Final Award in Quick Composing TT-183 | Окончательные итоги блицконкурса TT-183

Continued perpetuum mobile | Продолженный вечный двигатель

50 entries were received from 25 authors representing 17 countries | На конкурс поступило 50 композиций от 25 авторов из 17 стран

From the director I received 50 problems for judging without author names. When suggesting the theme, I was very interested to see the different ideas that the authors would come up with. Although many problems showed similar play there were also many original ideas. When describing the theme, it was also my mistake not to show which twins are not considered thematic, and as a result there some problems creating specific twins for every phase instead of a general twin for all phases. There were several interesting ideas among those problems which might be suitable in another tourney, but I cannot include them in the award. I have also decided to include in the award a little more problems than usual, due to the unique theme. When evaluating the problems, I mainly focused on originality and execution. The number of phases influenced my decision as well. I expected more problems of length higher than 2, but they are probably hard to create without many weaknesses.

Award is the following | Отличия распределились следующим образом

1st Prize, 1st Place - No 45 Chris Tylor & Andrey Frolkin TT-183, SuperProblem, 22-03-2017
8/pB1p4/P2P4/P2Pp3/1P1pk3/1p1pn3/2pP2P1/1bK1RR2
h#2	see text	(11+10)

2nd Prize, 2nd Place - No 36 Ricardo Vieira TT-183, SuperProblem, 22-03-2017
2bn4/4Rp2/1B1pNp2/rB3K2/2p4p/2Pnk1b1/2PrppP1/8
h#2	see text	(8+14)

1st Hon. Mention, 3rd Place - No 44 Chris Tylor & Andrey Frolkin TT-183, SuperProblem, 22-03-2017
8/2p1p3/2p1P3/1bp5/p1k2N2/P3P3/1K1P4/8
h#2	see text	(6+7)

1st Prize, 1st Place - No 45, Chris Tylor (England) & Andrey Frolkin (Ukraine) 8/pB1p4/P2P4/P2Pp3/1P1pk3/1p1pn3/2pP2P1/1bK1RR2

a) diagram: 1.Ba2 (tempo) Rd1 (unpin) 2.Sxd5 (self-pin) Rde1# (switchback)

b) in mating position of a) add wP for a checkless legal position.
+wPe2? (leading to 7 solutions) = illegal position
White balance: 11 (pieces on the board) + 5 (exd, fxe, gxfxexd) + 1 (Bf1) = 17.
+wPe3! – 1.Bb1 (tempo) Bc8 (unpin) 2.Sxe3 (self-pin) Bb7# (switchback)

c) in mating position of b) add wP for a checkless legal position.
+wPc6? (leading to 3 one-move solutions) = illegal position
White balance: 11 (pieces on the board) + 5 (exd, fxe, gxfxexd) = 16.
Black balance: 10 (pieces on the board) + 6 (cxbxa, exdxc, fxexd) + 1 (hxg->g8 or bPh was captured on its file and h2->h8) = 17.
+wPd5! – solution is the same as in a) ...

A very original twinning mechanism – adding a white pawn and keep the position legal. In each of the twins, white has a choice of other square which does not work due to illegality. And in the end the only correct choice leads to infinity play. Very complicated problem requiring a lot of material, but in a good way!

EN <-> RU

2nd Prize, 2nd Place - No 36, Ricardo Vieira (Brazil) 2bn4/4Rp2/1B1pNp2/rB3K2/2p4p/2Pnk1b1/2PrppP1/8

a) diagram: 1.Sc5 Bd7 2.Sb7 Sf4#

b) in mating position of a) the knights that moved at B1 and W2 exchange position (bSc5<->wSf4): 1.Se6 Bb5 2.Sd8 Sd3#

c) in mating position of b) the knights that moved at B1 and W2 exchange position (bSe6<->wSd3): = a) ...

This entry is really confusing, everything looks good and complicated but the black king is in check!
Despite the king in check, the problem shows a highly original idea with a somewhat strange twinning mechanism. I like the matching play of Bb5 and Sd8 along the back of the position. I struggled a little with myself where to place this problem, but I decided that despite the obvious flaw of the problem it is highly original, complicated and deserves a high commendation.

EN <-> RU

1st Honorable mention, 3rd Place - No 44, Chris Tylor (England) & Andrey Frolkin (Ukraine) 8/2p1p3/2p1P3/1bp5/p1k2N2/P3P3/1K1P4/8

a) diagram: 1.Ba6 Kc2 2.Bb5 d3#

b) in mating position of a) wSd3: 1.Ba6 Kb2 2.Bb5 Se5#

c) in mating position of b) wRe5: 1.Ba6 Kc2 2.Bb5 Re4#

d) in mating position of c) wSe4: 1.Ba6 Kb2 2.Bb5 Sd2#

e) in mating position of d) wPd2 = a) ...

Very nice and clean idea shown in Forsberg twinning mechanism of four phases. What is special about this problem is that in each of the phases white needs to make a tempo move and it is made by the white king. Very sound idea. It is unfortunate that the black play is very weak.

EN <-> RU

2nd Honorable mention - No 22A Vladislav Nefyodov TT-183, SuperProblem, 22-03-2017
4N1K1/4N1Bn/4k3/5p2/8/8/8/8
h#2	see text	(4+3)

3rd Honorable mention - No 50 Luis Miguel Martin TT-183, SuperProblem, 22-03-2017
8/4B3/8/ppp5/7R/2pk4/K1p5/3n4
h#2	see text	(3+7)

4th Honorable mention - No 8 Pietro Pitton TT-183, SuperProblem, 22-03-2017
8/8/8/4KPnp/5Pkp/8/7P/6N1
h#2	see text	(5+4)

2nd Honorable mention - No 22A, Vladislav Nefyodov (Russia) 4N1K1/4N1Bn/4k3/5p2/8/8/8/8

a) diagram: 1.Sf8 Sc8 2.Sd7 Sc7#
b) mating position of a) Ke6<->Kg8: 1.Sf6 Se8 2.Sh7 Se7#
c) mating position of b) Kg8<->Ke6 = a) ...

In miniature setting and a nice twinning mechanism the black knight performs a Rundlauf. In the first phase he needs to avoid check with Sf6 while in the second phase he has to avoid Sf8 on its way back.
Good idea and well executed.

EN <-> RU

3rd Honorable mention - No 50, Luis Miguel Martin (Spain) 8/4B3/8/ppp5/7R/2pk4/K1p5/3n4

a) diagram: 1.Kd2 Rh1 2.Kc1 Bg5#
b) in mating position of a) Kc1->d3: 1.Kc4 Be7 2.Kb4 Rh4#
c) in mating position of b) Kb4->d3 = a) ...

One of the only problem showing a small reminder for modern play with echo-ODT and a pin mate.

EN <-> RU

4th Honorable mention - No 8, Pietro Pitton (Italy) 8/8/8/4KPnp/5Pkp/8/7P/6N1

a) diagram: 1.Se4 f6 2.Sg3 h3#
b) mating position of a) 180 grad: 1.Sd5 a7 2.Sb4 c4#
c) mating position of b) 180 grad = a) ...

One more surprising twinning mechanism – board rotation. Here it is combined with a tempo move by white.

EN <-> RU

5th Honorable mention - No 4 Ivars Ozols TT-183, SuperProblem, 22-03-2017
3n3b/B6K/p4pp1/2rp3R/2pkb3/p4p2/2PP1p2/5n2
h#2	see text	(5+14)

Commendation - No 1 Ivars Ozols TT-183, SuperProblem, 22-03-2017
K7/BP6/8/8/8/8/7p/7k
h#2	see text	(3+2)

Commendation - No 6 Illo Krampis TT-183, SuperProblem, 22-03-2017
1br5/2kP4/1p6/4N3/8/8/8/2K5
h#2	see text	(3+4)

5th Honorable mention - No 4, Ivars Ozols (Latvia) 3n3b/B6K/p4pp1/2rp3R/2pkb3/p4p2/2PP1p2/5n2

a) diagram: 1.Bd3 Bb8 2.Be2 Rh4#
b) mating position of a) Be2->e4: 1.Ra5 Rh5 2.Ra4 Ba7#
c) mating position of b) Ra4->c5 = a) ...

Nice matched echo ODT play where black seeks for hideaway.

EN <-> RU

Commendation - No 1, Ivars Ozols (Latvia) K7/BP6/8/8/8/8/7p/7k

a) diagram: 1.Kg2 b8Q 2.Kh1 Qb7#
b) mating position of a) wPb7 = a) ...

Commendation - No 6, Illo Krampis (Latvia) 1br5/2kP4/1p6/4N3/8/8/8/2K5

a) diagram: 1.Ba7 d8R 2.Bb8 Rd7#
b) mating position of a) wPd7 = a) ...

Commendation - No 9 Ralf Krätschmer TT-183, SuperProblem, 22-03-2017
8/1N4R1/8/3rk3/6B1/5K2/8/8
h#2	see text	(4+2)

Commendation - No 10 Menachem Witztum TT-183, SuperProblem, 22-03-2017
3N4/3pq3/3p1k1K/4p3/6p1/6p1/6P1/5N2
h#2	see text	(4+7)

Commendation - No 13 Dan-Constantin Gurgui TT-183, SuperProblem, 22-03-2017
8/4p3/1p2K3/1Bk5/2N5/1R4P1/8/8
h#2	see text	(5+3)

Commendation - No 9, Ralf Krätschmer (Germany) 8/1N4R1/8/3rk3/6B1/5K2/8/8

a) diagram: 1.Rd4 Rc7 2.Kd5 Rc5#
b) mating position of a) wBc5: 1.Ke5 Bf8 2.Rd5 Bg7#
c) mating position of b) wRg7 = a) ...

Commendation - No 10, Menachem Witztum (Israel) 3N4/3pq3/3p1k1K/4p3/6p1/6p1/6P1/5N2

a) diagram: 1.Qe6 Se3 2.Qf5 Sd5#
b) mating position of a) wRd5: 1.Qe6 Rd1 2.Qe7 Rf1#
c) mating position of b) wSf1 = a) ...

Commendation - No 13, Dan-Constantin Gurgui (Romania) 8/4p3/1p2K3/1Bk5/2N5/1R4P1/8/8

a) diagram: 1.Kd4 Rd3 2.Ke4 Sd2#
b) mating position of a) Ke4->c5: 1.Kb4 Rb3+ 2.Ka5 Sc4#
c) mating position of b) Ka5->c5 = a) ...

Commendation - No 14 Christer Jonsson TT-183, SuperProblem, 22-03-2017
8/3P4/3bn3/3pkp2/8/4K3/8/8
h#2	see text	(2+5)

Commendation - No 19 Luis Miguel Martin TT-183, SuperProblem, 22-03-2017
8/8/8/4B3/1p2b1N1/4K3/4P1p1/4k3
h#2	see text	(4+4)

Commendation - No 21 Luis Miguel Martin TT-183, SuperProblem, 22-03-2017
8/8/1P6/1p2pn2/1pk2Nr1/rn6/2B3b1/B5K1
h#2	see text	(5+9)

Commendation - No 14, Christer Jonsson (Sweden) 8/3P4/3bn3/3pkp2/8/4K3/8/8

a) diagram: 1.Be7 d8S 2.Bf6 Sf7#
b) mating position of a) wPf7: 1.Be7 f8S 2.Bd6 Sd7#
c) mating position of b) wPd7 = a) ...

Commendation - No 19, Luis Miguel Martin (Spain) 8/8/8/4B3/1p2b1N1/4K3/4P1p1/4k3

a) diagram: 1.Be4-c2 Sh2 2.Bd1 Bg3#
b) mating position of a) Ke3<->Ke1: 1.Bd1-c2 Be5 2.Be4 Sg4#
c) mating position of b) Ke1<->Ke3 = a) ...

Commendation - No 21, Luis Miguel Martin (Spain) 8/8/1P6/1p2pn2/1pk2Nr1/rn6/2B3b1/B5K1

a) diagram: 1.Sc5 Be4 2.Rf3 Bd5#
b) mating position of a) wRd5: 1.Ra3 Rd2 2.Sb3 Rc2#
c) mating position of b) wBc2 = a) ...

Commendation - No 25 Ivan Antipin TT-183, SuperProblem, 22-03-2017
8/b2q4/2p5/8/1K6/2Nk1P2/3rr3/6B1
h#2	see text	(4+6)

Commendation - No 26 Janez Nastran TT-183, SuperProblem, 22-03-2017
7N/8/4qp2/4pk1B/8/5K2/8/8
h#2	see text	(3+4)

Commendation - No 27 Michael Lütt TT-183, SuperProblem, 22-03-2017
2K5/4P3/8/4k3/4Pb2/1N6/8/8
h#2	see text	(4+2)

Commendation - No 25, Ivan Antipin (Russia) 8/b2q4/2p5/8/1K6/2Nk1P2/3rr3/6B1

a) diagram: 1.Rc2! Sd5 2.Red2 Sf4#
b) mating position of a) wRf4: 1.Re2! Rc4 2.Rcd2 Rc3#
c) mating position of b) wSc3 = a) ...

Commendation - No 26, Janez Nastran (Slovenia) 7N/8/4qp2/4pk1B/8/5K2/8/8

a) diagram: 1.Qg8 Be8 2.Qg5 Bd7#
b) in mating position of a) wRd7: 1.Qg8 Rh7 2.Qe6 Rh5#
c) in mating position of b) wBh5 = a) ...

Commendation - No 27, Michael Lütt (Germany) 2K5/4P3/8/4k3/4Pb2/1N6/8/8

a) diagram: 1.Kd6 e8Q 2.Be5 Qd7#
b) in mating position of a) wPd7: 1.Bf4 d8Q+ 2.Ke5 Qe7#
c) in mating position of b) wPe7 = a) ...

Commendation - No 30 Ingemar Lind TT-183, SuperProblem, 22-03-2017
8/K1k5/8/8/8/8/8/Q7
h#2	see text	(2+1)

Commendation - No 31 Ingemar Lind TT-183, SuperProblem, 22-03-2017
8/P7/bnN5/1k6/p2K4/8/8/8
h#2	see text	(3+4)

Commendation - No 39 Mikhail Halma TT-183, SuperProblem, 22-03-2017
8/np6/r7/pkN1K3/p2P4/8/8/8
h#2	see text	(3+6)

Commendation - No 30, Ingemar Lind (Sweden) 8/K1k5/8/8/8/8/8/Q7

a) diagram: 1.Kc8 Kb6 2.Kb8 Qh8#
b) in mating position of a) Kb6<->Kb8: 1.Ka6 Kc7 2.Ka7 Qa1#
c) in mating position of b) Ka7<->Kc7 = a) ...

Commendation - No 31, Ingemar Lind (Sweden) 8/P7/bnN5/1k6/p2K4/8/8/8

a) diagram: 1.Bb7 a8S 2.Ka6 Sc7#
b) in mating position of a) wPc7: 1.Kb5 c8S 2.Ba6 S8a7#
c) in mating position of b) wPa7 = a) ...

Commendation - No 39, Mikhail Halma (Ukraine) 8/np6/r7/pkN1K3/p2P4/8/8/8

a) diagram: 1.Rb6 Se6 2.Ka6 Sc7#
b) in mating position of a) wPc7: 1.Kb5 c8Q 2.Ra6 Qc5#
c) in mating position of b) wSc5 = a) ...

Schachography: White pieces show “V”, Black – “F”. It is dedication to Valery Frigin. (author.)

EN <-> RU

Commendation - No 40 Mikhail Halma TT-183, SuperProblem, 22-03-2017
8/8/8/8/8/P7/R3n3/1Nk1K3
h#2	see text	(4+2)

Commendation - No 46 Chris Tylor & Andrey Frolkin TT-183, SuperProblem, 22-03-2017
7q/2K1pr2/4kb1p/4rp1P/5R1p/8/8/8
h#2	see text	(3+9)

Commendation - No 48 Luis Miguel Martin TT-183, SuperProblem, 22-03-2017
8/8/8/4N1p1/4pk2/1K6/7R/8
h#2	see text	(3+3)

Commendation - No 40, Mikhail Halma (Ukraine) 8/8/8/8/8/P7/R3n3/1Nk1K3

a) diagram: 1.Sc3 Sd2 2.Sb1 Sb3#
b) in mating position of a) Sb3<->Sb1: 1.Sd2 Sc3 2.Sb1 Se2#
c) in mating position of b) Sb1<->Se2 = a) ...

Commendation - No 46, Chris Tylor (England) & Andrey Frolkin (Ukraine) 7q/2K1pr2/4kb1p/4rp1P/5R1p/8/8/8

a) diagram: 1.Bg7 Rg4 2.Kf6 Rg6#
b) in mating position of a) wSg6: 1.Ke6 Kc6 2.Bf6 Sf4#
c) in mating position of b) wRf4: 1.Bg7 Rg4 2.Kf6 Rg6#
d) in mating position of c) wSg6: 1.Ke6 Kc7 2.Bf6 Sf4#
e) in mating position of d) wRf4 = a) ...

Commendation - No 48, Luis Miguel Martin (Spain) 8/8/8/4N1p1/4pk2/1K6/7R/8

a) diagram: 1.Ke3 Sc4+ 2.Kd3 Rd2#
b) in mating position of a) Ke3->f4: 1.Kg4 Se5+ 2.Kh5 Rh2#
c) in mating position of b) Kh5->f4 = a) ...