Award in SuperProblem - 2015 Informal Tourney | Fairies
Итоги годового конкурса SuperProblem - 2015 | Сказочные задачи
Published: July 07, 2016Опубликовано: 07 июля 2016
Firstly, I would like to thank SuperProblem editors for inviting me to judge the tourney. Internet allows publication of practically unlimited number of problems, but there are two complications while final competition is being shaped. Just as in the printed magazines, the submitted problems have to be edited and prepared for publication. And, sites have to build their reputation so that authors are willing to send there their good problems, not just something.
Fortunately, SuperProblem site now successfully manages both. Its editorial team is dedicated and the diagrams were published in the very pleasant form. Moreover, thanks to existing history of the site the authors are already sending very good fairies to the tourney knowing it is worth it.
As a result I had a chance to judge the tourney where prize-awarded problems will in no case disappoint. Thus my thanks from the first paragraph are not just formal – I am indeed happy to express them.
The award will be presented in my favourite order – from good to excellent. And before that I would like to dedicate a few lines to the problems that just did not make it to the list – they might have been at least commended under other circumstances.
G004 – Super-AUW, twins and mating pictures are quite chaotic.
G010 – Interesting for 3 units, but pity that there is no formal or strategic theme.
G021 – Sub-standard fare of K. Šoulivý, he can do better.
G029 – Much better rendering of the same scheme has got Special Honourable Mention in the jubilee tourney P. Gvozják 50 JT 2015.
G030 – The analogy is fine, but in each solution two neutral pieces including nQ are only used for blocking checkmating neutral piece, that is why I do not like the economy.
Finally, thanks to all authors participating in the tourney!
Предлагается следующее распределение отличий | Here is the proposal award
6th Commendation - G018 Daniel Novomesky SuperProblem, 01-12-2015 |
|
3k1b2/(q2)7/4PK2/8/8/8/8/5(q2)(q2)1 |
ser-h#10 | 2.1..
a7,f1,g1:Grasshopper(G) | (2+5) |
|
5th Commendation - G001 Dieter Müller & Franz Pachl SuperProblem, 15-01-2015 |
|
8/8/4P3/1N2k3/8/2N5/3b4/K1(q1)(Q1)4 |
h#2 | b) ALic1->b1
c1, d1: Andernach Lion | (5+3) |
|
4th Commendation - G003 Aleksandr Sygurov SuperProblem, 22-02-2015 |
|
8/8/8/5pP1/3K1NR1/6PP/1Q1PpBP1/3k4 |
Ser-h=3 | 4 solutions | (10+3) |
|
6th Commendation - G018 Daniel Novomesky (Slovakia)
1.Gf7 2.Gg7 3.Gg8 4.Ge8 5.Bd6 6.Ge7 7.Gd7 8.Gc5 9.Bc7 10.Gc8 e7#
1.Ge1 2.Gd1 3.Ge7 4.Gf7 5.Kc7 6.Gb7 7.Gd7 8.Kd8 9.Ke8 10.Gd8 e6xf7#
Two ideal mates in a very clean rendenring.
5th Commendation - G001 Dieter Müller & Franz Pachl (Germany)
a) 1.ALic8(Sc3=b) ALid4(Bd2=w) 2.ALif5(Pe6=b) ALib2(Sc3=w)# b) 1.ALib6(Sb5=b) ALid5(Bd2=w) 2.ALif6(Pe6=b) ALia5(Sb5=w)#
All moves are specific to Andernach lions, we see changes of colours: 2x2 knights, 2x pawn, 2x bishop, in a specific ODT.
4th Commendation - G003 Aleksandr Sygurov (Russia)
1.e1Q 2.Qe7 3.Qxg5 Rxg5 =
1.e1S 2.Sxg2 3.Sh4 Rxh4 =
1.e1R 2.Re3 3.Rxg3 Rxg3 =
1.e1B 2.Bxd2 3.Bxf4 Rxf4 =
Although the strategy is very simple and the means used are well known, the result is original: blend of black AUW with a cross of wR.
3rd Commendation - G022 Kostěj Šoulivý SuperProblem, 01-12-2015 |
|
2(!N)5/8/3(!R)3(N1)/8/8/3k4/8/8 |
h#2 | 4.1.. Super Circe & Patrol Chess
h6: Empress (EM)
| (1+1+2) |
|
2nd Commendation - G033 Igor Kochulov SuperProblem, 20-12-2015 |
|
3R1(q1)2/3RK2(q1)/3R4/5P(q1)1/8/2k3PP/8/8 |
h#2 | 3.1..
f8, g5, h7: Locust (L) | (7+4) |
|
1st Commendation - G013 Victor Zheglov SuperProblem, 30-09-2015 |
|
8/(k3)(!r1)6/8/(K3)7/p7/P7/6(!q1)1/8 |
hs#42.5 | b7: Rook Locust a5, a7: Poseidon g2: Locust | (2+2+2) |
|
3rd Commendation - G022 Kostěj Šoulivý (Czech Republic)
1.Ke2 EMxd6(nRc4) 2.nSxd6(EMd2) nSxc4(nRd1)#
1.nRxh6(EMc4) nRb6 2.Kd4 nSxb6(nRc3)#
1.Ke4 nSb6 2.nSc4 EMxd6(nRf6)#
1.nRd4 nSd6 2.Kxd4(nRf3) EMf5#
2+2 specific checkmates, this is about a standard of K. Šoulivý.
2nd Commendation - G033 Igor Kochulov (Russia)
1.Lxh3-h2 Rb7 2.Lxf5-f4 Rc6#
1.Lxg3-g2 Rb8 2.Lxh3-h2 Rc7#
1.Lxf5-f4 Rb6 2.Lxg3-g2 Rc8#
Cycles of black moves in h#2 are somewhat less common that cycles of white moves. The one here is based on well known strategy of unpinning white pieces, of which the first released actively guards and the second checkmates. The point is in two other elements: avoiding the alternative black 2nd moves (here managed by additional activity of moved locust) and economy, which is very good.
1st Commendation - G013 Victor Zheglov (Russia)
1...POa7-b8 2.POa5-a6 POb8-c8 3.POa6-a7 POc8-d8 4.POa7-b8 POd8-e8 5.POb8-c8 POe8-f8 6.POc8-d8 POf8-g8 7.POd8-e8 POg8-h7 8.POe8-f8 POh7-h6 9.POf8-g8 POh6-h5 10.POg8-h7 POh5-h4 11.POh7-h6 POh4-h3 12.POh6-h5 POh3-h2 13.POh5-h4 POh2-g1 14.POh4-h3 POg1-f1 15.POh3-h2 POf1-e1 16.POh2-g1 POe1-d1 17.POg1-f1 POd1-c1 18.POf1-e1 POc1-b1 19.POe1-d1 POb1-a1 20.POd1-c1 POa1-a2 21.POc1-b1 POa2-a1 + 22.POb1-a2 POa1-b1 23.POa2-a1 + POb1-c1 24.POa1-a2 POc1-d1 25.POa2-b1 POd1-e1 26.POb1-c1 POe1-f1 27.POc1-d1 POf1-g1 28.POd1-e1 POg1-h2 29.POe1-f1 POh2-h3 30.POf1-g1 POh3-h4 31.POg1-h2 POh4-h5 32.POh2-h3 POh5-h6 33.POh3-h4 POh6-h7 34.POh4-h5 POh7-g8 35.POh5-h6 POg8-f8 36.POh6-h7 POf8-e8 37.POh7-g8 POe8-d8 38.POg8-f8 POd8-c8 39.POf8-e8 POc8-b8 40.POe8-d8 POb8-a7 41.POd8-c8 POa7-a6 42.POc8-b8 POa6-a5 43.POb8-a7 nLg2xb7-a8#
More I look at this problem, more I like it. With relatively simple means the author managed to show exchange of two "kings" in a very long problem. The problem reminded me of a few problems with similarly limited movement possibilities, of which I would perhaps cite yacpdb/409595. Also, G013 has elegant determination of SW-corner manoeuvre.
5th Honorable Mention - G023 Vlaicu Crisan & Eric Huber SuperProblem, 01-12-2015 |
|
2nn4/3KP1(b1)1/8/1(r1)3(R3)2/3(B3)k1B1/3R3(q3)/8/3(q3)4 |
hs#3.5 | b) Pe7->c6
d1, h3: Leo (LE) f5: Pao (PA) d4: Vao (VA) b5: Chameleon Pao (cPA) g7: Chameleon Vao (cVA) | (6+7) |
|
4th Honorable Mention - G012 Miodrag Mladenović SuperProblem, 24-07-2015 |
|
5n2/P7/1P1k1PP1/2N1ppp1/1Q2p3/2P3pb/3Pp1Pb/4K1nr |
r#3vvv | | (10+12) |
|
3rd Honorable Mention - G014 Yury Gorbatenko SuperProblem, 10-10-2015 |
|
4R2b/B2pN3/1NP2rq1/4Pp2/1pBKP3/3nP3/Pp2k3/3r4 |
r#2 | | (11+10) |
|
5th Honorable Mention - G023 Vlaicu Crisan & Eric Huber (Romania)
a) diagram: 1...Sd6 2.VAg1 LEh7 3.PAf2 cPAe5=cVA 4.Rd4+ cVAxd4=cPA#
b) Pe7->c6: 1...Se6 2.PAf1 LEa4 3.VAf2 cVAe5=cPA 4.Bf5+ cPAxf5=cVA#
In a way perfect ODT with reciprocal exchange of functions of 5 pairs of pieces. But the specific Chameleon feels a bit schematic and there are pieces used only as hurdles by each side (those arriving on f2 and d5).
4th Honorable Mention - G012 Miodrag Mladenović (Serbia)
1.Qb5? (A) – 2.Qxe2 Sf3#, 1...Se6! (a) 2.Sb7#
1.Qc4? (B) – 2.Qxe2 Sf3#, 1...Sd7! (b) 2.Sb7#
1.Sxe4+? ~ 2.Sxg3 Bxg3#, 1...Ke6! 2.Qd6#
1.g7! – 2.Sxe4+ ~ 3.Sxg3 Bxg3#
1...Se6 (a) 2.Qc4 (B) – 3.Qxe2 Sf3#
1...Sd7 2.Qb5 (A) – 3.Qxe2 Sf3#
1...Kc6 2.Qc4 – 3.Qxe2 Sf3#
1...Kd5 2.Qb5 – 3.Qxe2 Sf3#
(2...Sf3+ 3.Kxe2 Re1#)
The first of a few orthodox r# in the award, with theme of 143rd TT SuperProblem, where Black is expected to defend against short tries by forcing White to checkmate and in the solution the tries become variations after Black defending against threat by preparing reflex mate for White. It sounds complicated and indeed it is necessary to use nontrivial motivation for complex to work. Here in two variations.
3rd Honorable Mention - G014 Yury Gorbatenko (Russia)
1.e6! - 2.exd7 Rd6#
1...dxc6 2.Sed5! c5#, 1...dxe6 2.Kbd5! e5#, 1...d6 2.Bd5! Se5#, 1...d5 2.exd5! Rf8#
1...Rf8+/Rxе6+ 2.Kd5! Qxе6#/Rd6#
This orthodox r#2 does not fit into framework described in the comment to the 4th HM. But it has strong theme as well: black Pickaninny is blended with 5 different White pieces entering d5 (one of them obviously in the supplementary variation).
2nd Honorable Mention - G034 Victor Zheglov SuperProblem, 20-12-2015 |
|
8/8/5b2/1BBK4/6b1/5k2/8/8 |
hs#5.5 | 6.1.. NewKoeKo | (3+3) |
|
1st Honorable Mention - G015 Marcel Tribowski SuperProblem, 02-11-2015 |
|
3R4/2p1PPp1/2B1K1p1/4b1P1/2P2PN1/2pb3R/N1rkp1p1/q3nQ2 |
r#3 | | (12+12) |
|
3rd Prize - G007 L.Salai jr., E.Klemanič, M.Dragoun SuperProblem, 21-03-2015 |
|
(e1)4b2/2(R3)1p(E1)pP/(e1)5Kp/(Q3)6P/k7/pp2pp1n/(b3)3(e1)3/3(e1)B(r3)1(E1) |
s#2 | c7, f1: Pao a2: Vao, a5: Leo d1, f7, a8, a6, e2, h1: Equihoppers | (8+16) |
|
2nd Honorable Mention - G034 Victor Zheglov (Russia)
1...Kf3-g3 2.Kd5-e5 Bg4-f3 3.Ke5-f5 Kg3-g2 4.Kf5-g4 Bf6-e7 5.Kg4-h3+ Kg2-h2 6.Bc5-d6+ Be7-h4#
1...Kf3-f4 2.Kd5-d4 Bg4-e6+ 3.Bc5-d6 Be6-d5 4.Bb5-f1 Bf6-d8 5.Bf1-g2 Bd8-b6 6.Kd4-e3+ Bd5-b7#
1...Kf3-e4+ 2.Bc5-b4 Bg4-d1 3.Bb5-d3+ Ke4-f5 4.Bb4-f8 Bf6-d4 5.Bf8-g7 Bd1-b3 6.Kd5-e6+ Bd4-b2#
1...Bf6-c3 2.Bb5-d3 Kf3-e2 3.Kd5-e4 Bg4-d7 4.Bc5-g1 Bc3-d4 5.Bd3-c4 Bd7-c6 6.Ke4-f3+ Bd4-b6#
1...Bf6-d8 2.Bb5-c6 Bg4-c8 3.Bc5-d6 Bd8-e7 4.Bd6-g3 Kf3-e4+ 5.Kd5-e6 + Be7-d6 6.Ke6-f5+ Bd6-b8#
1...Bf6-e7 2.Bc5-f2 Kf3-e4 3.Kd5-c4 Bg4-c8 4.Bb5-d7 Be7-c5 5.Bd7-c6 Bc8-a6 6.Kc4-d3+ Bc5-a7#
NeuKöko is a condition complicated enough to prevent human solving and mostly even composing. Yet, I would like to award highly this silicon product as 6 solutions in long helpselfmates are extremely rare sight, there is 5-fold echo of the critical position and even the odd solution shows the same checkmating manoeuvre (bB running away from White to parry check in the NeuKöko manner). If the sixth solution was non-existent or also with echo, this would be high prize.
1st Honorable Mention - G015 Marcel Tribowski (Germany)
1.Sxe5? (A) - 2.Bd5 (C) Bf5#, 1...Sf3! 2.Rxd3#
1.fxe5? (B) - 2.Bd7 (D) Bxc4#, 1...Qd1! 2.Qf4#
1.Rhh8! - 2.Rhe8 ~ 3.Kd7 Bf5#, 2...Bd4(Bf6) 3.Bd5 (C) Bf5# / 3.Bd7 (D) Bxc4#
1...Qd1 2.Qxe2+ Kxe2 3.Sxe5 (A) Bf5# / 3.fxe5 (B) Bf5#, 2...Qxe2 3.Bd5 (C) Bf5# / 3.Bd7 (D) Bxc4# (2.Rhe8? Bxf4! 3.Qxf4#)
1...Kd1 2.Sxe5 (A) ~ 3.Bd5 C Bf5# (2.Rhe8? Rd2! 3.Se3#)
1...g1Q 2.fxe5 (B) ~ 3.Bd7 (D) Bxc4#, 2...Qxg4+ 3.Kd5 Qxc4#, 2...Qb6 3.Rd~8 Qxc6#
r#3 that does not entirely conform to the requirements of 143rd TT SuperProblem as in the solution defence 1...g1Q is not a reflex one, it rather threats check 2...Qxg4+ on the second move. But the emphasis is besides reflex play put on the interesting motivation (unpinning, line opening, variety of checkmates) and some algebraic relationship of moves.
3rd Prize - G007 Ladislav Salai jr. (Slovakia), Emil Klemanič (Slovakia) and Michal Dragoun (Czech Republic)
1.PAa7! - 2.LEc7+ EQe8#
1...EQf5 2.LEc5+ EQe4#, 1...EQe4 2.LEb4+ EQc2#
1...Sg5 2.LEd5+ EQg4#, 1...e5 2.LEb5+ EQc4#, 1...e6 2.LEb6+ EQc6#
Perfect analogy of five variations: in the threat black mates over immobilized EQf7. Thus the defence against threat lies in the provision of the new hurdle for EQf7. But White exploits this by using newly placed piece as hurdle for checkmate by EQa6 and in the precise battery checks in W2 White provides another hurdle for mating move. Excellent use of EQ properties, even if the position is slightly heavy.
2nd Prize - G008 Lev Grolman SuperProblem, 01-06-2015 |
|
8/6(!b)r/1q6/8/1bp1(!k)3/6p1/3(!q)1(!r)2/8 |
h#2 | 3.1.. AntiCirce Circe Parrain
| (0+5+4) |
|
1st Prize - G017 Miodrag Mladenovic SuperProblem, 02-11-2015 |
|
br1b4/2n1B2R/1pp1kn2/3pNp2/p2P1P2/7R/P2pP1pr/K2B2N1 |
r#3vvv | | (11+14) |
|
|
2nd Prize - G008 Lev Grolman (Russia)
1.Qd8 nRf3 2.Rxg7(Rh8) nKe3(nBg6)#
1.Rh8 nBh6 2.Bxd2(Bf8) nKf4(nQe2)#
1.Bf8 nQd6 2.Qxf2(Qd8) Kd4(nRe2)#
By chance it is already known that G008 entered FIDE Album thanks to results of WCCI 2013-2015. In my opinion, it is quite deserved as the analogy and depth of the play is very good, not speaking about extremely light position for the thematic complex shown. Black pieces enter their rebirth squares, in B1 by simple move, in B2 by capturing their neutral colleagues in the cyclic manner: BxnQ, QxnR, RxnB. White in W1 prepares mating nets by moving the same neutral piece as is moving in B2. And the mating moves do a lot: neutral kings enters squares double attacked by neutral pieces standing on the board, with the third one appearing from Parrain limbo to guard what is necessary. White doublecheck by neutrals the nK, but it is not a selfcheck thanks to occupied black rebirth squares. Elegant blend of Anticirce and neutrals with Circe Parrain spicing the content by just adequate amount of exotic taste.
1st Prize - G017 Miodrag Mladenovic (Serbia)
1.Ba3? - 2.Bc1 dxc1Q#, 1...Be7! 2.Re7#
1.Rc3? - 2.Rc1 dxc1Q#, 1...Rb7! 2.Rc6#
1.Sd3? - 2.Sc1 dxc1Q#, 1...b5! 2.Sc5#
1.e4! - 2.Se2 ~ 3.Sc1 dxc1Q#
1...Sh5 2.Ba3 ~ 3.Bc1 dxc1Q# (2.Se2? Sf4 3.Sxf4#)
1...c5 2.Rc3 ~ 3.Rc1 dxc1Q# (2.Se2? cxd4 3.Sxd4#)
1...Sb5 2.Sd3 ~ 3.Sc1 dxc1Q# (2.Se2? Sxd4 3.Sxd4#)
To my surprise, G017 was not evaluated so highly in WCCI. Maybe it is caused by single well-known black reflex mate 1...dxc1Q, maybe by the repetition of white reflex mate 3.Sxd4# in two defences against threat in the solution. But in my opinion, G017 is the best problem of the competition as it shows in fairly acceptable position with just orthodox means difficult theme of the 143rd TT SuperProblem in 3 tries and variations. The play bears mark of the excellent composing technique, with varied exploitation of orthodox motivation available. I sincerely hope that FIDE Album judges would decide to include the problem.
Judge of the section: Juraj Lörinc (Slovakia)Судья раздела: Юрай Лёринч (Словакия)
COMMENTS (real-time mode) | КОММЕНТАРИИ посетителей
close XIn the form below, you are able to submit comment to this article. If your comment is about a mistake/anticipation/version of a problem, please, use an appropriate category (click the button "Category" and select a relevant one)
Enter your comment and click the black button "Add comment" - you will be prompted to log in via one of several popular social networks; to do this click on the appropriate icon. If you want to remain anonymous, enter a nickname, email address and click "Send" - your message will immediately appear in the widget (new comments appear at the bottom). To reply to someone comment click the "Reply" link below the corresponding comment.
If you want to attach an image (e.g. chess diagram) to your comment click on the icon  (in the lower right corner of the input field) and select a needed graphic file on your computer.
You can subscribe to comments of this widget by clicking the icon  and enter your e-mail. Visitors who use rss-aggregators can subscribe to rss-feed for this widget by clicking on the icon 
закрыть XВ форме ниже вы можете оставить комментарий к данной статье. Если ваше сообщение касается замечания об ошибке, сообщения о предшественнике или предложения версии задачи, пожалуйста, используйте соответствующую категорию (кнопка "Категории" ниже поля ввода комментария справа).
После ввода текста сообщения нажмите черную кнопку "Комментировать". Вам будет предложено авторизоваться через одну из нескольких популярных социальных сетей; для этого щелкните по иконке соответствующей соцсети. Если вы хотите остаться анонимом, введите произвольный никнейм, адрес электронной почты и нажмите "Отправить" - ваше сообщение сразу появится в виджете комментариев (новые комментарии выводятся внизу). Для ответа на чей-либо комментарий щелкните ссылку "Ответить" ниже соответствующего комментария.
Чтобы прикрепить к тексту комментария картинку (например, диаграмму), нажмите на иконку  (в нижнем правом углу поля ввода) и выберите нужный графический файл на вашем компьютере.
Чтобы подписаться на комментарии щелкните иконку  и введите адрес вашей электронной почты. Посетители, использующие rss-агрегаторы, могут подписаться на rss-фид данного виджета, щелкнув по иконке 
comments powered by HyperComments
|