Final Award in Quick Composing TT-177 | Окончательные итоги блицконкурса TT-177

Helpmate Circe Clockwise | Головокружение от Цирце

Theme | Тема

41 entries were received from 18 authors representing 11 countries | На конкурс поступила 41 композиция от 18 авторов из 11 стран

EN <-> RU

From the director we've received 41 anonymous problems. There was hardly any comparison material on the subject, so we expected interesting new ideas. The palette extended from little problems to profound strategic pieces, which had very good chances to go into the award. Independently of each other, we fixed the first prize, the problem speaks for itself. We had hardly discussions about the other problems and we decided that 17 problems go into the award. We think it was a successful tourney.

First, some comments on the failed problems:
- No 01 (Kd8-Ka8): Here somehow the red thread between the 3 solutions is missing, no analogy.
- No 04 (Kh8-Kd5): No true dual avoidance, because the capture with the wrong rook removes the wSa1 from the board. Solutions are quite harmless.
- No 05 (Ka1-Kd5): The solutions are not uniform. a) is still the best.
- No 06 (Kd6-Kd4): Only building of mate images and no harmony.
- No 09 (Kc2-Kd4): Shows the same as No 07, probably from the same author. The No 09 has two stones less, but we prefer the No 07 because the first white move is more subtle.
- No 10 (Kh2-Kd5): Circe only uses in the mate move, three times the same mate position.
- No 12 (Kh7-Kd4): bQg2/bSb6 are only cook-stoppers, a high price for this simple idea.
- No 13 (Kc1-Kc6): This big black king star is bought with a lot of not necessary pieces in the four phases too expensive.
- No 14 (Kc8-Kc6): Too simple solutions.
- No 17 (Kf7-Ke5): At a first glance this shows very well, but actually the board rotation only changes the direction of the pawns, whereby each time another pawn is capturing the white bishop. The mate positions are always the same.
- No 18 (Kb2-Ke4): Similar mate images as in No 07, although fourfold, but Circe only virtual in the mate move.
- No 21 (Ka7-Ke5): Very simple strategy with hardly difference between a) and b).
- No 22 (Kd7-Kd5): The same mate after identical strategy.
- No 27 (Ka1-Kf3): Fourfold queen promotion, but in all phases there are not necessary pieces.
- No 29 (Ke3-Kh4): Black ¾-promotion, block change, but little Circe and simple solutions.
- No 30 (Ke4-Kf1): Although a miniature, but see No 29.
- No 31 (Kb1-Kd1): No analogy, here we expected reciprocal captures by the bQ in b).
- No 32 (Ka6-Kh3): Chess protection for the wK, but the first black moves are too trivial.
- No 34 (Kh3-Kg5): Building of mate images, move repetition (wR/bS), no analogy.
- No 36 (Kb5-Kg5): c) should be omitted. It could be improved by a twin with fewer pieces. In such a form it would be a commendation.
- No 37 (Ka2-Kg1): It’s true a six piece problem, but different non harmonic solutions and no analogy.
- No 38 (Kc2-Kd4): Actually boring because there is no change in the four phases.
- No 39 (Kh3-Ke5): This problem doesn’t meet the announcement. Twins should only be generated by rotation of the board. Nothing else was allowed. But without removing the mating piece the problem is also correct, but in b) the mating piece is a Nachtwächter, besides the both solutions of a) are clearly better.
- No 41 (Ke6-Ke2): Solutions are too simple. In c) the solution also works without Circe.

Thanks a lot to Aleksey Oganesjan for the exemplary collaboration and congratulations to the successful authors.

Award is the following | Отличия распределились следующим образом

1st Prize, 1st Place - No 19
Juraj Lörinc
TT-177, SuperProblem, 21-12-2016
rR2bb2/1B1n1kp1/6N1/2n2p2/2q5/8/5K2/1r6
h#2b) 90 grad
Circe
(4+10)
2nd Prize, 2nd Place - No 2
Themis Argirakopoulos
TT-177, SuperProblem, 21-12-2016
8/1P6/2K5/5p1n/4p1nk/6p1/2br2P1/8
h#2b-d) 90, 180, 270 grad
Circe
(3+8)
3rd Prize, 3rd Place - No 26
Ingemar Lind
TT-177, SuperProblem, 21-12-2016
7b/6P1/1P1p4/8/5K2/3r4/3rkn2/3qnb2
h#22.1..   b) 90 grad
Circe
(3+9)

1st Prize, 1st Place - No 19, Juraj Lörinc (Slovakia) rR2bb2/1B1n1kp1/6N1/2n2p2/2q5/8/5K2/1r6

a) diagram:
1.Rxb8(Ra1)! Ra6 2.Sxb7(Bf1)! Bxc4(Qd8)#
1.Sxb8(Ra1)? ... 3.Qd5!, 2.Rxb7(Bf1)? ... 3.Se6!
b) 90 grad:
1.Rxg7(Bc1)! Bxe3(e7) 2.Sxh7(Rh1)! Rxh3(Bc8)#
1.Sxg7(Bc1)? ... 3.Bxh3(Rh1)!, 2.Rxh7(Rh1)? ... 3.Sxh3(Rh1)!
The top problem convinces through a rich strategy that meets the highest demands. Dual avoidance in both black moves, in each solution are three Circe captures, function changes wR/wB as cover and mate piece, excellent harmony and analogy. It is worthwhile to study the subtleties of this problem.
EN <-> RU

2nd Prize, 2nd Place - No 2, Themis Argirakopoulos (Greece) 8/1P6/2K5/5p1n/4p1nk/6p1/2br2P1/8

a) diagram: 1.Rd2-d8 b7-b8B 2.Rd8*b8[+wBc1] Bc1-g5 #
b) 90 grad: 1.Rb5-g5 g7-g8R 2.Rg5*g8[+wRh1] Rh1*e1[+bSb8] #
c) 180 grad: 1.Re7-e8 b7-b8Q 2.Re8*b8[+wQd1] Qd1*a4[+bSg8] #
d) 270 grad: 1.Bg3-h4 g7-g8S 2.Bh4-f6 Sg8*f6[+bBf8] #
The theme was predestined for an AUW, these here with rebirth of the promoted pieces have an economical construction. Circe is used in all four phases in the mate move, three times for white, once for black. Note, how tricky the author has solved the coverage of h3 (after rotation c1, a6, f8).
EN <-> RU

3rd Prize, 3rd Place - No 26, Ingemar Lind (Sweden) 7b/6P1/1P1p4/8/5K2/3r4/3rkn2/3qnb2

a) diagram:
1.Qd1-b3 g7-g8S 2.Qb3*g8[+wSb1] Sb1-c3 #
1.Qd1-a1 g7*h8R[+bBf8] 2.Qa1*h8[+wRa1] Ra1*e1[+bSb8] #
b) 90 grad:
1.Rb5-b8 f7-f8Q 2.Rb8*f8[+wQd1] Qd1*b3[+bSg8] #
1.Rc5-c8 f7-f8B+ 2.Rc8*f8[+wBc1] Bc1*a3 #
Also this AUW with fourfold Circe mates is good succeeded, distributed on 2 x 2 solutions. Very nice is the reason, which black piece has to capture the white promoted piece.
EN <-> RU
4th Prize - No 3
Dieter Müller
TT-177, SuperProblem, 21-12-2016
8/6n1/8/3Pk1p1/3pP3/2rb3K/1nP1N2b/6B1
h#2b) 270 grad
Circe
(6+8)
1st Honorable mention - No 25
Ingemar Lind
TT-177, SuperProblem, 21-12-2016
1bkr4/1bnppP2/1p1rp3/8/6K1/1P4P1/5P2/8
h#2b-d) 90, 180, 270 grad
Circe
(5+10)
2nd Honorable mention - No 7
Dieter Müller
TT-177, SuperProblem, 21-12-2016
1B6/1B2r3/1qP3N1/8/3k3K/2p2P2/8/8
h#2vb) 270 grad
Circe
(6+4)

4th Prize - No 3, Dieter Müller (Germany) 8/6n1/8/3Pk1p1/3pP3/2rb3K/1nP1N2b/6B1

a) diagram: 1.Sf5!! (Se8?) cxd3[+bBc8] 2.Sd6+ Bxd4[+wPd7]#
b) 270 grad: 1.Sd8!! (Sa5?) Sxf3[+bRa8] 2.Sc6+ Bxg8[+bBc8]#
To spin the mate net, white has to capture a black piece. Because this is an illegal self-check, black closes first the line of the rebirth piece on his way to a block, only to open it again immediately. Profound strategy with dual avoidance and cross check.
EN <-> RU

1st Honorable mention - No 25, Ingemar Lind (Sweden) 1bkr4/1bnppP2/1p1rp3/8/6K1/1P4P1/5P2/8

a) diagram: 1.Rd6-c6 f7-f8Q 2.Rd8*f8[+wQd1] Qd1*d7 #
b) 90 grad: 1.Rf5-c5 c7-c8R 2.Rc5*c8[+wRh1] Rh1*h5[+bRa8] #
c) 180 grad: 1.Re3-e8 c7-c8S 2.Re8*c8[+wSb1] Sb1*d2[+bPd7] #
d) 270 grad: 1.Rc4-f4 f7-f8B 2.Rf4*f8[+wBc1] Bc1*b2 #
AUW distributed to four pawns, uniform with opening by the bRd6. It’s a pity that there are only three Circe mates.
EN <-> RU

2nd Honorable mention - No 7, Dieter Müller (Germany) POS

a) diagram:
1.Qb6*b7[+wBf1]? Bf1-c4 2.Qb7*b8[+wBc1] Bc1-e3# (3.Re7*e3[+wBc1!!])
1.Re7*b7[+wBf1]! Bf1-c4 2.Rb7*b8[+wBc1] Bc1-e3#
b) 270 grad:
1.Rb5*b2[+wBc1]? Bc1-f4 2.Rb2*a2[+wBf1] Bf1-d3# (3.Qd2*d3[+wBf1]!!)
1.Qс2*b2[+wBc1]! Bc1-f4 2.Qb2*a2[+wBf1] Bf1-d3#
Mirrored echo mates with dual avoidance in the first black move. By the self-covering bishops, all four moves use the Circe condition.
EN <-> RU
3rd Honorable mention - No 24
Maryan Kerhuel
TT-177, SuperProblem, 21-12-2016
3B2rb/2p3p1/1n1P2Pk/3P4/1p1PP3/8/1rp3R1/K2B4
h#2b) 90 grad
Circe
(9+9)
4th Honorable mention - No 16
Anatoly Vasilenko
TT-177, SuperProblem, 21-12-2016
8/8/3K4/8/3kr3/3q4/2PB4/2N2b2
h#2b) 180 grad
Circe
(4+4)
5th Honorable mention - No 20
Misha Shapiro
TT-177, SuperProblem, 21-12-2016
5b2/qPpK4/6P1/4ppp1/3ppk1n/2p1n1r1/1Pp5/rb2N3
h#2b-d) 90, 180, 270 grad
Circe
(5+16)

3rd Honorable mention - No 24, Maryan Kerhuel (France) 3B2rb/2p3p1/1n1P2Pk/3P4/1p1PP3/8/1rp3R1/K2B4

a) diagram: 1.Sxd5[+wPd2] Bxc7 2.Sxc7[+wBc1] d3#
b) 90 grad: 1.bxa5[+wBc1] Rb4 2.axb4[+wRa1] Be3#
Very rich content with a rebirth of both battery pieces by one black piece. The construction is by many pawns rather heavy.
EN <-> RU

4th Honorable mention - No 16, Anatoly Vasilenko (Ukraine) 8/8/3K4/8/3kr3/3q4/2PB4/2N2b2

a) diagram: 1.Qb5 c4 (tempo) 2.Bxc4[+wPc2] c3#
b) 180 grad: 1.Qxf7[+wPf2] f3 (tempo) 2.Bf5 f4#
Tempo moves of the wPc2 as a double and a single step. This is a refreshingly original idea, unfortunately with repetition of the bishop’s block.
EN <-> RU

5th Honorable mention - No 20, Misha Shapiro (Israel) 5b2/qPpK4/6P1/4ppp1/3ppk1n/2p1n1r1/1Pp5/rb2N3

a) diagram: 1.Rg3-g4 b7-b8S 2.Qa7*b8[+wSg1] Sg1-e2#
b) 90 grad: 1.Sc4-d2 b7*a8B 2.Qg8*a8[+wBf1] Bf1*e2[+bPe7]#
c) 180 grad: 1.Kc5-b5 g7*h8R 2.Qh2*h8[+wRa1] Ra1*a5[+bSb8]#
d) 270 grad: 1.Rf7-e7 c7-c8Q 2.Ba6*c8[+wQd1] Qd1*d5#
Without the repetition rook block in d), we would have placed this AUW a little higher, despite of all 16 black pieces and only three Circe mates.
EN <-> RU
1st Commendation - No 28
Ingemar Lind
TT-177, SuperProblem, 21-12-2016
1r6/6p1/6r1/4pq2/1R2n1pk/6p1/4P3/4K3
h#2b) 270 grad
Circe
(3+9)
2nd Commendation - No 23
Michel Caillaud
TT-177, SuperProblem, 21-12-2016
8/1P1K4/6q1/7k/5B2/8/1r2Nb2/8
h#2b) 90 grad
Circe
(4+4)
3rd Commendation - No 11
Jacques Rotenberg
TT-177, SuperProblem, 21-12-2016
8/K3p1P1/8/4k1q1/1n6/8/1P6/8
h#2b-d) 90, 180, 270 grad
Circe
(3+4)

1st Commendation - No 28, Ingemar Lind (Sweden) 1r6/6p1/6r1/4pq2/1R2n1pk/6p1/4P3/4K3

a) diagram: 1.Rb8*b4[+wRa1] 0-0-0 2.Rg6-g5 Rd1-h1 #
b) 270 grad: 1.Qd6-d7 Re2*a2[+bRa8] 2.0-0-0 Ra2-a8 #
Castling were also to be expected for the theme, here the long castling by white and black, initiated by reciprocal captures of the rooks and decorated with dual avoiding blocks of bR/bQ.
EN <-> RU

2nd Commendation - No 23, Michel Caillaud (France) 8/1P1K4/6q1/7k/5B2/8/1r2Nb2/8

a) diagram: 1.Bh4 b8Q 2.Rxb8[+wQd1] Sg3#
b) 90 grad: 1.Rxb4[+wSg1] g8R 2.Bxg8[+wRh1] Sf3#
Nice change of promotion queen/rook with rebirth of battery rear piece and double check.
EN <-> RU

3rd Commendation - No 11, Jacques Rotenberg (France) 8/K3p1P1/8/4k1q1/1n6/8/1P6/8

a) diagram: 1.Kd4 g8Q 2.Qe3 Qd5#
b) 90 grad: 1.Ke3 b8Q 2.Sxb8[+wQd1] Qd4#
c) 180 grad: 1.d1S g8Q 2.Se3 Qd5#
d) 270 grad: 1.Kc6 b8Q 2.Qb7 Qd6#
Varied solutions with four times Circe mates. Four queen-promotions are, of course, much easier to implement than an AUW.
EN <-> RU
4th Commendation - No 3
Michael Barth
TT-177, SuperProblem, 21-12-2016
8/8/1K6/1b1r4/1p1kn3/1P1Np3/3p4/5q2
h#2b) 270 grad
Circe
(3+8)
5th Commendation - No 35 (version)
Dan-Constantin Gurgui
TT-177, SuperProblem, 31-12-2016
7k/4p2r/6n1/8/6K1/8/8/7R
h#2b) 90 grad
Circe
(2+4)
6th Commendation - No 15
Igor Kochulov
TT-177, SuperProblem, 21-12-2016
5r2/1P4K1/r7/2p1k3/8/8/8/8
h#2b) 90 grad
Circe
(2+4)

4th Commendation - No 33, Michael Barth (Germany) 8/8/1K6/1b1r4/1p1kn3/1P1Np3/3p4/5q2

a) diagram: 1.Qxd3[+wSb1] (1.Bxd3?) Sc3 2.bxc3[+wSg1] Sf3#
b) 270 grad: 1.Bxf4[+wSg1] (1.Qxf4?) Sf3 2.gxf3[+wSb1] Sc3#
After rebirth the white knight with the right piece, he has to be captured again. Rather simple, but homogenous strategy.
EN <-> RU

5th Commendation - No 35 (version), Dan-Constantin Gurgui (Romania) 7k/4p2r/6n1/8/6K1/8/8/7R

a) diagram: 1.Sf8 Rxh7[+bRa8]+ 2.Sxh7[+wRh1] Rxh7[+bSg8]#
b) 90 grad: 1.Kg2 Rf1 2.Kxf1[+wRh1] Rxg1[+bRh8]#
A funny miniature with rebirth of the black knight in a), which blocks in both phases a square and rebirth of the white rook for the final mate in b).
EN <-> RU

6th Commendation - No 15, Igor Kochulov (Russia) 5r2/1P4K1/r7/2p1k3/8/8/8/8

a) diagram: 1.Raa8! (Rfa8?) bxa8Q 2.Rf4 Qd5#
b) 90 grad: 1Rhh8! (Rfh8?) gxh8Q 2.Rf5 Qd4#
Charming six piece problem with dual avoidance (the right rook has to sacrifice itself, so that the other can block), two Circe echo model mate.
EN <-> RU
7th Commendation - No 8
Dieter Müller
TT-177, SuperProblem, 21-12-2016
8/8/4B3/4k2N/1N2r3/8/rRp5/7K
h#2b) 270 grad
Circe
(5+4)
8th Commendation - No 40
Ralf Krätschmer
TT-177, SuperProblem, 21-12-2016
8/1P3rP1/1r4p1/8/8/2K1p1k1/1P2pNb1/8
h#2b-d) 90, 180, 270 grad
Circe
(5+7)

7th Commendation - No 8, Dieter Müller (Germany) 8/8/4B3/4k2N/1N2r3/8/rRp5/7K

a) diagram: 1.Ra2*b2[+wRa1] Ra1-a6 2.Rb2*b4[+wSg1] Sg1-f3#
b) 270 grad: 1.Re5*e2[+wSb1] Sb1-d2 2.Re2*g2[+wRh1] Rh1-h5#
A nice presentation of reciprocal change and model mates.
EN <-> RU

8th Commendation - No 40, Ralf Krätschmer (Germany) 8/1P3rP1/1r4p1/8/8/2K1p1k1/1P2pNb1/8

a) diagram: 1.Kg3*f2[+wSg1] b7-b8Q 2.Rb6*b8[+wQd1] Qd1-e1 #
b) 90 grad: 1.Kc2-c3 g7-g8Q 2.Rg3*g8[+wQd1] Qd1-c2 #
c) 180 grad: 1.Kb6-c6 g7-g8Q 2.Rg3*g8[+wQd1] Qd1*d6 #
d) 270 grad: 1.Kf7-e8 b7-b8Q+ 2.Rb6*b8[+wQd1] Qd1-d7 #
Fourfold queen promotion, good use of wS in all four phases.
EN <-> RU


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F# (fairies | сказки)

Participants | Участники

Argirakopoulos T. – No 2
Barth M. – No 33
Caillaud M. – No 23
Gurgui D. – No 34, 35, 37
Kerhuel M. – No 24
Kochulov I. – No 14, 15
Krätschmer R. – No 1, 40, 41
Lind I. – No 25, 26, 27, 28, 29, 30
Lörinc J. – No 19
Müller D. – No 3, 4, 5, 6, 7, 8, 9, 38, 39
Navon E. – No 36*
Parrinello M. – No 21, 22
Rotenberg J. – No 10, 11, 12
Shapiro M. – No 20
Shorokhov B. – No 13
Tar G. – No 17, 18
Vasilenko A. – No 16
Witztum M. – No 31, 32, 36*

The Winner Is | Победитель

Juraj Lörinc
Congratulations! | Поздравляем!

Judges | Арбитры

Franz Pachl

Rainer Kuhn

Director and editor
Директор и редактор

Aleksey Oganesjan
e-mail: alexeioganesyan@gmail.com

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