Moremovers - SuperProblem 2025 Informal Tourney - Многоходовки
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Entries should be sent to director of the section not later than 1st December 2025
Note! Not more than 3 originals per one author, including joint works, may be published; versions - unlimited.
Задачи направляйте директору раздела не позднее 1 декабря 2025 годаNote! Not more than 3 originals per one author, including joint works, may be published; versions - unlimited.
Важно! Могут быть опубликованы не более трех задач одного автора, включая совместные произведения; версии - неограниченно.
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C488 (solution | решение)
Jayakumar Vellavoor(India)83p2p12pPk1Pp2P1P1pK2N3P16B13N
1. Be1! Kd5 2. Bf2 Ke6 3. Sb6 Kxe5 4. Sa8 Kd5/Ke6/Kf4 5. Sc7 Ke5 6. Be3 Kf6 7. Bd4#C489 (solution | решение)
Daniele Gatti (Italy)8/2p5/2p5/K1P3R1/2p5/k1p2P1P/2Q1P1pp/6N1
1. Rg4! [threat 2. Rxc4 [threat 3. Ra4, Rxc3#]1. ... hxg1=Q 2. Rxc4 [threat 3. Ra4, Rxc3#]
2. ... Qd4 3. Rxd4 [ad lib. 4. Ra4#]
2. ... Qxc5+ 3. Rxc5 [ad lib. 4. Rxc3#]
1. ... h1=B 2. Qb1 [zugzwang]
2. ... c2 3. Qxc2 [zugzwang]
3. ... c3 4. Ra4#
C490 (solution | решение)
Daniele Gatti (Italy)8/8/2p5/2p5/1p3N2/3p1NPP/pPpPRP2/R3K2k
1. Re4! [zugzwang]1. ... c4 2. Rxc4 [threat 3. Rxc2 [threat 4. O-O-O#] 3. ... dxc2 4. Ke2+ c1=Q 5. Rxc1#]
2. ... b3 3. Rc5 [zugzwang]
3. ... c1=Q+ 4. Rcxc1 [zugzwang]
4. ... c5 5. Rc3 [ad lib. 6. O-O-O#]
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C491 (solution | решение)
Daniele Gatti (Italy)B5rr/1P3p1N/kP6/P5N1/1K4P1/8/8/8
Try: 1. Se4? [ad lib. 2. Sc5#]But 1. ... Rxg4!
Solution: 1. Sf8! [threat 2. b8=S#]
1. ... Rxf8 2. Se4 [threat 3. Sc5#]
2. ... Rc8 3. b8=S+
3. ... Rxb8 4. Sc5#
2. ... Rh5 3. gxh5 [threat 4. Sc5#]
3. ... Rc8 4. bxc8=Q/B#
C492 (solution | решение)
Jayakumar Vellavoor(India)8/8/8/3B4/8/1p1kNp2/1P1N1P2/3K4
1. Sdc4 Kd4 2. Kd2 Kc5 3. Kc3 Kb5 4. Bb7 Kc5 5. Sd5 Kb5 6. Kd4 Ka4 7. Bc6#C493 (solution | решение)
Jayakumar Vellavoor(India)8/5p2/pN1k1P1p/1p1P1B1P/1P1P1p1K/p1N2P2/P4B2/8
1. Sa8! a5 2. Kg4 a4 3. Bg3 fxg3 4. Kf4 g2 5. Ke4 g1Q 6. Sxb5#Лишняя пешка f3(Валерий Смирнов)
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C494 (solution | решение) withdrawal | исключается
Béla Majoros (Hungary)1k6/3K4/B7/B7/8/8/8/8
1. Bc8! Ka7 2. Kc7 Ka8 3. Bb7+ Ka7 4. Bb6#1. - Ka8 2. Kc7 Ka7 3. Bb6+ Ka8 4. Bb7#
Полный предшественник - yacpdb/134747
C495 (solution | решение)
Arjun Naranganam (India)8/3p2p1/2pNk1N1/2P1P1K1/1B6/8/8/8
1. Kf4! Kd5 2. Ke3 Ke6 3. Ba3 Kd5 4. Nf4+ Kxe5 5. Bb2#C496 (solution | решение)
Arjun Naranganam (India)4B3/1p1Nk3/2pNP3/2P1K1P1/3B4/1p6/8/8
1. Kf5? ~ 2. Bf6# 1. ... Kd8!1. Sf7?(2. Kf5 (3. Bf6+ Kxe8 4. Sd6#)) 1. ... b2!
1. Bb2! zz
1. ... b6/b5 2. cxb6(e.p.) Kd8 3. Kf6 ~ 4. e7#
2. ... c5 3. Kd5 Kd8 4. Bf6#
1. ... Kd8 2. Kf6 Kc7 3. Ke7 b6/b5 4. cxb6#
2. ... b6/b5 3. cxb6(e.p.) ~ 4. e7#
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C497 (solution | решение)
Nikolaj Zujev(Lithuania)8/3K4/8/3kNR2/8/4P3/5N2/8
1. Rf4? ~ 2.Se4 Kxe5 3.Sd2/Sd6 Kd5 4.Rf5#1. ... Kc5!
1. Rf8! (2. Re8 Kc5 3. Rb8 Kd5 4. Rb5#)
1. ... Kxe5 2. Ke7 Kd5 3. Rc8 Ke5 4. Rc5#
C498 (solution | решение)
Arjun Naranganam (India)3BB3/2N5/3k4/1p6/1P6/1K1p2p1/3P2P1/8
1. Kc3! Ke5 2. Bd7 Kd6 3. Bc8 Kc6/e5 4. Se8 Kd5 5. Bd7 Ke4/e5 6. Bc7+ Kd5/e4 7. Sf6#(mm)Версия без 2-х пешек - 3BB3/2N5/3k4/1p6/1P6/1K3p2/5P2/8 (Валерий Смирнов)
C499 (solution | решение)
Nikolaj Zujev(Lithuania)1K6/8/8/1p6/2k5/4Q3/4N3/8
1. Kb7(Ka7)? zz Kb4 2. Qc3+ Ka4 3. Sd4 zz b4 4. Qa1#1. ... Kd5!
1. Kc8? zz
1. ... Kb4 2. Qc3+ Ka4 3. Sd4 zz b4 4. Qa1#
1. ... Kd5 2. Kd7 Kc4 3. Qc3+ Kd5 4. Qd4#
1. ... b4!
1. Kc7! zz
1. ... Kb4 2. Qc3+ Ka4 3. Sd4 zz b4 4. Qa1#
1. ... Kd5 2. Kd7 Kc4 3. Qc3+ Kd5 4. Qd4#
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C500 (solution | решение)
Antonio Tarnawiecki (Peru)8/3B2p1/3kp1Pp/2N4R/2P3P1/4B2P/3K3P/6N1
1.Re5!1…Kxe5 2.Sxe4 Kxe4 3.Sf3 Kxf3/e5/h5 4.Bc6#
2…h5 3.Sf3+ Kxe4 4.Bc6#
1…Kc7 2.Rxe6 Kb8 3.Bf4+ Ka7/Ka8 4.Ra6#
2…Kd8 3.Bf4 e3/h5 4.Re8#
2…h5 3.Bf4+ Kd8 4.Re8#
1…Ke7 2.Rxe6+ Kd8 3.Bf4 e3/h5 4.Re8#
1…h5 2.Rxe6+ Kc7 3.Bf4+ Kd8 4.Re8#
C501 (solution | решение)
Yuri Arefiev (Russia)BK6/1np1p1kP/5R1p/4B1pp/6pR/8/6b1/6rq
Более сложный механизм “мельницы” – “Двухсторонняя мельница” (Double-sided mill) (Есть также логика в выборе шахующих ходов белой ладьи)(1. Ra-b-…, Rf1-f2..+?)
1. h8Q+! Kxh8 2. Rg6+ (2. Rxe7+? Kg8 3. Rg7+ Kf8!… - сначала надо подключить Rh4, а потом уже Ba8)
2. … Kh7 3. Rg7+ Kh8 4. Rxg5+ Kh7 5. Rg7+ Kh8 6. Rgxg4+ Kh7 7. Rg7+ Kh8 8. Rf4!(ещё рано 8. Rxg2+?…) Rf1 9. Rxe7+ Kg8 10. Rg7+ Kh8 11. Rxc7+ Kg8 12. Rg7+ Kh8 13. Rxb7+ Kg8 14. Rg7+ Kh8 15. Rxg2+ Kh7 16. Be4#
C502 (solution | решение)
Sunila Kavunkal (India)1kr5/8/PP6/4N3/1p6/1K6/8/8
1. Sd7+ Ka8 2. b7+ Ka7 3. bxc8R. Kxa6 4. Rb8 Ka7 5. Kxb4 Ka6 6. Kc5 Ka7 7. Kc6 Ka6 8. Ra8#4. ... Ka5 5. Rb7 Ka6 6. Sc5+ Ka5 7. Kc4 b3 8. Rb5#
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C503 (solution | решение)
Sunila Kavunkal (India)4N3/8/8/3k4/3N4/P2KP3/1B6/8
1. Bc3 Kc5 2. Ba5 Kd5 3. Bb4 Ke5 4. Bd6+ Kd5 5. e4# (model)C504 (solution | решение)
Sunila Kavunkal (India)8/Q7/8/3p4/bp6/k7/1p6/1K6
1.Qa6 d4 2.Qc4 Bc2+ 3.Kxc2 b1Q+ 4.Kxb1 b3 5.Qc5 Ka4 6.Kb2 d3 7.Kc3 ~ 8.Qb4#C505 (solution | решение)
Luis Echemendia (Spain)2N4B/8/2Bpk1K1/5p2/2p2p2/3p1P2/3P4/8
1. Sb6? d5!1. Ba1?/Bg7? d5!
1. Bd4! zz
1. ... d5 2. Kg7 c3 3. Kf8 c2/cxd2 4. Ke8 ~ 5. Bd7#
1. ... c3 2. Bxc3 d5 3. Bh8 d4 4. Kg7 Ke5 5. Kf7#
Circuit de Fou Coin à coin (diagonal)
Circuit linéaire
Circuit blanc
Indien
Batterie royale
Batterie blanche
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C506 (solution | решение)
Luis Echemendia (Spain)8/8/8/2R5/4Nk2/5p2/2K2N2/8
1. Rc6? Ke3!1. Sc3? Kg3!
1. Rg5! Ke3 2. Sc3
2. ... Kxf2 3. Kd2 Kf1 4. Sd1 f2 5. Se3#
2. ... Kd4 3. Sd3 Ke3 4. Re5+ Kd4 5. Re4#
3. ... f2 4. Re5 Kc4 5. Re4#
2. ... Kf4 3. Sh3+ Ke3 4. Rd5 ~ 5. Rd3#
Есть дефектный предшественник- yacpdb/418814
C507 (solution | решение)
Luis Echemendia (Spain)8/3Np1KB/2p1p2p/1pP3k1/1P4p1/1P4p1/2N3P1/8
1. Sf8! (2. Sxe6+…)1. ... h5 2. Bd3 Kf4 3. Sg6+ Kg5 4. Sd4(5. Sxe6#) h4 5. Sxe6+ Kh5 6. Sgf4#
1. ... Kf4 2. Kxh6 Ke5 3. Kg5 Kd5 4. Sd7 e5 5. Sb6+ Ke6 6. Bg8#
C508 (solution | решение)
Petrašinović Petrašin(Srbija)8/7Q/4p3/3k4/8/K2P2P1/8/4B3
1.Qe4?1...Kc5 2.Qxe6 Kb5 3.Bf2+ Ka5 4.Qb6#
2...Kd4 3.Qf5 Ke3 4.Qe4#
but: 1...Kd6!
1.Qc7?, Kd4; 1.Bb4?, Kc6!
1.Ba5!
1...Kc6 2.Qc7+ Kd5 3.Bb6 ~ 4.Qc5#
3...e5 4.Qd7#
1...Kd4 2.Qe4+ Kc5 3.Bc7 ~ 4.Qc4#
1...Kc5 2.Qd7 e5 3.Kb3 e4 4.d4#
1...Kd6 2.Qc7+ Kd5 3.Bb6 ~ 4.Qc5#
3...e5 4.Qd7#
1...Ke5 2.Bb4 ~ 3.Qg6 Kd4/Kd5 4.Qe4#
2...Kf6 3.Be7+ Ke5 4.Qe4#
1...e5 2.Qd7+ Kc5 3.Kb3 e4 4.d4#
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C509 (solution | решение)
Bosko Miloseski (Macedonia)8/8/2P5/4BRP1/2p1BP2/2Pp2pp/3Pp1pp/4K2k
1.Be5-d4? ?? Stalemate1.Be5-b8! Kh1-g1 2.Bb8-a7 Kg1-h1 3.R5-c5 Kh1-g1 4.Rc5-b5 Kg1-h1 5.Rb5-b6 Kh1-g1 6.Rb6-b1 Kg1-h1 7.Ba7-f2! g3*f2 8.Ke1*f2 e2-e1=Q 9.Rb1*e1#
- Zabunov battery
- Herlin manoevre
- Active sacrifice
C510 (solution | решение)
Luis Echemendia (Spain)2B1N3/4p3/1K6/1p1kp1p1/2p2p2/2P2P2/2P5/4N3
1. Bf5!1. ... b4 2. Sc7+ Kd6 3. Sb5+ Kd5 4. Sd3 [5. Sxb4#]. cxd3 5. c4+ Kxc4 6. Be6#
1. ... g4 2. Sd3 [3. Sb4#] cxd3 3. cxd3 gxf3/g3/b4 4. Sc7+ Kd6 5. Sxb5+ Kd5 6. c4#
Echange des 2° et 4° coups blancs
Switchback noir
Switchback de Roi
Umnov différé
Sacrifice blanc
