Final Award in Quick Composing TT-197 | Окончательные итоги блицконкурса TT-197

Twin by a Move | Ходовой близнец

Theme | Тема

105 entries were received from 41 authors representing 19 countries | На конкурс поступило 105 композиций от 41 авторов из 19 стран

EN <-> RU

From TT Director Aleksey Oganesjan I received 105 problems in anonymous form. Among my criteria of evaluation there are a theme, a harmony, a technique and an aesthetics. I paid special attention to problems with twins that are cannot formed via the only shifting, i. e. with twins “corresponding to” castling or promotion.

Award is the following | Отличия распределились следующим образом

1st Prize, 1st Place - No 99
Ingemar Lind
TT-197, SuperProblem, 04-01-2018
r3k2r/3nb3/p7/K7/6B1/8/2b5/4R2q
h#2
b) Ke8->c8, Ra8->d8 (0-0-0)
c) Ke8->g8, Rh8->f8 (0-0)
(3+8)
2nd Prize, 2nd Place - No 5
Stephen Taylor
TT-197, SuperProblem, 04-01-2018
7q/2p2pQn/4Pp2/5k1r/1P3P1r/nKb1pp2/3P4/7b
h#2
b) Pd2->c3; c) Pd2->d3
d) Pd2->e3; e) Pd2->d4
(6+13)
3rd Prize, 3rd Place - No 11
Christer Jonsson
TT-197, SuperProblem, 04-01-2018
8/3R4/4N3/5P1B/p3k3/2P1P1b1/1K1pqpn1/8
h#2
b) Sg2->e3
(7+7)

1st Prize, 1st Place - No 99, Ingemar Lind (Sweden) r3k2r/3nb3/p7/K7/6B1/8/2b5/4R2q

a) diagram: 1.Rd8 Be2 2.Bf8 Bh5#
b) Ke8->c8, Ra8->d8 (0-0-0): 1.Qb7 Re6 2.Sb8 Rc6#
c) Ke8->g8, Rh8->f8 (0-0): 1.Qh8 Rg1 2.Bh7 Be6#
Three harmonic phases in each of which Black block two squares and White create battery and checkmate by her double check.
EN <-> RU

2nd Prize, 2nd Place - No 5, Stephen Taylor (England) 7q/2p2pQn/4Pp2/5k1r/1P3P1r/nKb1pp2/3P4/7b

a) diagram: 1.Ke4 Qg1 2.Kd3 Qxe3#
b) Pd2->c3: 1.Ke4 Qxh8 2.f5 Qd4#
c) Pd2->d3: 1.Kxe6 Qg4+ 2.Kd5 Qd7#
d) Pd2->e3: 1.fxe6 Qd7 2.Rg4 Qd3#
e) Pd2->d4: 1.Kxf4 Qxf6+ 2.Rf5 Qxh4#
Twins corresponding Albino with active play of wQ and 5 different mates. Excellent technical achievement.
EN <-> RU

3rd Prize, 3rd Place - No 11, Christer Jonsson (Sweden) 8/3R4/4N3/5P1B/p3k3/2P1P1b1/1K1pqpn1/8

a) diagram: 1.Qg4 Re7 2.Kf3 Sd4#
b) Sg2->e3: 1.Bd6 Bf7 2.Kd3 Sc5#
Self-pinning, creating and play of indirect battery. Function permutation between both White and Black pieces.
EN <-> RU
4th Prize - No 38
Dieter Müller
TT-197, SuperProblem, 04-01-2018
b7/5p2/Knrk2q1/3pN3/3p3N/8/8/2R5
h#2
b) Kd6->e5
(4+8)
5th Prize - No 36
Dieter Müller
TT-197, SuperProblem, 04-01-2018
2r5/1P4n1/Np2p3/1P6/2kB3q/5b1r/4P2b/5K2
h#2
b) –Pb7 +wSc8 (bxc8S)
c) –Pb7 +wBc8 (bxc8B)
d) –Pb7 +wRc8 (bxc8R)
(6+9)
6th Prize - No 81
Karol Mlynka
TT-197, SuperProblem, 04-01-2018
1n3r1q/b1P3P1/1k6/2p5/4K3/8/8/8
h#2
b) –Pc7, +wSb8 (cxb8S)
c) –Pg7, +wRf8 (gxf8R)
(3+6)

4th Prize - No 38, Dieter Müller (Germany) b7/5p2/Knrk2q1/3pN3/3p3N/8/8/2R5

a) diagram: 1.Rc6-c7 Shxg6 (a) 2.Rb7 Rc6# (b)
b) Kd6->e5: 1.Qg6-e4 Rxc6 (b) 2.f5 Sg6# (a)
Harmonic delayed Umnov. Good skill in building of mating pictures.
EN <-> RU

5th Prize - No 36, Dieter Müller (Germany) 2r5/1P4n1/Np2p3/1P6/2kB3q/5b1r/4P2b/5K2

a) diagram: 1.Kxb5 b8Q 2.Kxa6 Qxb6#
b) –Pb7 +wSc8 (bxc8S): 1.Bd5 Be5 2.Rb3 Sd6#
c) –Pb7 +wBc8 (bxc8B): 1.Bc6 Bxg7 2.Bxb5 Bxe6#
d) –Pb7 +wRc8 (bxc8R): 1.Kd5 Bf6 2.Kd6 Rd8#
Total AUW with a good technique. Pity that in initial position of d) bK is under a check.
EN <-> RU

6th Prize - No 81, Karol Mlynka (Slovakia) 1n3r1q/b1P3P1/1k6/2p5/4K3/8/8/8

a) diagram: 1.Kc6 gxf8Q 2.Kd7 c8Q#
b) –Pc7, +wSb8 (cxb8S): 1.Kc7 gxh8Q 2.Kd6 Qe5#
c) –Pg7, +wRf8 (gxf8R): 1.Kb7 c8Q+ 2.Ka8 Qc6#
Bicolor phoenix. Flawless skill.
EN <-> RU
7th Prize - No 14
Stephen Taylor
TT-197, SuperProblem, 04-01-2018
8/8/6N1/1p6/2p1k2r/7p/4P3/R3K2R
h#2
b) Ke1->c1, Ra1->d1 (0-0-0)
c) Ke1->g1, Rh1->f1 (0-0)
(5+5)
Special Prize - No 35
Anatoly Vasilenko & Andrey Frolkin
TT-197, SuperProblem, 04-01-2018
1qnbk2r/P1np3p/p6P/p2p3p/8/3P2pr/1P1PbPP1/5RK1
h#2
b) Be2->d1
(9+15)
1st Honorable mention - No 8
Phani Bhushan
TT-197, SuperProblem, 04-01-2018
r3k3/3N1p2/8/1P6/1n6/8/8/R3K3
h#2
b) Ke8->c8, Ra8->d8 (0-0-0)
c) Ke1->c1, Ra1->d1 (0-0-0)
(4+4)

7th Prize - No 14, Stephen Taylor (England) 8/8/6N1/1p6/2p1k2r/7p/4P3/R3K2R

a) diagram: 1.Ke3 Rd1 2.Re4 Rxh3#
b) Ke1->c1, Ra1->d1 (0-0-0): 1.Kf5 Rd5+ 2.Kg4 Rg1#
c) Ke1->g1, Rh1->f1 (0-0): 1.Rh5 Ra3 2.Rd5 Rf4#
Harmonic play of Black King and Rook that block a square (actively or passively).
EN <-> RU

Special Prize - No 35, Anatoly Vasilenko & Andrey Frolkin (Author), dedicated to the 60th birthday Mark Basisty 1qnbk2r/P1np3p/p6P/p2p3p/8/3P2pr/1P1PbPP1/5RK1

a) diagram:
1.0-0 fxg3 2.Kh8 Rxf8# (model mate)
Black balance: 15 (pieces on the board) + 1 (cxd or exd) = 16.
White balance: 9 + 6 (a7xb6xa5, b7xa6, cxd or exd, fxg, g6xh5) + 1 (Bc1) = 16.
Either the white e-pawn was promoted on e8 and the black c-pawn on c1 or the black e-pawn was promoted on e1 and the white c-pawn on c8. White has just played R~-f1. One of the castlings is illegal.
It is impossible to prove that Black has lost his castling right; therefore, Black has the right to castle according to the castling convention.

b) Be2->d1:
The retroanalysis is the same as in a), except that White has just played 0-0, for otherwise there is overbalance for one of the sides: c2xd3? – the black c-pawn could not get to c1; e2xd3? – the black e-pawn could not get to e1; Kh1-g1? – this must have been preceded by Rh4xh3+ – an excessive capture of a white piece, overbalance; Re1-f1? – illegal check to the black king.
The white e-pawn was promoted on e8; the black castling is illegal. This rules out the solution from a). The only solution is:
1.d6 Re1+ 2.Kd7 axb8S# (model mate)

An original rendition of the theme of mutually exclusive castlings. (Authors.)

Nice retro-puzzle with complex content.
EN <-> RU

1st Honorable mention - No 8, Phani Bhushan (India) r3k3/3N1p2/8/1P6/1n6/8/8/R3K3

a) diagram: 1.Ra7 Se5 2.Re7 Ra8#
b) Ke8->c8, Ra8->d8 (0-0-0): 1.Sc6 Ra7 2.Sb8 Sb6#
c) Ke1->c1, Ra1->d1 (0-0-0): 1.Sc6 bxc6 2.Rd8 Re1#
Twins with White and Black castlings in economic form.
EN <-> RU
2nd Honorable mention - No 52
Gábor Tar
TT-197, SuperProblem, 04-01-2018
2K5/2pn2b1/5P2/3k1q2/PpN1NB2/3rn1P1/4P3/8
h#2
b,c,d) Kd5->e6,e4,c4
(8+8)
3rd Honorable mention - No 53
Gábor Tar
TT-197, SuperProblem, 04-01-2018
8/8/1p2k3/1P2pNPK/4BP2/3N4/3PP3/8
h#2
b) Pe5->f4
(9+3)
4th Honorable mention - No 72
Fadil Abdurahmanović
TT-197, SuperProblem, 04-01-2018
7R/1K6/5Q2/8/1b6/4k3/5pp1/8
h#2
b) –Pf2, +bSf1 (f2-f1S)
c) –Pf2, +bBf1 (f2-f1B)
d) –Pf2, +bRf1 (f2-f1R)
(3+4)

2nd Honorable mention - No 52, Gábor Tar (Hungary) 2K5/2pn2b1/5P2/3k1q2/PpN1NB2/3rn1P1/4P3/8

a) diagram: 1.Kc6 Bxc7 2.Sd5 Sa5#
b) Kd5->e6: 1.Qd5 Be5 2.Sf5 Sg5#
c) Kd5->e4: 1.Rd5 f7 2.Bd4 Sd2#
d) Kd5->c4: 1.Sd5 Be3 2.Rc3 Sd2#
bK star in symmetrical position.
EN <-> RU

3rd Honorable mention - No 53, Gábor Tar (Hungary) 8/8/1p2k3/1P2pNPK/4BP2/3N4/3PP3/8

a) diagram:
*1...Bd5+ 2.Kxf5 e4#
1.exf4 Sc5+ 2.Ke5 d4#
b) Pe5->f4 (after 1st Black move):
*1...Sc5+ 2.Ke5 d4#
1.f3 Bd5+ 2.Kxf5 e4#
Amusing problem with exchange of set and actual play.
EN <-> RU

4th Honorable mention - No 72, Fadil Abdurahmanović (Bosnia & Herzegovina) 7R/1K6/5Q2/8/1b6/4k3/5pp1/8

a) diagram: 1.Ke2 Rf8 2.Kf1 Qxf2#
b) –Pf2, +bSf1 (f2-f1S): 1.Ke4 Rd8 2.Se3 Rd4#
c) –Pf2, +bBf1 (f2-f1B): 1.Be2 Qd4+ 2.Kf3 Rh3#
d) –Pf2, +bRf1 (f2-f1R): 1.g1S Qc3+ 2.Kf2 Rh2#
Miniature with three twins.
EN <-> RU
5th Honorable mention - No 97
Ingemar Lind
TT-197, SuperProblem, 04-01-2018
6b1/5P2/5k2/2b5/8/8/8/R3K3
h#2
b) –Pf7, +wSf8 (f7-f8S)
c) –Pf7, +wBf8 (f7-f8B)
d) –Pf7, +wRf8 (f7-f8R)
(3+3)
Special Hon. mention - No 90A
Phani Bhushan
TT-197, SuperProblem, 04-01-2018
bb6/8/1p3Pp1/rN1p3N/n3k2P/K7/1P3RP1/2n1r3
h#2
b) Pd5->d4
c=b) Pd4->d3
d=c) Pd3->d2
e=d) –Pd2, +bBd1
(8+10)
Commendation - No 105
Georgi Hadži-Vaskov
TT-197, SuperProblem, 04-01-2018
8/8/8/5kp1/5p2/8/R5p1/R3K3
h#2
b) Ke1->c1, Ra1->d1 (0-0-0)
(3+4)

5th Honorable mention - No 97, Ingemar Lind (Sweden) 6b1/5P2/5k2/2b5/8/8/8/R3K3

a) diagram: 1.Kg7 Ra8 2.Kh8 fxg8Q#
b) –Pf7, +wSf8 (f7-f8S): 1.Kg7 Ra7+ 2.Kh8 Sg6#
c) –Pf7, +wBf8 (f7-f8B): 1.Kg6 Ra6+ 2.Kh7 Rh6#
d) –Pf7, +wRf8 (f7-f8R): 1.Ke7 Rf7+ 2.Kd8 Ra8#
Total AUW, but with repetitive moves – Kg7, Kh8, Ra8.
EN <-> RU

Special Honorable mention - No 90A, Phani Bhushan (India) bb6/8/1p3Pp1/rN1p3N/n3k2P/K7/1P3RP1/2n1r3

a) diagram: 1.Sd3 Rf3 2.Se5 Sg3#
b) Pd5->d4: 1.Kd3 Sd6 2.Re3 Sf4#
c=b) Pd4->d3: 1.Re3 Sc7 2.Re5 Rf4#
d=c) Pd3->d2: 1.Ke3 Sg3 2.Bf3 Rxf3#
e=d) –Pd2, +bBd1: 1.Bg4 Re2+ 2.Kf5 Sd4#
Twins with shifting of Black Pawn “d” lead to 5 different mates.
EN <-> RU

Commendation - No 105, Georgi Hadži-Vaskov (Macedonia) 8/8/8/5kp1/5p2/8/R5p1/R3K3

a) diagram: 1.Ke4 Ra4+ 2.Ke3 R1a3#
b) Ke1->c1, Ra1->d1 (0-0-0): 1.Kg4 Rxg2+ 2.Kh4 Rh1#
Commendation - No 48
Dieter Müller
TT-197, SuperProblem, 04-01-2018
3b1N2/4kP2/5r2/8/5N2/4pr1p/5B2/3K1R2
h#2
b) Ke7->f8
(6+6)
Commendation - No 62
Dan-Constantin Gurgui
TT-197, SuperProblem, 04-01-2018
5qb1/3n1P2/3k4/1K2p3/3Bp3/8/8/8
h#2
b) –Pf7, +wBg8 (f7xg8B)
(3+6)
Commendation - No 86
Emanuel Navon
TT-197, SuperProblem, 04-01-2018
8/5B1p/2p4p/2PNP1R1/4k3/1PP3P1/1pK5/2N5
h#2
b) –Pb2, +bSc1 (b2xc1S)
c) –Pb2, +bSb1 (b2-b1S)
d) –Pb2, +bRb1 (b2-b1R)
(10+5)

Commendation - No 48, Dieter Müller (Germany) 3b1N2/4kP2/5r2/8/5N2/4pr1p/5B2/3K1R2

a) diagram: 1.Rg3 Bxg3 2.Rg6 S4xg6#
b) Ke7->f8: 1.Re6 Bh4 2.Rg3 Sxe6#

Commendation - No 62, Dan-Constantin Gurgui (Romania) 5qb1/3n1P2/3k4/1K2p3/3Bp3/8/8/8

a) diagram: 1.Qe8 fxe8Q 2.Kd5 Qxd7#
b) –Pf7, +wBg8 (f7xg8B): 1.Qf7 Bc5+ 2.Kd5 Bxf7#

Commendation - No 86, Emanuel Navon (Israel) 8/5B1p/2p4p/2PNP1R1/4k3/1PP3P1/1pK5/2N5

a) diagram: 1.bxc1B Bh5 2.Be3 Sf6#
b) –Pb2, +bSc1 (b2xc1S): 1.Sd3 Rf5 2.Sxe5 Rf4#
c) –Pb2, +bSb1 (b2-b1S): 1.Sd2 Sd3 2.Sf3 Sf2#
d) –Pb2, +bRb1 (b2-b1R): 1.Rxb3 Sxb3 2.h5 Sd2#
Special Commendation - No 103
Michael Lütt
TT-197, SuperProblem, 04-01-2018
8/3P4/8/6Pk/2p5/4B3/2r1p1pK/8
h#2
b) –Pg2, +bSg1 (g2-g1S)
c) –Pe2, +bBe1 (e2-e1B)
d) –Pe2, +bQe1 (e2-e1Q)
(4+5)

Special Commendation - No 103, Michael Lütt (Germany) 8/3P4/8/6Pk/2p5/4B3/2r1p1pK/8

a) diagram: 1.g1R d8Q 2.Rxg5 Qxg5#
b) –Pg2, +bSg1 (g2-g1S): 1.Sh3 d8Q 2.Sxg5 Qxg5#
c) –Pe2, +bBe1 (e2-e1B): 1.Bh4 d8Q 2.Bxg5 Qxg5#
d) –Pe2, +bQe1 (e2-e1Q): 1.Qa5 d8Q 2.Qxg5 Qxg5#


COMMENTS (real-time mode) | КОММЕНТАРИИ посетителей
comments powered by HyperComments

Sections | Разделы

H# (helpmates | коопматы)

Participants | Участники

Abdurahmanović F. – No 1
Balasubramanian S. K. – No 87*, 88*, 89
Bhushan P. – No 8, 88*, 90A, 90B
Bidlen A. – No 54, 55, 56, 57, 58, 59, 60
Bilokin Y. – No 74, 75, 76, 77*
Brukhanov I. – No 2
Diatlov O. – No 15
Dragoun M. – No 44*
Drążkowski K. – No 63, 64
Evseev V. – No 65
Frolkin A. – No 35*
Giakatis T. – No 100, 101
Gurgui D. – No 61, 62
Hadži-Vaskov G. – No 104, 105
Halma M. – No 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34
Jonsson C. – No 7, 9, 10, 11
Kirichenko A. – No 3
Koci V. – No 69
Kreimer M. – No 77*
Labai Z. – No 18
Lind I. – No 95, 96, 97, 98, 99
Lütt M. – No 102, 103
Manikumar S. – No 87*, 91, 92, 93, 94
Medintsev V. – No 71
Mlynka K. – No 80A, 80B, 81, 82, 83
Müller D. – No 36, 37, 38, 39, 40, 41, 42, 43, 44*, 45, 46, 47, 48, 49
Navon E. – No 84*, 85*, 86
Nefyodov V. – No 67
Parrinello M. – No 66
Ruppin R. – No 78, 79
Serafimović I. – No 70
Shorokhov B. – No 19
Stun J. – No 73
Tar G. – No 50, 51, 52, 53
Taylor S. – No 4, 5, 13, 14
Tritten P. – No 12
Trommler S. – No 20, 21, 22
Vasilenko A. – No 6, 35*
Vieira R. – No 68
Witztum M. – No 84*, 85*
Yuzyuk V. – No 16, 17A, 17B

The Winner | Победитель

Ingemar Lind
Congratulations! | Поздравляем!

Judge | Арбитр

János Csák

Director and editor
Директор и редактор

Aleksey Oganesjan
e-mail: alexeioganesyan@gmail.com

Comments | Комментарии

show | показать