf4 2.Qe3+ Kxe3 3.Sd5#
1...exf4 2.Qc5+ Rxc5 3.Sxe4#, 2...Rf5 3.Qxf5#
1...Rxf4/Rf8/Rf7 2.Qxh6+ Kxh6 3.g5#
1...Rcc6 2.Sxe4+ Kxf4 3.Bd2#
The four captures by black are nice, but there is no unity in the play.
EN <-> RU

2nd Commendation - No 24, Ingemar Lind (Sweden)

1.Ke3! Kh1 2.Qb7 Kg1 3.Qb1#
1...h1Q(R) 2.Qf2+ (A) Kh2 3.Rh6# (B)
1...h1S 2.Rh6 (B) Sg3/Sf2 3.Qf2# (A)
1.Rh6? h1Q 2.Qa7+ Kf1 3.Rf6#, 1...Kh1!
1.Qf3? Kh1 2.Rg6 Kg1 3.Qxg2#, 1...h1Q 2.Qe3+ Kh2/Kf1 3.Rh6/Rf6#, 1...h1S!
Black promotions are always pretty, even when there is no connection between them.
EN <-> RU

3rd Commendation - No 7, Zoltan Labai (Country)

1...Bc~ 2.Qc2+ (A) Qd3/Qxc2 3.Rxd4#
1...Re6 2.Qxf4+ (B) Sxf4 3.Re3#
1.Sxd5! – 2.Sxf6+ Rxf6 3.Qe5#
1...Bxd5 2.Qc2+ (A) Qd3/Qxc2 4.Rxd4#
1...Rxd5 2.Qxf4+ (B) Sxf4 3.Re3#
1...Kxd5 2.Rxa5+ Ke4/Bb5 3.Bf3#
Nice problem but it is a shame the white play is so simple.
EN <-> RU
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Sections | Разделы

#3 (threemovers | трёхходовки)

Participants | Участники

Abramenko S. – No 13, 14
Agapov I. – No 11
Bourd E. – No 16, 17
Davidenko F. – No 18
Kapustin F. – No 1*, 2, 19
Koci V. – No 3
Labai Z. – No 7, 8
Lind I. – No 20, 21, 22, 23, 24, 25, 26
Hnatyna M. – No 5
Novitsky P. – No 9, 10
Permyakov E. – No 1*
Shifrin S. – No 12
Shumarin V. – No 4
Stepochkin A. – No 6
Hadži-Vaskov G. – No 15*
Milošeski B. – No 15*
Tar G. – No 27

The Winner Is | Победитель

Evgeni Bourd
Congratulations! | Поздравляем!

Judge | Арбитр

Arieh Grinblat

Translation | Перевод

Aleksey Oganesjan

Editor | Редактор

Aleksey Oganesjan
e-mail: alexeioganesyan@gmail.com