Award in SuperProblem - 2017 Informal Tourney | Helpmates

Итоги годового конкурса SuperProblem - 2017 | Коопматы

Published: February 14, 2018
Опубликовано: 14 февраля 2018

Section H#2 | Задачи на коопмат в 2 хода

First of all, I would like to thank the editor for giving me the honor of judging this tournament on the SuperProblem site and also for the collaboration, having reported several compositions to be compared with the published ones.

69 helpmates in two took part the tournament: the general level was good enough but lower what I thought.

List of participating problems : E401 (E401a), E402, E403, E405, E406, E408, E409, E410, E415, E416 (E416a), E417, E422, E424, E425, E428, E430, E431, E432, E433, E436, E437, E439, E448, E448a, E450, E453, E454, E457, E460, E461, E465 (E465a, E465b), E469, E470, E476, E477, E478, E480, E481 (E481a), E482, E483, E494, E496, E525, E526, E530, E534 (E534a), E535, E536, E539, E542, E543, E544, E551, E552, E553, E554, E556, E557, E559, E560, E566, E567, E568.

Before moving on to the ranking, it is right I motivate my choices with comments on some of the problems I did not selected. Regarding others not mentioned below, I think they have a too simple or unbalanced content.
E403 - Improvement of a problem by the same author: ycpdb/361341. I see enough differences to justify the publication, but not for recognition.
E408 - This HOFT is enjoyable, but the four solutions are simple.
E415 - This problem has certainly deserved the publication for the presence of the 4 bR moves in B1, but there are many similarities with the helpmate of the three co-authors (see ycpdb/384875), of which is obviously a version.
E422 - Tempo move only in one solution.
E428 - It doesn’t convince me. Three pairs of solutions, each pair with simply the inversion of black moves and identical play.
E430 - The solutions are rather similar.
E432 - Familiar mixed AUW.
E436 - White promoting pawns are used in turn. I prefer the CJ Feather problem published together with the solution.
E437 - Linear content with concurrent mates.
E450 - Symmetrical.
E454 - The strategy is rather familiar. Despite the dual avoidance, the black inversion of moves it’s a simple mechanism, in my opinion, which produces two identical mate positions. The extra solution has only a few elements in common with the first two (selfblock, battery mate) and it doesn’t increase the problem value.
E457 - Well known strategy in twin form.
E460 - Nice but familiar Grimshaw and concurrent mates.
E461 - The position is legal also with a bPe7 for the bSf7. 6bq/1p2p3/1p4Q1/bp2N2p/nkpK4/p1p5/2P5/8
E465, E465a, E465b - A possible improvement of economy: b7/4Brpn/3b2kN/R2N2pp/5P2/8/8/7K
E470 - Anticipated by Árpád Molnar, Magyar Sakkszövetség 1965, 3rd HM (see yacpdb/44471).
E476 - The part a) is acceptable, with Zilahi, Kniest, distant blocks, but part b) is rather symmetrical and schematic.
E478 - The effects in the wPP moves are not really attractive and the content is rather unbalanced.
E481 - Unbalanced, improved by the version.
E481a - The battery play is familiar.
E482 - Version by Vidadi Zamanov, Wola Gułowska 2016-12, Comm. (See yacpdb/422655)
E525 - The bQe8 can be removed.
E530 - I think this idea should be developed without the black interferences in B2, to avoid so the use of the two BB in turn.
E539 - Can be compared with yacpdb/444282 and also with P1269818
E544 - It would have been better to develop this idea in 3 moves with two solutions.
E551 - Nice miniature with two Anderssen mates in the same square, but I think it’s a little bit for a recognition.
E553 - The mates on the same line feel simple. The strategy can be compared to P0577761
E557 - In my opinion, the announced cycle did not succeed well, because the move in e6 is always in B1 and that in e5 in B2.
E559 - The Zilahi matrix is like the following: yacpdb/404403
E560 - Substantially the same matrix of Christer Jonsson, ASIGC 2011-12 (see yacpdb/404253), with two more solutions.
E566 - The absence of castle in d) takes away all charms.

1st Prize - E417
Fadil Abdurahmanović
SuperProblem, 19-01-2017
white Qg2 Pf2a2 Rc1 Ba1 Kh3 black Qd1 Pb5h7h5f4e4d2b7b6 Sd7b3 Bc8 Kd5
2nd Prize - E542
Christer Jonsson & Rolf Wiehagen
SuperProblem, 16-11-2017
white Qd3 Pc4 Ke5 black Be3 Kg1 Qb8 Ph4f5c3 Se8d6 Rh5e1
h#2b) Kg1->h7, c) Kg1->b6(3+10)
3rd Prize - E526M. Dragoun,
L. Salai jr., E. Klemanič, J. Kovalič
SuperProblem, 29-10-2017
white Qe1 Pb4f5 Ke3 Ra8f4 Ba2a3 black Ba5h5 Kf8 Qc8 Pc3g3g7g6 Sa7 Rb8d5

1st Prize - E417 Fadil Abdurahmanović (Bosnia and Herzegovina)2b5/1p1n3p/1p6/1p1k3p/4pp2/1n5K/P2p1PQ1/B1Rq4

1.Sb3-c5 Ba1-e5 2.Kd5-c6 Qg2*e4 # {,} 1.Sb3-d4 Rc1-c6 2.Kd5-e5 Qg2-g5 # {,
 } 1.Sb3*c1 Qg2-g7 2.Kd5-c4 Qg7-d4 # {,} 1.Sb3*a1 Qg2-g6 2.Kd5-d4 Qg6-d6 #

A very elegant HOTF problem, which shows a duel where the wQ is opposed to a bS and to the bK, in diagonal-orthogonal echo. In two solutions the bS interferes one of two white pieces, while the other moves in W1 in turn, for a nice ASP play, obviously with pin mate. In the other two solutions the bS captures one of the same white pieces in turn, to open so a flight to the king.

2nd Prize - E542 Christer Jonsson (Sweeden) and Rolf Wiehagen (Germany)1q2n3/8/3n4/4Kp1r/2P4p/2pQb3/8/4r1k1

a) 1.Kg1-h1 Qd3*e3 {(Qxf5? 2.Rg1 Qh3#??)} 2.Re1-g1 Qe3-h3 # {,
   } b) bKg1-->h7 1.Kh7-h8 Qd3*f5 {(Qxd6? 2.Rh7 Qf8#??)} 2.Rh5-h7 Qf5-f8 # {,
   } c) bKg1-->b6 1.Kb6-a5 Qd3*d6 {(Qxe3? 2.Qb4 Qa7#??)} 2.Qb8-b6 Qd6-a3 #

This problem stands out for the cyclical dual avoidance for white selfpin, followed by direct unpin of the wQ with selfblock. The cyclically changed functions of Qb8/Re1/Rh5, the black FML, and the model mates are very appreciable in the whole. Pity the two choices in c) involve different mates, so there is not the cyclical form for those. The helpmate P1343384 reported for comparison is very complex, with once again three wQ moves. However its strategy is different from that of E542. In that problem every promotion allows a different selfpin move by the wQ, then the promoted piece unpins the wQ.

3rd Prize - E526 Michal Dragoun (Czechia), Ladislav Salai jr., Emil Klemanič, Ján Kovalič (all three Slovakia)Rrq2k2/n5p1/6p1/b2r1P1b/1P3R2/B1p1K1p1/B7/4Q3

1.Rd5-d3 + Ke3*d3 2.Rb8*b4 {(Qxf5+?)} f5*g6 # {,} 1.Rd5-d4 Ke3*d4 2.Qc8*f5 {(Rxb4+?)} b4*a5 #

Two white direct batteries and a black halfpin are visible in the position. Black sacrifices to play the wK and thus allow the wQ to guard the “e” file. The position taken by the wK determines which of the two pieces of the half-battery selfpins by capturing the front pieces of one of the batteries. Then the other battery fires and mates exploiting the double pin.

4th Prize - E439
Vitaly Medintsev
SuperProblem, 23-03-2017
white Pf3g5 Kh2 Bb2c4 Sc6c7 black Qa3 Pa2c5a5h6b6 Kf5 Bd8b1 Rh7h8
5th Prize - E401
Anatoly Skripnik
SuperProblem, 04-01-2017
white Rd8 Kb2 Bb4 Sf2c5 black Bd1 Ke5 Qd3 Pg4c2 Sd6 Rd2
1st Honorable Mention - E536
Viktor Yuzyuk
SuperProblem, 10-11-2017
white Pf5b5g7d7a7 Ka1 black Bg8 Kd4 Qa8 Pe3d3c3 Sh7c8 Re5c5

4th Prize - E439 Vitaly Medintsev (Russia)3b3r/2N4r/1pN4p/p1p2kP1/2B5/q4P2/pB5K/1b6

1.Bb1-c2 Bb2-c1 2.Bc2-b3 Bc4-d3 # {(1.Bd3? Bc1 2. Qd3??/Qb2+ Bxd3#?? , 1.Qd3? Bc1 2.Bd3??)
 } 1.Bd8-f6 Sc7-e6 2.Bf6-g7 Sc6-e7 # {(1.Re7? Se6 2.Be7??/Bc7+ Sxe7#?? , 1.Be7? Se6 2.Re7??)}

Each of the mating squares is guarded by two black pieces. If one of these sacrificed itself in B1 by a move in that square, the other would have no useful moves in B2 to abandon the guard, in turn. So one of these pieces moves instead twice to interfere the other. I like also that the four white pieces change their roles in cyclical form: this increases the artistic value of the problem, even if there are no model mates.

5th Prize - E401 Anatoly Skripnik (Russia)3R4/8/3n4/2N1k3/1B4p1/3q4/1Kpr1N2/3b4

1.Sd6-f5 {(A)} Rd8-d6 {(a)} 2.Rd2-e2 {(B)} Sc5*d3 # {(b),} 1.Rd2-e2 {(B)} Bb4-d2 {(c)} 2.Sd6-f5 {(A)} Sf2*g4 # {(d),} 1.Qd3-c4 {(C)} Sc5-d3 + {(b)} 2.Ke5-d5 {(D)} Rd8*d6 # {(a)}

I found only a few helpmates in two where the inversion of black moves and the inversion of white ones are combined in three solutions as shown in this problem. None of these, moreover, is closely enriched by Umnov effects as it happens in the three solutions of E401. Regarding the version E401a, there are no important changes in it, so I referred to the E401 for my evaluations.

1st Honorable Mention - E536 Viktor Yuzyuk (Ukraine)q1n3b1/P2P2Pn/8/1Pr1rP2/3k4/2ppp3/8/K7

1.Kd4-d5 Ka1-b1 2.Kd5-d6 d7-d8=Q # {,} 1.Qa8-d5 a7-a8=Q 2.Kd4-c4 Qa8-a4 # {,} 1.Bg8-d5 g7-g8=Q 2.Kd4-e4 Qg8-g4 # {,
 } 1.Sh7-f8 g7*f8=Q 2.Rc5-d5 Qf8-b4 # {,} 1.Qa8-b8 a7*b8=Q 2.Re5-d5 Qb8-f4 #

Five solutions with promotion to Q and five moves in the same square are surely an remarkable result, but it detracts that the latter are divided between B1 and B2. Also the symmetry does not recommend me to assign a higher place to this problem.

2nd Honorable Mention - E431
Luis Miguel MARTÍN
SuperProblem, 08-03-2017
white Qe1 Pa5 Kf1 Ra8c8 black Se2f2 Pd6b5e4c3e3b2 Kb7 Rf5b1 Bc4
3rd Honorable Mention - E477
János Csák
SuperProblem, 16-07-2017
white Qa3 Pb5 Se5e4 Kb4 black Kf5
h#22.1.. b) Qa3->a6 2.1..(5+1)
4th Honorable Mention - E409
Yuri Gorbatenko
SuperProblem, 10-01-2017
white Qh6 Ra3 Kc7 Ba2 Pc3c4 black Bd5 Kf5 Qe4 Pe6f3 Sg4 Rd3e5

2nd Honorable Mention - E431 Luis Miguel MARTÍN (Spain)R1R5/1k6/3p4/Pp3r2/2b1p3/2p1p3/1p2nn2/1r2QK2

1.Se2-c1 + Qe1-e2 2.Bc4-d5 Qe2*b5 # {,} 1.Sf2-d1 + Qe1-f2 2.Rf5-d5 Qf2-f7 #

Indirect white unpin with the check to specify the line where the wQ has to move; selfpin, direct unpin with interference. Altogether, an unusual presentation of the Grimshaw theme in two solutions with diagonal-orthogonal echo.

3rd Honorable Mention - E477 János Csák (Hungary)8/8/8/1P2Nk2/1K2N3/Q7/8/8

a) 1.Kf5*e5 Se4-f6 2.Ke5-d4 Qa3-c3 # {,} 1.Kf5*e4 Qa3-f3 + 2.Ke4-d4 Se5-c6 # {,
   } b) wQa3-->a6 1.Kf5*e5 Qa6-f6 + 2.Ke5-d5 Se4-c3 # {,} 1.Kf5*e4 Se5-f3 2.Ke4-d5 Qa6-c6 #

Very fine rex-solus with only six units, with analogies in the moves of the wQ and the two wS, playing both W1 and mates in the same squares. The Zilahi is part of this mechanism and it is due to the moves of the bK, which captures the piece in turn redundant. Such strategy makes the E477 a happy insight.

4th Honorable Mention - E409 Yuri Gorbatenko (Russia)8/2K5/4p2Q/3brk2/2P1q1n1/R1Pr1p2/B7/8

1.Bd5*c4 Ra3-a5 2.Bc4-a6 {(Bb5?)} Ba2*e6 # {,} 1.Rd3*c3 Ba2-b1 2.Rc3-c1 {(Rc2?)} Ra3*f3 #

Nice line opening effects in diagonal-orthogonal echo with dual avoidance for self-unpin.

5th Honorable Mention - E405
Emanuel Navon
SuperProblem, 07-01-2017
white Pc6b4g6 Sc5f8 Ke8 black Pd6c4d4g7d7 Kd5 Rh5 Se6 Ba8
h#2b) Pd7<-->Se6(5+8)
6th Honorable Mention - E424
Zivko Janevski
SuperProblem, 10-02-2017
white Pc6 Kh2 Rd6 Bc7 black Qc2 Pe7f7g6f5h3d2d4c4 Ke5 Rg5d3 Bd5a7
Special Honorable Mention - E425
Fadil Abdurahmanovic
SuperProblem, 12-02-2017
white Pb2a3 Sg1 Ra1 Ke1 black Pe5e4e3h3g3g2c4 Kd4 Bh2a2 Sa6
h#2*vset play, try play(5+11)

5th Honorable Mention - E405 Emanuel Navon (Israel)b3KN2/3p2p1/2Ppn1P1/2Nk3r/1Ppp4/8/8/8

a) 1.d7*c6 {(Bxc6? Sfxd7 - Sfxe6 2. Re5)} Sf8-d7 {(Sfxe6?)} 2.Rh5-e5 Sd7-b6 # {,
   } b) bPd7<-->bSe6 1.e6-e5 {(Re5? Sfxe6 - Sfxd7 2. Bxc6)} Sf8-e6 {(Sfxd7?)} 2.Ba8*c6 Se6-c7 #

A good example of black and white dual avoidance. Black must choice carefully the units to block the squares c6 or e5, to avoid the wS selfpins in W1. Also the wS has two choices in its first move, but one fails in turn for anticipatory white selfpin.

6th Honorable Mention - E424 Zivko Janevski (Macedonia)8/b1B1pp2/2PR2p1/3bkpr1/2pp4/3r3p/2qp3K/8

1.Bd5-e6 Rd6-d5 + 2.Ke5-f6 Bc7-e5 # {,} 1.Bd5*c6 Rd6-e6 + 2.Ke5-d5 Re6-e5 # {,
 } 1.Bd5-f3 Kh2*h3 2.Ke5-f4 Rd6-e6 # {,} 1.Rd3-f3 Kh2-h1 2.Qc2-e4 Rd6*g6 #

Two pairs of connected solutions with battery play. After a selfblock the battery fires and one of the battery piece in turn moves to mate in the square left by the bK. On the other side, mutual black interferences to play the wK and battery mate.

Special Honorable Mention - E425 Fadil Abdurahmanovic (Bosnia and Herzegovina)8/8/n7/4p3/2pkp3/P3p1pp/bP4pb/R3K1N1

{set play:} 1...a3-a4 {!!(tempo)} 2.Kd4-d3 0-0-0 # {# (Rd1?),} 1.Sa6-b4 a3*b4 2.Bh2*g1 {!(tempo)} Ra1-d1 # {(0-0-0?!!)
    try play:} 1.Kd4-d3 0-0-0 # {# ??    0-0-0 is not legal!

The Retro elements with Castle-not Castle are nice, but the real point of interest is that white has a tempo move in set play and black instead in the actual play. As the author rightly comments, this is the very unusual anti-form of the Lindner theme. This problem is an improvement of another already published (see: yacpdb/391748 - editorial), so I had to decide whether to reward it or not, and if so, how to place it. By comparing E425 with its predecessor, we note a certain similarity, but also some important differences: first of all, in the Orbit helpmate there is no real black tempo in set play. Moreover, E425 is appreciable because all white force has a role in both phases: in particular the wPa3 moves both in set and in actual play. At the end, I opted for a special Honorable mention, that should be enough to highlight the problem. Although some constructive choices in the use of black material can be criticized, the author has motivated them following the discussion on the problem and I consider them secondary to the importance of the composition.

1st Commendation - E483
Christer Jonsson & Rolf Wiehagen
SuperProblem, 07-09-2017
white Pg5g2c6b4 Rc4 Bg6d2 Kd1 black Qf5 Ph7f7e6e5d7d5d3 Rf2d4 Bb6 Ke4
h#2see text(8+12)
2nd Commendation - E448a
Vitaly Medintsev (ded. to G. Chumakov)
SuperProblem, 18-04-2017
white Pb4 Kc2 Be4 Sa7 Rd3 black Sf4 Ba8 Kc4
h#2b) Ba8->h1(5+3)
3rd Commendation - E469
Gennady Ignatenko
SuperProblem, 13-06-2017
white Qb1 Kf5 Rb7 black Kc4 Ph4e4a4h5e5a5 Rh2h7 Bh1h8 Sc2c7

1st Commendation - E483 Christer Jonsson (Sweeden) and Rolf Wiehagen (Germany)8/3p1p1p/1bP1p1B1/3ppqP1/1PRrk3/3p4/3B1rP1/3K4

a) 1.Qf5*g6 Rc4*d4 + 2.Ke4-f5 g2-g4 # {,} b) wPg2-->e2 {Pg2->e2} 1.Rd4*c4 Bg6*f5 + 2.Ke4-d4 e2-e3 # {,
  } c) bPe5-->g3 {Pe5->g3} 1.d7*c6 {(A)} Rc4*c6 2.f7-f6 {(B)} Rc6*e6 # {,} d) bPd5-->g3 {Pd5->g3} 1.f7-f6 {(B)} Bg6-e8 2.d7*c6 {(A)} Be8*c6 #

HOTF with four linear solutions in twin form. Mutual captures in a) and b); inversion of the black moves, mates in the same square in c) and d).

2nd Commendation - E448a Vitaly Medintsev (Russia) dedicated to Gennady Chumakovb7/N7/8/8/1Pk1Bn2/3R4/2K5/8

a) 1.Ba8-d5 Sa7-c6 2.Sf4*d3 Be4*d3 # {,} b) bBa8-->h1 1.Sf4-d5 Rd3-e3 2.Bh1*e4 + Re3*e4 #

A Zilahi is part of a complete cycle of 4 captures, with ideal mates.

3rd Commendation - E469 Gennady Ignatenko (Russia)7b/1Rn4r/8/p3pK1p/p1k1p2p/8/2n4r/1Q5b

1.Rh2-g2 Kf5*e4 2.Bh8-g7 Rb7*c7 # {,} 1.Rh7-g7 Kf5*e5 2.Bh1-g2 Qb1*c2 #

Double Grimshaw with pure interferences. The first one to allow the wK move, the second to loss the guard on the mate line. To note the mirror mates, that are quite rare.

4th Commendation - E534a
Igor Agapov
SuperProblem, 14-11-2017
white Pe4h4h3 Kc5 Bb8 Rf4g3 black Be3c8 Kh2 Qh5 Pf2d4 Sg5 Rf3g4
h#2see text(7+9)
5th Commendation - E496
Menachem Witztum
SuperProblem, 06-10-2017
white Pd3e2 Sh4g7 Bf8 Kh8 black Be5c8 Kf4 Qa8 Pc5g3 Sg4g8 Rh3d8
6th Commendation - E406
Menachem Witztum
SuperProblem, 07-01-2017
white Sc7a6 Pb5a2c2 Kh5 Rf3 Bf5 black Qe8 Pf7f6a4a3b6 Kc4 Rd4

4th Commendation - E534a Igor Agapov (Russia)1Bb5/8/8/2K3nq/3pPRrP/4brRP/5p1k/8

a) {diagram} 1.Kh2*g3 Kc5-d6 2.Kg3*f4 Kd6-d5 # {,
   } b) bRf3<-->wRf4 wRg3<-->bRg4 {BRs<->WRs} 1.Rg3-g1 Rf3*e3 2.Rg1-h1 Bb8*f4 # {,
   } c) wRg3<-->bRg4 {Rg3<->Rg4} 1.Rg3*h3 Rg4*g5 2.Rh3*h4 Rf4*h4 # {,
   } d) bRf3<-->wRf4 {Rf3<->Rf4} 1.Rf4*f3 Rg3-g2 + 2.Kh2*h3 Rg2-h2 #

It may be strange that a problem without strategic unity enters the ranking, but here the unusual twin mechanism catches our attention.

5th Commendation - E496 Menachem Witztum (Israel)q1br1BnK/6N1/8/2p1b3/5knN/3P2pr/4P3/8

1.Rd8-d5 {(S8h6?)} Bf8-e7 2.Sg8-h6 Sh4-g2 # {,} 1.Rd8-d7 {(S8f6?)} Bf8*c5 2.Sg8-f6 Sg7-e6 #

Anticipatory direct unpin combined with interference to precise B1. Following indirect unpin.

6th Commendation - E406 Menachem Witztum (Israel)4q3/2N2p2/Np3p2/1P3B1K/p1kr4/p4R2/P1P5/8

1.Qe8-e4 {(Qe2?)} Rf3-f2 2.Qe4*c2 Rf2*c2 # {,} 1.Qe8-c6 {(Qe5?)} Bf5-d7 2.Qc6*b5 + Bd7*b5 #

The bQ has two choices to reach its arrival square in two moves, but one fails for white pin. The play is slightly unbalanced, since in one solution the bQ could reach b5 in one move, but also in this case it would pin the wB. So the bQ must move before, through the critical square d7.

7th Commendation - E567
Fadil Abdurahmanović
SuperProblem, 18-12-2017
white Sf3d5 Be4f6 Kg2 black Bg5 Kg4 Qf4 Pe3e5 Sd4 Rf5

7th Commendation - E567 Fadil Abdurahmanović (Bosnia and Herzegovina)8/8/5B2/3Nprb1/3nBqk1/4pN2/6K1/8

1.Sd4*f3 Sd5*f4 2.Bg5*f4 Be4*f3 # {,} 1.Bg5*f6 Be4*f5 + 2.Sd4*f5 Sd5*f6 #

The idea is partly present in other problems, such as Friedrich Hariuc, feenschach 2008 (see P1098986), but I must recognize that here the black and white interplay is very well performed.

International Judge: Francesco Simoni (Italy)Международный судья: Франческо Симони (Италия)
January 13, 201813 января 2018

Section H#2.5 & 3 | Задачи на коопмат в 2.5 и 3 хода

Within this section, there were 51 entries (including 3 versions) to be judged: E4067, E411, E418, E423, E426, E434, E442, E443, E446, E447, E462, E463, E464 (E464a), E467, E468 (E468a), E471, E473, E474, E475, E479, E484 (E484a), E487, E488, E489, E493, E495, E500, E501, E502, E503, E504, E505, E512, E513, E518, E519, E527, E531, E537, E540, E541, E545, E547, E549, E550, E558, E561, E564

Award is the following.

1st Prize - E423
Vasyl Kryzhanivskyi
SuperProblem, 04-02-2017
white Pd5f2c3 Bd6 Rf5 Kg8 black Bh5h8 Ke4 Qe7 Ph2f6c4e3 Sg3g4 Rh3
2nd Prize - E407
Vitaly Medintsev & Anatoly Skripnik
SuperProblem, 09-01-2017
white Kh1 Pd4c2d2 Rc5 Bf4 Sb7h5 black Ba8g1 Kc1 Qh7 Pe6a4f5d7 Sc8g6 Rf7d1
h#3b) Rd1->b1(8+12)
3rd Prize - E468a
V. Gurov, B. Shorokhov, V. Medintsev
SuperProblem, 04-06-2017
white Rf8 Sf2d7 Bh3 Kd1 Pb2g2 black Bb8f1 Kc4 Qf5 Pb5 Se8e5 Rc2
h#2.52 solutions(7+8)

1st Prize - E423 Vasyl Kryzhanivskyi (Ukraine)6Kb/4q3/3B1p2/3P1R1b/2p1k1n1/2P1p1nr/5P1p/8

1.Sg4*f2 Bd6-f4 {(A)} 2.Ke4-f3 Bf4-h6 + 3.Kf3-g4 Rf5-f4 # {(B),} 1.Qe7*d6 Rf5-f4 + {(B)} 2.Ke4-e5 Rf4-d4 3.Sg3-f5 f2-f4 # {(C),} 1.Ke4*f5 f2-f4 {(C)} 2.Kf5-g6 f4-f5 + 3.Kg6-h6 Bd6-f4 # {(A)}

Wonderful cyclic Zilahi theme with double role of square f4.

2nd Prize - E407 Vitaly Medintsev and Anatoly Skripnik (both Russia)b1s5/1S1p1r1q/4p1s1/2R2p1S/p2P1B2/8/2PP4/2kr2bK

a) 1.d7-d5 Bf4-h6 2.Rf7*b7 Sh5-f4 3.Rb7-b1 Sf4-d3 # {,} b) bRd1-->b1 1.Sg6-h4 Rc5-c6 2.Qh7*h5 Sb7-c5 3.Qh5-d1 Sc5-d3 #

Harmonious presentation of complex strategy.

3rd Prize - E468a Valery Gurov, Boris Shorokhov, Vitaly Medintsev (all three Russia)1b2nR2/3N4/8/1p2nq2/2k5/7B/1Pr2NP1/3K1b2

1...Sd7-c5 2.Qf5*f8 Sc5-b3 3.Qf8-b4 Bh3-e6 # {,} 1...Sf2-d3 2.Qf5*h3 Sd3-b4 3.Qh3-b3 Rf8-f4 #

Excellent Zilahi

4th Prize - E540
Boris Shorokhov
SuperProblem, 14-11-2017
white Pd6h6 Kb5 Rf6 black Bh7 Kf4 Qf5 Pd7e7g7d5h5 Sd8 Re8
1st Honorable Mention - E558 (v)
Nikola Stolev
SuperProblem, 14-02-2018
white Pb4d2 Sf2 Bh6 Kh2 black Be5 Kd5 Qb2 Pf6f4e4 Se6d3 Rc6
h#3b) -Pb4(5+9)
2nd Honorable Mention - E463
Gennady Ignatenko & Yuri Bilokin
SuperProblem, 05-06-2017
white Rd4 Ba8d8 Ka1 black Rc5 Se7h4 Bh8g2 Kf3 Pe4g4d3c2

4th Prize - E540 Boris Shorokhov (Russia)3nr3/3pp1pb/3P1R1P/1K1p1q1p/5k2/8/8/8

1.Kf4-e5 h6*g7 2.Qf5-e6 g7-g8=Q 3.Ke5*d6 Qg8-g3 # {,} 1.Kf4-g5 d6*e7 2.Qf5-g6 e7*d8=S 3.Kg5*h6 Sd8-f7 #

Model pin-pates with change of pin-line. Good connectionn between Zilahi and Chumakov themes.

1st Honorable Mention - E558 (version) Nikola Stolev (Macedonia)8/8/2r1np1B/3kb3/1P2pp2/3n4/1q1P1N1K/8

a) 1.Be5-d4 Bh6*f4 2.Sd3-e5 d2-d3 3.Se5-c4 d3*e4 # {,} b) -wPb4 1.Qb2-d4 Bh6-f8 2.Sd3-b2 Sf2-d3 3.Sb2-c4 Sd3-b4 #

An interesting play onto square d3 with Umnov effect.

2nd Honorable Mention - E463 Gennady Ignatenko (Russia) and Yuri Bilokin (Ukraine)B2B3b/4n3/8/2r5/3Rp1pn/3p1k2/2p3b1/K7

1.c2-c1=S {(Re5?)} Bd8-c7 2.Sc1-e2 Bc7-g3 3.Rc5-e5 {(Rc3?)} Rd4*d3 # {,} 1.Kf3-e3 {(Rc3?)} Bd8-a5 2.Sh4-f3 Ba5-e1 3.Rc5-c3 {(Re5?)} Rd4*e4 #

A well-determinated choice of indirect unpinning.

3rd Honorable Mention - E458
Jorge Kapros
SuperProblem, 14-05-2017
white Ra1 Kh1 Bb1 Se4 Pb4 black Ph2h3c3b3b5e6e7a7 Sg4 Rg5 Kf5 Bf6a8
4th Honorable Mention - E475
Fadil Abdurahmanović
SuperProblem, 08-07-2017
white Ph2e2h3 Ka6 Re1 Sg7 black Pf3c3g5c5 Kf4 Bd1 Rh7
h#2.52 solutions(6+7)
Commendation - E434
Aleksey Oganesjan & Vitaly Medintsev
SuperProblem, 15-03-2017
white Pf4 Ka4 Sd3 black Qb2 Pc6c7f7h7a6 Ra8b1 Bd7a1 Ke8
h#3b) Ra8->h8(3+11)

3rd Honorable Mention - E458 Jorge Kapros (Argentina)b7/p3p3/4pb2/1p3kr1/1P2N1n1/1pp4p/7p/RB5K

1.Bf6-e5 Ra1-a6 2.Be5-f4 Ra6-c6 3.e6-e5 Se4-g3 # {(Sd6?) ,} 1.Sg4-e5 Ra1-a2 2.Rg5-g4 Ra2-g2 3.Rg4-f4 Se4-d6 # {(Sg3?)}

Harmonious solutions with self-unpinning and anti-dualized mates, though double attack on BK is a little pity.

4th Honorable Mention - E475 Fadil Abdurahmanović (Bosnia and Herzegovina)8/6Nr/K7/2p3p1/5k2/2p2p1P/4P2P/3bR3

1...e2-e4 2.Rh7*h3 e4-e5 {!!} 3.Kf4-g4 Re1-e4 # {,} 1...e2*f3 {! (e4?)} 2.g5-g4 f3*g4 {!! (hxg4?)} 3.Bd1-f3 Sg7-e6 #

Mixed Bristol theme with WPe2 starring.

Commendations (without order)

Commendation - E434 Aleksey Oganesjan and Vitaly Medintsev (both Russia)r3k3/2pb1p1p/p1p5/8/K4P2/3N4/1q6/br6

a) 1.0-0-0 Sd3-e5 {(Sb4?)} 2.Qb2-b8 Se5-g6 {(Sxc6?)} 3.Rb1-b7 Sg6-e7 # {,} b) bRa8-->h8 1.0-0 Sd3-b4 {(Se5?)} 2.Qb2-h8 Sb4-d5 {(Sxc6?)} 3.Ba1-g7 Sd5-e7 #

Commendation - E505
Yuri Paramonov
SuperProblem, 14-10-2017
white Sd4 Rh8 Kd6 black Ke4 Sg5g7
Commendation - E527
M. Gershinsky & A.Pankratiev
SuperProblem, 31-10-2017
white Rf2 Kh1 Bd1 black Bg1 Kd5 Qc5 Pd6e6g4h4g3 Sd4h2 Rh3
h#3*set play + 2 solutions(3+11)
Commendation - E564
M. Gershinsky & A. Pankratiev
SuperProblem, 12-12-2017
white Pb2 Kd3 Rc1b1 Ba2 black Pb3d2c2h2f3h4h5 Kh7 Bh6

Commendation - E505 Yuri Paramonov (Russia)7R/6n1/3K4/6n1/3Nk3/8/8/8

1.Sg7-e6 Kd6-c6 2.Ke4-e5 Rh8-f8 3.Sg5-e4 Sd4-f3 # {,} 1.Sg7-h5 Sd4-c6 2.Sh5-f6 Rh8-h4 + 3.Ke4-f5 Sc6-e7 # {,} 1.Ke4-f4 Sd4-f3 2.Kf4-f5 Kd6-e7 3.Kf5-g6 Sf3-h4 #

Commendation - E527 Mikhail Gershinsky (Ukraine) and Alexander Pankratiev (Russia)8/8/3pp3/2qk4/3n2pp/6pr/5R1n/3B2bK

1...Bd1*g4 {(Re2?)} 2.Sd4-c6 Rf2-e2 3.Bg1-d4 Bg4*e6 # {,
 } 1.Sd4-c6 Rf2-b2 {(Be2?)} 2.Qc5-d4 Bd1-e2 3.Kd5-c5 Rb2-b5 # {,} 1.e6-e5 Bd1-a4 {(Rc2?)} 2.Sd4-e6 Rf2-c2 3.Qc5-d4 Ba4-c6 #

Commendation - E564 Mikhail Gershinsky (Ukraine) and Alexander Pankratiev (Russia)8/7k/7b/7p/7p/1p1K1p2/BPpp3p/1RR5

1.c2*b1=Q + Kd3-c4 2.Qb1*b2 Rc1-g1 3.Qb2-h8 Ba2-b1 # {,} 1.d2*c1=B Ba2*b3 2.Bc1*b2 Rb1-g1 3.Bb2-h8 Bb3-g8 #

Judge of the section: János Csák (Hungary)Судья раздела: Янош Кчак (Венгрия)
February 8, 20188 февраля 2018

Section H#3.5 - N | Задачи на коопмат в 3.5 - N ходов

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H # 2 | H # 2.5 & 3 | H # 3.5-N

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H # 2 - Francesco Simoni

H # 2.5 & 3 - János Csák

H # 3.5 - N - Zlatko Mihajloski

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Vitaly Medintsev

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